在 laravel 5.2 中使用工厂关系违反完整性约束
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【中文标题】在 laravel 5.2 中使用工厂关系违反完整性约束【英文标题】:Integrity constraint violation using factory relationships in laravel 5.2 【发布时间】:2016-07-18 08:41:51 【问题描述】:我是 laravel 测试的新手,我正在尝试使用模型工厂创建虚拟数据。 我有三张桌子:
公司 客户 简介一家公司有很多客户,一个客户有很多简报。
clients
和 briefs
的格式非常相似。他们都有外键firm_id
和client_id
。
在进行 phpunit 测试时,我想使用以下代码创建来自公司的客户实例和来自客户的简报实例:
$client = $firm->clients()
->save(factory(App\SearchFirmClient::class)->create());
$brief = $client->briefs()
->save(factory(App\SearchFirmBrief::class)->create());
$client
的创建毫不费力,但 $brief
抛出错误:
Illuminate\Database\QueryException: SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'client_id' cannot be null (SQL: insert into `search_firms_briefs` (`user_id`, `title`, `description`, `contact_id`, `client_id`, `updated_at`, `created_at`) values (1, Et in amet., Quo soluta ut impedit nesciunt autem. Laborum aperiam est non molestiae animi non quod. Explicabo eligendi doloribus ex quia vitae placeat ut., 0, , 2016-03-30 10:06:34, 2016-03-30 10:06:34))
两个表格的格式:
Schema::create('search_firms_clients', function(Blueprint $table)
$table->increments('client_id');
$table->integer('search_firm_id')->unsigned();
$table->foreign('search_firm_id')->references('id')->on('search_firms')->onDelete('cascade');
$table->string('name');
$table->softDeletes();
$table->timestamps();
);
Schema::create('search_firms_briefs', function(Blueprint $table)
$table->increments('brief_id');
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('client_id')->on('search_firms_clients')->onDelete('cascade');
$table->string('title');
$table->softDeletes();
$table->timestamps();
);
每个模型工厂:
$factory->define(App\SearchFirmClient::class, function ($faker)
return [
'name' => $faker->company,
'email' => $faker->companyEmail,
'phone' => $faker->phoneNumber,
'address' => $faker->address,
'website' => $faker->url,
];
);
$factory->define(App\SearchFirmBrief::class, function ($faker)
return [
'user_id' => 1,
'title' => $faker->sentence(3),
'description' => $faker->text(),
'contact_id' => 0,
];
);
关系:
class SearchFirm extends Model
protected $table = 'search_firms';
protected $primaryKey = 'id';
public function clients()
return $this->hasMany('SearchFirmClient', 'search_firm_id');
class SearchFirmClient extends Model
use SoftDeletes;
protected $table = 'search_firms_clients';
protected $primaryKey = 'client_id';
protected $dates = [ 'deleted_at' ];
public function briefs()
return $this->hasMany('SearchFirmBrief', 'client_id')->orderBy( 'updated_at', 'desc');
class SearchFirmBrief extends Model
use SoftDeletes;
protected $table = 'search_firms_briefs';
protected $primaryKey = 'brief_id';
protected $touches = array('client');
protected $dates = [ 'deleted_at'];
public function client()
return $this->belongsTo('SearchFirmClient', 'client_id');
【问题讨论】:
【参考方案1】:问题 #1
briefs
表上没有 id
列,但您在 clients
表上引用它。
把外键改成brief_id
:
Schema::create('search_firms_clients', function(Blueprint $table)
$table->increments('client_id');
$table->integer('search_firm_id')->unsigned();
$table->foreign('search_firm_id')
->references('brief_id') // <-- Change this
->on('search_firms')
->onDelete('cascade');
$table->string('name');
$table->softDeletes();
$table->timestamps();
);
Schema::create('search_firms_briefs', function(Blueprint $table)
$table->increments('brief_id');
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('client_id')->on('search_firms_clients')->onDelete('cascade');
$table->string('title');
$table->softDeletes();
$table->timestamps();
);
问题 #2
您没有user_id
成员。
$factory->define(App\SearchFirmBrief::class, function ($faker)
return [
'client_id' => 1, // <-- change this
'title' => $faker->sentence(3),
'description' => $faker->text(),
'contact_id' => 0,
];
);
结论
最好遵循 Laravel 的命名标准,以后会省去很多麻烦(即使用默认表名,主键名)
【讨论】:
search_firms_clients
表引用了主键为'id'
的search_firm
表。 clients
模型创建完成,没问题。问题在于 briefs
模型引用了新创建的 clients
模型。
尝试运行artisan migrate:refresh
或手动删除数据库并重新迁移以上是关于在 laravel 5.2 中使用工厂关系违反完整性约束的主要内容,如果未能解决你的问题,请参考以下文章
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