Laravel 以 json 格式显示/返回数据，而不是以 html 格式显示/返回数据

Posted 2023-03-14

【中文标题】Laravel 以 json 格式显示/返回数据，而不是以 html 格式显示/返回数据

【英文标题】：Laravel Displaying/returning data in json format instead of displaying/returning data in html format

【发布时间】：2019-08-11 16:33:54

【问题描述】：

我有一种奇怪的情况，数据以 json 格式而不是 html 格式显示！ 在路由http://127.0.0.1:8000/addpost 显示添加帖子的表单和最近添加的帖子。

它显示要添加帖子的表单，当点击提交时，它会以 json 格式返回数据，而不是显示表单和添加的帖子。 1）为什么它返回 json 数据？ 2）如何以html格式显示数据？ 这就是我的路线

web.php
Route::get('addpost','PostController@index');
Route::post('addpost','PostController@store');

控制器->

PostController.php 
class PostController extends Controller

     public function index()
    
        $posts = Post::latest()->first();
        return view('addpost',compact('posts'));

    

    public function store(Request $request)
    
        $post =new Post();
        $post->title=   $request->input('title');
        $post->body=    $request->input('body');

        if($request->hasfile('postimage'))
        
            $file=$request->file('postimage');
            $extention=$file->getClientOriginalExtension();
            $filename=time().'.'.$extention;
            $file->move('uploads/post',$filename);
            $post->postimage=$filename;
        
        else
            return $request;
            $post->postimage='';
        

        $post->save();
        return back()->with('success', 'Your images has been successfully Upload'); 
    

   

和视图

<div class="container">
        <div class="jumbotron">
            @if(Auth::user())
            <h3> Add new post with images</h3>
            <form action="url('addpost')" method="POST" enctype="multipart/form-data">
                csrf_field()
            <div class="form-group">
                <label>Title</label>
                <input type="text" name="title" class="form-control" >
            </div>
            <div class="form-group">
                <label>Body</label>
                <input type="text" name="body" class="form-control" >
            </div>
            <div class="input-group">
                <div class="custom-file">
                    <input type="file" name="image" class="custom-file-input">
                    <label class="custom-file-label">Choose file</label>

                </div>
            </div>
            <button type="submit" name="submit" class="btn-brn-primary"> Save Post</button>
            @if($posts)
            @foreach($posts as $post)
             <tr>
                        <td>$post->id</td>
                        <td>$post->title</td>
                        <td>$post->body</td>
                        <!-- <td><img src="asset('uploads/post/'.$post->image)" style="height: 150px;"></td>
                        <td><a href="">EDIT</a></td> -->
                    </tr>
            @endforeach
            @endif
            @else
            <h1>no</h1> 
            @endif 
        </form>
        </div>  
    </div>

【参考方案1】：

if($request->hasfile('postimage')) // -> you are checking for postimage, in your html 
                                   // markup the file filed is called "image", 
                                   // therefore you will never enter this if block
        
            $file=$request->file('postimage');
            $extention=$file->getClientOriginalExtension();
            $filename=time().'.'.$extention;
            $file->move('uploads/post',$filename);
            $post->postimage=$filename;
        
        else
            return $request; // here you are returning the $request object that 
                             // causes your unformatted response
            $post->postimage='';