NSPredicate (nsdictionary+array+nsdictionary)

Posted 2023-03-11

【中文标题】NSPredicate (nsdictionary+array+nsdictionary)

【英文标题】：NSPredicate ( nsdictionary+array+nsdictionary)

【发布时间】：2016-08-09 04:54:27

【问题描述】：

我尝试过 NSPredicate，但总是得到响应 0。 检查打击代码并提供您的建议哪里出错了。 源数组：-

CityId = 0;
TreatmentProgramServices =     (
            
        TreatmentServicesId = 9;
        TreatmentServicesName = Coed;
    ,
            
        TreatmentServicesId = 1;
        TreatmentServicesName = Intervention;
    ,
            
        TreatmentServicesId = 3;
        TreatmentServicesName = Residential;
    
);
TreatmentProgrameId = 3;

---

filterTreatmentServices 是数组计数是：- 3

 NSPredicate* updatePre =  [NSPredicate predicateWithFormat:@"(%K IN %@)",@"TreatmentProgramServices.TreatmentServicesId" ,filterTreatmentServices];

 filterTreatmentService =[soureceArray filteredArrayUsingPredicate:updatePre];

请提出解决方案

【问题讨论】：

NSPredicate* updatePre = [NSPredicate predicateWithFormat:@"TreatmentProgramServices.TreatmentServicesId == %@",@"3"]];

@balkaransingh 它不起作用，因为 TreatmentProgramServices.TreatmentServicesId TreatmentProgramServices 中的问题是其 dic 之后的数组。

请检查答案。

【参考方案1】：

请用这个

  NSArray *filterArray=[soureceArray filteredArrayUsingPredicate:[NSPredicate predicateWithBlock:^BOOL(id  _Nonnull evaluatedObject, NSDictionary<NSString *,id> * _Nullable bindings) 
                return [[evaluatedObject valueForKey:TreatmentServicesId]  == 3];
            ]];