iOS 应用程序的 Firebase 3.7.0 上的链接错误
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【中文标题】iOS 应用程序的 Firebase 3.7.0 上的链接错误【英文标题】：Linking error on Firebase 3.7.0 for iOS Application 【发布时间】：2016-11-09 14:13:21 【问题描述】：我正在尝试在我的 ios 应用程序中使用 Firebase SDK 3.7.0，但它给出了链接错误。
我已按照 README.md 中描述的步骤进行操作，该文件包含在从 https://firebase.google.com/docs/ios/setup 下载的框架 SDK 中，关于没有 CocoaPods 部分的集成。
在链接时，出现以下错误：
Undefined symbols for architecture armv7:
"_sqlite3_bind_double", referenced from:
___48-[FIRASqliteStore bindValues:toStatement:error:]_block_invoke in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_bind_null", referenced from:
___48-[FIRASqliteStore bindValues:toStatement:error:]_block_invoke in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_column_type", referenced from:
-[FIRASqliteStore valueAtColumn:forStatement:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_column_double", referenced from:
-[FIRASqliteStore valueAtColumn:forStatement:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_open_v2", referenced from:
-[FIRASqliteStore openAndValidateDatabase:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_clear_bindings", referenced from:
-[FIRASqliteStore cleanUpStatement:forQuery:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
-[FIRASqliteStore bindValues:toStatement:error:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_column_count", referenced from:
-[FIRASqliteStore recordsForQuery:parameterValues:error:withFilter:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
-[FIRASqliteStore validateDatabaseWithError:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_OBJC_CLASS_$_s-s-readingList", referenced from:
objc-class-ref in GoogleSignIn(please_link_SafariServices.framework_.o)
"_OBJC_CLASS_$_MFMessageComposeViewController", referenced from:
objc-class-ref in FirebaseInvites(GINInviteController_af66380ba390cf14b066932397806d20.o)
objc-class-ref in FirebaseInvites(GPPACLSearchViewController_3fc71921176f5b855c444ab9ce9260c7.o)
objc-class-ref in FirebaseInvites(GINInviteScrollView_5b90efc8e1a69f9dfe581b021e7f869b.o)
"_OBJC_CLASS_$_CMMotionManager", referenced from:
objc-class-ref in FirebaseDynamicLinks(GPPSpamSignal_a0a54565a3243ede865cc9b2724bc7a8.o)
"_sqlite3_column_bytes", referenced from:
-[FIRMessagingRmq2PersistentStore scanOutgoingRmqMessagesWithHandler:] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
-[FIRASqliteStore valueAtColumn:forStatement:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_reset", referenced from:
-[FIRASqliteStore cleanUpStatement:forQuery:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_changes", referenced from:
-[FIRMessagingRmq2PersistentStore deleteMessagesFromTable:withRmqIds:] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
-[FIRMessagingRmq2PersistentStore deleteExpiredOrFinishedSyncMessages:] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
-[FIRASqliteStore deleteRecordsFromTableWithName:condition:parameterValues:error:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
"_sqlite3_errmsg", referenced from:
-[FIRMessagingRmq2PersistentStore saveMessageWithRmqId:tag:data:error:] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
-[FIRMessagingRmq2PersistentStore lastErrorMessage] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
XCode 版本是 7.0.1
【问题讨论】：
【参考方案1】：你需要添加这个框架，因为你不使用 Pod
libicucore.tbd
CFNetwork.framework
安全性框架
SystemConfiguration.framework
libc++.tbd
libsqlite3.tbd
对于 2020 年，如果您仍然遇到以下令人发指的错误：
_OBJC_CLASS_$_SKPaymentQueue _OBJC_CLASS__$_SKProductsRequest
然后，另外添加 StoreKit
【讨论】：
【参考方案2】：不确定为什么必须添加所有这些框架，即使您不使用 pod。我把它整理出来，只添加了 libsqlite3.dylb 和 libs.1.dylib
【讨论】：
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