3d 触摸快速动作调用 UIButton

Posted 2023-03-10

【中文标题】3d 触摸快速动作调用 UIButton

【英文标题】：3d touch quick action call UIButton

【发布时间】：2016-12-22 12:54:58

【问题描述】：

我在初始 VC 上创建了一个有 4 个 UIButtons 的应用程序。 每个按钮都连接到另一个 VC（在所有情况下都相同），但参数不同。

 @IBAction func googleBtnPressed(_ sender: AnyObject) 
    searchEngine = "Google"
    print(searchEngine)
    performSegue(withIdentifier: "google", sender: nil)



@IBAction func bingBtnPressed(_ sender: AnyObject) 
    searchEngine = "Bing"
    print(searchEngine)
    performSegue(withIdentifier: "google", sender: nil)



@IBAction func ddgBtnPressed(_ sender: AnyObject) 
    searchEngine = "DuckDuckGo"
    print(searchEngine)
    performSegue(withIdentifier: "google", sender: nil)



@IBAction func customBtnPressed(_ sender: AnyObject) 
    performSegue(withIdentifier: "custom", sender: nil)



if let vc = segue.destination as? ViewController 
            if searchEngine == "Google" 
                    vc.url = NSURL(string: "https://www.google.com")
                    vc.segueUsed = "google"
                    vc.searchEngine = "google"
            

            else if searchEngine == "Bing" 
                    vc.url = NSURL(string: "https://www.bing.com")
                    vc.segueUsed = "google"
                    vc.searchEngine = "bing"
            

            else if searchEngine == "DuckDuckGo" 
                    vc.url = NSURL(string: "https://www.duckduckgo.com")
                    vc.segueUsed = "google"
                    vc.searchEngine = "duckduckgo"
            
        

    else if segue.identifier == "custom"
        print(segue.identifier!)
        if let vc = segue.destination as? ViewController 
            vc.segueUsed = "custom"
        
    

我想使用 3d Touch 的快速操作从主屏幕调用这 4 个按钮。 我已经在 info.plist 文件中创建了条目，但是在处理 AppDelegate.swift

中的响应时遇到了困难

<key>UIApplicationShortcutItems</key>
<array>
    <dict>
        <key>UIApplicationShortcutItemType</key>
        <string>$(PRODUCT_BUNDLE_IDENTIFIER).Google</string>
        <key>UIApplicationShortcutItemTitle</key>
        <string>Google</string>
        <key>UIApplicationShortcutItemIconType</key>
        <string>google</string>
    </dict>
</array>

我该如何实现？

感谢您的帮助。

【参考方案1】：

let yourViewcontroller = self.window?.rootViewController// This view controller should be action view controller
        let itemKey = shortcutItem.userInfo["<YOUR KEY>"]
        if itemKey == "Google" 
            //call google action method
         else if itemKey == "Bing" 
            //call Bing action method
         else if itemKey == "Ddg" 
            //call "Ddg" action method
        else if itemKey == "CustomButton" 
            //call CustomButton action method
        

注意：您可以将 itemKey 保存在 ShortCutItemDictionary 中。

【讨论】：

能否详细说明如何从 appDelegate 调用操作方法。