如何在 Spring Boot 中解决“提取类型 [class com.*] 的响应时出错”？

Posted 2023-02-27

【中文标题】如何在 Spring Boot 中解决“提取类型 [class com.*] 的响应时出错”？

【英文标题】：How to solve "Error while extracting response for type [class com.*" in Spring Boot?

【发布时间】：2020-05-02 08:28:40

【问题描述】：

您可能想跳到下面的我的更新 2

我有一个可以工作的 RestController，因为当我直接从浏览器访问它时，它会返回一个 JSON 响应。但是，当我在不同的有界上下文中从服务发送请求时，我收到错误：

"timestamp":1579095291446,"message":"Error while extracting response for type 
[class com.path.to.contexttwo.client.dto.WorkerDetails] and content type [application/json]; nested exception is 
org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: 
Unexpected character ('<' (code 60)): expected a valid value (JSON String, Number, Array, Object or token 'null', 'true' or 'false');
nested exception is com.fasterxml.jackson.core.JsonParseException: 
Unexpected character ('<' (code 60)): 
expected a valid value (JSON String, Number, Array, Object or token 'null', 'true' or 'false')\n at [Source: (PushbackInputStream); 
line: 1, column: 2]","details":"uri=/context-two/register-new"

这是我的代码：

RestController

package com.path.to.contextone.aplication.presentation;

@RestController
@RequestMapping(path = "/iacess", produces = "application/json")
@CrossOrigin(origins = "*")
public class IAccessRestController 

    UserRepository userRepo;
    IAcessService iaccessService;
    EntityLinks entityLinks;

    @Autowired
    public IAccessRestController(
            UserRepository userRepo,
            IAcessService iaccessService,
            EntityLinks entityLinks) 
        this.userRepo = userRepo;
        this.iaccessService= iaccessService;
        this.entityLinks = entityLinks;
    

    @GetMapping("/get-worker-details/userName")
    public WorkerDetails getWorkerDetails(@PathVariable String userName) 

        User user = userRepo.findByUsername(userName);

        WorkerDetails workerDetails = new WorkerDetails();
        workerDetails.setUserId(userId);
        workerDetails.setGender(user.gender());
        workerDetails.setFirstName(user.getFirstName());
        workerDetails.setLastName(user.getLastName());
        workerDetails.setPhoneNumber(user.getPhoneNumber());

        if (workerDetails != null) 
            return workerDetails;
        
        return null;
    

RestClient

package com.path.to.contexttwo.client;

// imports omitted, as well as other code

@Service
public class IAcessRestClientImpl implements IAcessRestClient 

    private final RestTemplate restTemplate;

    @Autowired
    public IAcessRestClientImpl(
            final RestTemplate restTemplate
    ) 
        this.restTemplate = restTemplate;
    

    @Override
    public WorkerDetails getWorkerDetailsByName(final String userName) throws URISyntaxException 

        Map<String,String> urlVariables = new HashMap<>();
        urlVariables.put("userName", userName);
        return restTemplate.getForObject(
                "http://localhost:8080/iacess/get-worker-details/userName",
                WorkerDetails.class,
                urlVariables
        );
    

配置

package com.path.to.contexttwo.configuration;

@Configuration
@EnableWebMvc
public class RestClientConfig 

    @Bean
    public RestTemplate restTemplate() 
        final RestTemplate restTemplate = new RestTemplate();

        List<HttpMessageConverter<?>> messageConverters = new ArrayList<>();
        MappingJackson2HttpMessageConverter converter = new MappingJackson2HttpMessageConverter();
        List<MediaType> mediaTypes = new ArrayList<MediaType>();
        mediaTypes.add(MediaType.APPLICATION_JSON);
        converter.setSupportedMediaTypes(mediaTypes);
        messageConverters.add(converter);
        restTemplate.setMessageConverters(messageConverters);
        restTemplate.getInterceptors().add(new JsonInterceptor());

        return restTemplate;
    

工人详情

package com.path.to.contexttwo.client.dto;

import java.io.Serializable;
import java.util.Objects;

public class WorkerDetails implements Serializable 

    private long userId;
    private String gender;
    private String firstName;
    private String lastName;
    private String phoneNumber;

    public WorkerDetails() 
        this.userId = -1;
        this.gender = null;
        this.firstName = null;
        this.lastName = null;
        this.phoneNumber = null;
    

    // omitted all args constructor, getters, setters, equals, hascode, toString for simplicity

WorkerDetails 也存在于包 com.path.to.contextone.ohs_pl 中；

我已经尝试了3天，阅读和调试，无济于事。调试器似乎显示当 RestTemplate 分析 WorkerDetails.class 时发生错误。

我也尝试在所有配置类中使用 ComponentScan，因为文件位于单独的包（有界上下文）中，但没有成功。

我可以只使用调用 IAcessRestClient 的类中的 UserDetailsRepository 来获取 WorkerDetails，但这会使两个不同的有界上下文依赖于同一个数据库架构。

任何帮助将不胜感激。 我可以根据请求发布附加代码。

提前致谢

更新 @SB 要求输入参数。这是发送参数的类：

CompanyServiceImpl

package com.path.to.contexttwo.domain.services;

// imports

@Service
public class CompanyServiceImpl implements CompanyService 

    private CompanyRepository companyRepository;
    private CompanyWorkerRepositoery companyWorkerRepositoery;
    private WorkerDetailsClient workerDetailsClient;
    private WebApplicationContext applicationContext;

    @Autowired
    CompanyServiceImpl (
            CompanyRepository companyRepository,
            CompanyWorkerRepositoery companyWorkerRepositoery,
            WorkerDetailsClient workerDetailsClient,
            WebApplicationContext applicationContext
    ) 
        this.companyRepository = companyRepository;
        this.companyWorkerRepositoery = companyWorkerRepositoery;
        this.workerDetailsClient = workerDetailsClient;
        this.applicationContext = applicationContext;
    

    @Transactional
    public Company criateCompany(CompanyDTO dto) throws URISyntaxException  

        if (dto.getLegalyAuthorized() == true && dto.getTerms() == true) 
            Company company = new Company(
                    dto.getCompanyName(),
                    dto.getStateId()
            );
            company = CompanyRepository.save(company);

            // when saving the company, we also need some details from the current logged in user which can be 
            // retrieved from the idendity and access bounded context. We need those details to be saved in this context            

            Authentication auth = SecurityContextHolder.getContext().getAuthentication();
            String name = auth.getName();

            WorkerDetails workerDetails = WorkerDetailsClient.getWorkerDetailsByName(
                    name
            );

            // ... we can't reach the rest of the code anyway, so we omitted            
    

这是我直接访问 RestController 时得到的响应：

"userId":127,"gender":"M","firstName":"Primeiro","lastName":"Último","phoneNumber":"922222222"

更新 2

注释掉 .anyRequest().authenticated() 并且一切运行正常！因此，它一直与 Spring Security 有关。多可惜。现在将尝试在启用安全性的情况下使事情正常进行。由于重定向到登录页面，我收到了 html 作为响应。正确实施了身份验证（带有基本身份验证的令牌请求）并且一切正常。

谢谢大家！

【问题讨论】：

您是否尝试将 username 替换为用户名的实际值：“localhost:8080/iacess/get-worker-detailsuserName”？

请分享您的输入参数和预期响应（当您从浏览器运行请求时有效。

@JavaBoy，是的，我尝试使用硬编码的 URI，但得到了同样的错误。其实调试的时候，url是正确的。

@SB，请查看我对问题的更新。谢谢！

根据错误，似乎有一些 HTML 代码是响应的一部分。您能否检查响应数据中的特殊字符？

【参考方案1】：

试试：

return restTemplate.getForObject(
   "http://localhost:8080/iacess/get-worker-details/" + userName,
   WorkerDetails.class);

【讨论】：

谢谢，JavaBoy！这实际上是我的第一次尝试。我很高兴按照书中的示例更改为当前形式。现在将恢复。