Hibernate 和 Spring Data JPA 无法处理带有特殊字符的 Oracle 表名？

Posted 2023-02-26

【中文标题】Hibernate 和 Spring Data JPA 无法处理带有特殊字符的 Oracle 表名？

【英文标题】：Hibernate and Spring DataJPA can not handle Oracle table name with special character?

【发布时间】：2017-02-01 04:54:24

【问题描述】：

我在使用Spring datajpa和Hibenate读取Oracle的时候遇到了一个错误，我会这样描述：

Oracle 表名包含特殊字符（双引号），所以我必须使用SELECT * FROM "Graph" WHERE "ID"=1。

所以，我在使用hibernate写实体类的时候，必须指出它的特殊名称。

这里是用来创建"Graph"表的ddl：

CREATE TABLE "ATLASCOPCO_TOOLSNET"."Graph" (
"ID" NUMBER(19) NOT NULL ,
"ResultID" NUMBER(19) NOT NULL ,
"GraphTypeID" NUMBER(19) NOT NULL ,
"SampleTime" BINARY_FLOAT NOT NULL ,
"AngleOffset" BINARY_FLOAT NOT NULL ,
"GraphValues" BLOB NOT NULL ,
"AngleFactor" BINARY_DOUBLE NULL ,
"TorqueFactor" BINARY_DOUBLE NULL ,
"StartTime" BINARY_FLOAT NULL ,
"EndTime" BINARY_FLOAT NULL 
)
LOGGING
NOCOMPRESS
NOCACHE

当我像这样使用普通表名时：

@Entity
@Table(name = "Graph")
@Getter
@Setter
public class Graph 
    @Id
    @Column(name = "ID\"")
    private Long id;

    @Column(name = "ResultID")
    private Long resultId;

    @Column(name = "GraphTypeID")
    private Long graphTypeID;

    @Column(name = "SampleTime")
    private BINARY_FLOAT sampleTime;

    @Column(name = "AngleOffset")
    private BINARY_FLOAT angleOffset;

    @Column(name = "GraphValue")
    private byte[] graphValue;

    @Column(name = "AngleFactor")
    private BINARY_DOUBLE angleFactor;

    @Column(name = "TorqueFactor")
    private BINARY_DOUBLE torqueFactor;

    @Column(name = "StartTime")
    private BINARY_FLOAT startTime;

    @Column(name = "EndTime")
    private BINARY_FLOAT endTime;

我收到错误：Caused by: java.sql.SQLSyntaxErrorException: ORA-00972: identifier is too long

当我使用这个时：

@Entity
@Table(name = "\"Graph\"")
@Getter
@Setter
public class Graph 
    @Id
    @Column(name = "\"ID\"\"")
    private Long id;

    @Column(name = "\"ResultID\"")
    private Long resultId;

    @Column(name = "\"GraphTypeID\"")
    private Long graphTypeID;

    @Column(name = "\"SampleTime\"")
    private BINARY_FLOAT sampleTime;

    @Column(name = "\"AngleOffset\"")
    private BINARY_FLOAT angleOffset;

    @Column(name = "\"GraphValue\"")
    private byte[] graphValue;

    @Column(name = "\"AngleFactor\"")
    private BINARY_DOUBLE angleFactor;

    @Column(name = "\"TorqueFactor\"")
    private BINARY_DOUBLE torqueFactor;

    @Column(name = "\"StartTime\"")
    private BINARY_FLOAT startTime;

    @Column(name = "\"EndTime\"")
    private BINARY_FLOAT endTime;

我收到了Caused by: java.sql.SQLSyntaxErrorException: ORA-00911: invalid character

【问题讨论】：

您的查询等于SELECT * FROM Graph WHERE ID=1

见***.com/a/13568581

【参考方案1】：

删除列名中的特殊字符\"，这是导致问题的原因。 JPA 和 Oracle 驱动程序都会正确处理。

您可以省略"，ANSI SQL 也可以。

CREATE TABLE NEW_TABLE (ID NUMBER(19) NOT NULL , NAME VARCHAR2(19) NOT NULL);

【参考方案2】：

假设您在一个名为 "id" 的表中有一个列，如下所示：

然后要使用特殊字符（"），您需要添加如下转义序列：

    @Column(name="`\"id\"`")
    private int id;

结果将是一个名称为 ("id") 的列。 请找到以下更新的 Graph POJO 类：

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table (name="`\"Graph\"`")
@Getter
@Setter
public class Graph 
@Id
@Column (name="`\"ID\"`")
private Long id;

@Column (name="`\"ResultID\"`")
private Long resultId;

@Column(name="`\"GraphTypeID\"`")
private Long graphTypeID;

@Column (name="`\"SampleTime\"`")
private BINARY_FLOAT sampleTime; 

@Column (name="`\"AngleOffset\"`")
private BINARY_FLOAT angleOffset;

@Column (name="`\"GraphValue\"`")
private byte[] graphValue;

@Column (name="`\"AngleFactor\"`")
private BINARY_DOUBLE angleFactor;

@Column (name="`\"TorqueFactor\"`")
private BINARY_DOUBLE torqueFactor;

@Column (name="`\"StartTime\"`")
private BINARY_FLOAT startTime;

@Column (name="`\"EndTime\"`")
private BINARY_FLOAT endTime;

---

要从图表中检索数据，请在 Hibernate 中使用以下代码：

Query query=session.createSQLQuery("SELECT * FROM `\" Graph \"` WHERE `\"ID\"`=1 ");

希望对你有所帮助。