插入触发器后创建视图

Posted 2023-02-26

【中文标题】插入触发器后创建视图

【英文标题】：Create view after insert trigger

【发布时间】：2015-08-05 05:15:59

【问题描述】：

我有两张表 company (id,company_name) 和 users (id,company_id,user_name)；

现在我想在公司表中插入数据时创建一个视图。

我使用了以下两种方法，但在这两种情况下都出现了相同的错误。错误是：

#1422 - Explicit or implicit commit is not allowed in stored function or trigger. 

第一个查询是：

DELIMITER $$
CREATE TRIGGER testInsert 
    AFTER INSERT ON companies
    FOR EACH ROW BEGIN

   CREATE VIEW test(user_name) AS 
    SELECT user_name
    FROM users;
END$$
DELIMITER ;

然后我尝试先创建过程并像这样在触发器中调用该过程

create procedure createView() 
 create view vt as select * from users; 


 CREATE TRIGGER `testInsert3` AFTER INSERT ON `companies`
FOR EACH ROW
BEGIN
   CALL createView();
END;

请帮帮我。

谢谢大家。

【参考方案1】：

    please refer this link, i think this will help you

    http://***.com/questions/16256250/create-view-in-a-trigger


try creating the view like this 


DELIMITER $$
CREATE TRIGGER testInsert 
    AFTER INSERT ON companies
    FOR EACH ROW BEGIN

   EXECUTE('CREATE VIEW test(user_name) AS SELECT user_name
    FROM users')
END$$
DELIMITER ;