Hibernate Criteria:在 Subquery/DetachedCriteria 中执行 JOIN
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【中文标题】Hibernate Criteria:在 Subquery/DetachedCriteria 中执行 JOIN【英文标题】:Hibernate Criteria: Perform JOIN in Subquery/DetachedCriteria 【发布时间】:2011-02-05 20:18:27 【问题描述】:我在使用 DetachedCriteria 将 JOIN 添加到子查询时遇到了问题。代码大致如下:
Criteria criteria = createCacheableCriteria(ProductLine.class, "productLine");
criteria.add(Expression.eq("productLine.active", "Y"));
DetachedCriteria subCriteria = DetachedCriteria.forClass(Model.class, "model");
subCriteria.setProjection(Projections.rowCount());
subCriteria.createAlias("model.modelLanguages", "modelLang");
subCriteria.createAlias("modelLang.language", "lang");
criteria.add(Expression.eq("lang.langCode", "EN"));
subCriteria.add(Restrictions.eqProperty("model.productLine.productLineId","productLine.productLineId"));
criteria.add(Subqueries.lt(0, subCriteria));
但记录的 SQL 不包含子查询中的 JOIN,但确实包含引发错误的别名
SELECT *
FROM PRODUCT_LINE this_
WHERE this_.ACTIVE=?
AND ? <
(SELECT COUNT(*) AS y0_
FROM MODEL this0__
WHERE lang3_.LANG_CODE ='EN'
AND this0__.PRODUCT_LINE_ID =this_.ID
)
如何将联接添加到 DetachedCriteria?
@Entity
@Table(name = "PRODUCT_LINE")
public class ProductLine implements java.io.Serializable
private long productLineId;
private char active;
private Set<Models> models = new HashSet<Models>(0);
@OneToMany(fetch = FetchType.LAZY, mappedBy = "productLine")
public Set<Models> getModels()
return this.models;
@Entity
@Table(name = "MODEL")
public class Model implements java.io.Serializable
private long modelId;
private ProductLine productLine;
private String name;
private Set<ModelLanguages> modelLanguages = new HashSet<ModelLanguages>(0);
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "PRODUCT_LINE_ID")
public ProductLine getProductLine()
return this.productLine;
@Column(name = "NAME", nullable = false)
public String getName()
return this.name;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "model")
public Set<ModelLanguages> getModelLanguages()
return this.modelLanguages;
@Entity
@Table(name = "MODEL_LANGUAGES")
public class ModelLanguages implements java.io.Serializable
private long id;
private Language language;
private Model model;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "LANGUAGE_ID", nullable = false, insertable = false, updatable = false)
public Language getLanguage()
return this.language;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "MODEL_ID", nullable = false, insertable = false, updatable = false)
public Model getModel()
return this.model;
@Entity
@Table(name = "LANGUAGES", uniqueConstraints = @UniqueConstraint(columnNames = "LANG_CODE"))
public class Language implements java.io.Serializable
private long languageId;
private String langCode;
private Set<ModelLanguages> modelLanguages = new HashSet<ModelLanguages>(
0);
@Column(name = "LANG_CODE", unique = true, nullable = false)
public String getLangCode()
return this.langCode;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "language")
public Set<ModelLanguages> getModelLanguages()
return this.modelLanguages;
Hibernate version: 3.2.6.ga
Hibernate core: 3.3.2.GA
Hibernate annotations: 3.4.0.GA
Hibernate commons-annotations: 3.3.0.ga
Hibernate entitymanager: 3.4.0.GA
Hibernate validator: 3.1.0.GA
【问题讨论】:
能把ProductLine
和Models
的定义和映射贴出来吗?
【参考方案1】:
您的代码在以下行中是否有错字:
criteria.add(Expression.eq("lang.langCode", "EN"));
我认为,您应该在子标准而不是标准上添加此限制。
【讨论】:
【参考方案2】:如果您需要在子查询中连接表,您可以尝试这样做。它在您的分离条件中明确指定 joinType。
subCriteria.createAlias("model.modelLanguages", "modelLang", CriteriaSpecification.LEFT_JOIN);
subCriteria.createAlias("modelLang.language", "lang", CriteriaSpecification.LEFT_JOIN);
【讨论】:
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