Xampp的登录php验证问题
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【中文标题】Xampp的登录php验证问题【英文标题】：Login php verification Problem with Xampp 【发布时间】：2019-11-06 19:35:01 【问题描述】：我正在尝试通过查询数据库表来验证使用 php 的网站登录。它在 login.php 中创建解析会话的错误。该网站全部托管在 XAMPP 上。这只是一个试用网站。这是我第一次用 PHP 编码，老实说才一周。
我尝试修改 $global 变量。是不是因为 xampp 在 MariaDB 而不是 sql 上运行，但这没有意义，因为这是 PHP 和 create_table
This is the login
<html form
<div class="loginbox">
<img src="images/log.png" class="log">
<h1> Login </h1>
<form action="login.php" method="post">
<div class="name">
<label for ="name"> Username/E-mail:</label>
<input type="text" id="name" name="username" placeholder="Enter
Username/E-mail">
</div>
<div class="password">
<label for="password"> Password:</label>
<input type="password" id="password" name="password"
placeholder="Enter Password">
</div>
<div>
<button type="submit" >Login</button>
</div>
</form>
</div>
And this is the table created for signup.
$persontable= "CREATE TABLE IF NOT EXISTS users.Person(
Userid INTEGER UNSIGNED AUTO_INCREMENT PRIMARY KEY,
Firstname VARCHAR(20) NOT NULL,
Lastname VARCHAR(20) NOT NULL,
Username VARCHAR(30) NOT NULL,
Email VARCHAR(30) NOT NULL,
Password VARCHAR(20) NOT NULL,
Dateofbirth DATE NOT NULL,
Address VARCHAR(50) NOT NULL,
City VARCHAR(50) NOT NULL,
Zipcode VARCHAR(20),)";
if (!(mysqli_query($handler,$persontable)))
die("Account has not been created successfully:".
mysqli_error($handler));
elseecho "Account has been created succesfully"
And this is the code of login<php
<?php
$servername = "127.0.0.1";
$username = "root";
$password = "";
/** Define variable to perform connection to the server*/
$handler = mysqli_connect($servername, $username, $password);
$errors = array();
session_start();
/** To perform authentication of login with the database*/
if(empty($_POST['username']))
$this->errors[] = "Username field was empty.";
elseif (empty($_POST['password']))
$this->errors[] = "Password field was empty.";
elseif(isset($_POST['username']) && isset($_POST['password']))
$user=$_POST['username'];
$pass=$_POST['password'];
$handler or die(mysqli_error());
mysqli_select_db($handler,'users') or die("Cannot select DB");
$query=mysqli_query($handler,"SELECT Username,Email,Password
FROM person WHERE username='".$user."' OR email='".$user."'");
$numrows = mysqli_num_rows($query);
/**The old code is stated below here
if ($result_of_login_check->num_rows == 1)
*/
/**The Problem Starts here*/
if ($numrows ==1)
if (password_verify($_POST['password'])
// write user data into PHP SESSION (a file on your
server)
/**The Problem Starts here*/
$_SESSION['user_name'] = $result_row->user_name;
$_SESSION['user_email'] = $result_row->user_email;
$_SESSION['user_login_status'] = 1;
else
$query->errors[] = "Wrong password or username. Try again.";
?>
【问题讨论】：
它可能停在password_verify，因为您使用错误，它应该吐出错误。如果不是，那么您需要确保错误检查和显示在您的 php 页面顶部添加：ini_set('display_errors', 'On'); ini_set('html_errors', 0); error_reporting(-1);
【参考方案1】：
<?php session_start(); ?> 在 login.php 顶部尝试此操作，并确保您在每个页面上都有启动会话
<?php session_start();?>
<?php
$servername = "127.0.0.1";
$username = "root";
$password = "";
/** Define variable to perform connection to the server*/
$handler = mysqli_connect($servername, $username, $password);
$errors = array();
/** To perform authentication of login with the database*/
if(empty($_POST['username']))
$this->errors[] = "Username field was empty.";
elseif (empty($_POST['password']))
$this->errors[] = "Password field was empty.";
elseif(isset($_POST['username']) && isset($_POST['password']))
$user=$_POST['username'];
$pass=$_POST['password'];
$handler or die(mysqli_error());
mysqli_select_db($handler,'users') or die("Cannot select DB");
$query=mysqli_query($handler,"SELECT Username,Email,Password
FROM person WHERE username='".$user."' OR email='".$user."'");
$numrows = mysqli_num_rows($query);
/**The old code is stated below here
if ($result_of_login_check->num_rows == 1)
*/
/**The Problem Starts here*/
if ($numrows ==1)
if (password_verify($_POST['password'])
// write user data into PHP SESSION (a file on your
server)
/**The Problem Starts here*/
$_SESSION['user_name'] = $result_row->user_name;
$_SESSION['user_email'] = $result_row->user_email;
$_SESSION['user_login_status'] = 1;
else
$query->errors[] = "Wrong password or username. Try again.";
?>
【讨论】：
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