类 '...\Entity\User' 没有方法 'getGenderList'

Posted 2023-02-16

【中文标题】类 \'...\\Entity\\User\' 没有方法 \'getGenderList\'

【英文标题】：Class '...\Entity\User' does not have a method 'getGenderList'类 '...\Entity\User' 没有方法 'getGenderList'

【发布时间】：2015-11-22 20:46:30

【问题描述】：

我正在使用Sonata Admin bundle 作为我网站的后端。

我的数据库中的用户表如下所示：

id (PK)
username
email
password
salt
last_login
created_at
company_id (FK)

我的用户实体如下所示：

<?php

namespace MyBundle\Entity;

use FOS\UserBundle\Entity\User as BaseUser;
//use Sonata\UserBundle\Entity\BaseUser as BaseUser;
use Doctrine\ORM\Mapping as ORM;

/**
 * User
 *
 * @ORM\Table(name="user", indexes=@ORM\Index(name="fk_user_company1_idx", columns="company_id"))
 * @ORM\Entity
 */
class User extends BaseUser

    /**
     * @var \DateTime
     *
     * @ORM\Column(name="created_at", type="datetime", nullable=true)
     */
    protected $createdAt;

    /**
     * @var integer
     *
     * @ORM\Column(name="id", type="integer")
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="IDENTITY")
     */
    protected $id;

    /**
     * @var \MyBundle\Entity\Company
     *
     * @ORM\ManyToOne(targetEntity="MyBundle\Entity\Company")
     * @ORM\JoinColumns(
     *   @ORM\JoinColumn(name="company_id", referencedColumnName="id")
     * )
     */
    protected $company;

    public function __construct()
    
        parent::__construct();
        // your own logic
    

    /**
     * Set username
     *
     * @param string $username
     * @return User
     */
    public function setUsername($username)
    
        $this->username = $username;

        return $this;
    

    /**
     * Get username
     *
     * @return string 
     */
    public function getUsername()
    
        return $this->username;
    

    /**
     * Set email
     *
     * @param string $email
     * @return User
     */
    public function setEmail($email)
    
        $this->email = $email;

        return $this;
    

    /**
     * Get email
     *
     * @return string 
     */
    public function getEmail()
    
        return $this->email;
    

    /**
     * Set password
     *
     * @param string $password
     * @return User
     */
    public function setPassword($password)
    
        $this->password = $password;

        return $this;
    

    /**
     * Get password
     *
     * @return string 
     */
    public function getPassword()
    
        return $this->password;
    

    /**
     * Set salt
     *
     * @param string $salt
     * @return User
     */
    public function setSalt($salt)
    
        $this->salt = $salt;

        return $this;
    

    /**
     * Get salt
     *
     * @return string 
     */
    public function getSalt()
    
        return $this->salt;
    

    /**
     * Get id
     *
     * @return integer 
     */
    public function getId()
    
        return $this->id;
    

    /**
     * Set company
     *
     * @param \MyBundle\Entity\Company $company
     * @return User
     */
    public function setCompany(\MyBundle\Entity\Company $company = null)
    
        $this->company = $company;

        return $this;
    

    /**
     * Get company
     *
     * @return \MyBundle\Entity\Company 
     */
    public function getCompany()
    
        return $this->company;
    

现在当我转到“编辑帐户”页面时，我收到以下错误：

Warning: call_user_func() expects parameter 1 to be a valid callback, class 'MyBundle\Entity\User' does not have a method 'getGenderList'

我的数据库中的用户表中没有性别。我该如何解决这个问题？

更新：

当我将use FOS\UserBundle\Entity\User as BaseUser; 更改为use Sonata\UserBundle\Entity\BaseUser as BaseUser;。然后我收到以下错误：

执行 'SELECT t0.username AS username1, t0.username_canonical AS username_canonical2, t0.email AS email3, t0.email_canonical AS email_canonical4, t0.enabled AS enabled5, t0.salt AS salt6, t0.password AS 时发生异常password7, t0.last_login AS last_login8, t0.locked AS locked9, t0.expired AS expired10, t0.expires_at AS expires_at11, t0.confirmation_token AS Confirm_token12, t0.password_requested_at AS password_requested_at13, t0.roles AS roles14, t0.credentials_expired AS credentials_expired t0.credentials_expire_at AS credentials_expire_at16, t0.created_at AS created_at17, t0.updated_at AS updated_at18, t0.date_of_birth AS date_of_birth19, t0.firstname AS firstname20, t0.lastname AS lastname21, t0.website AS website22, t0.biography AS biography23, t0.性别 AS gender24, t0.locale AS locale25, t0.timezone AS timezone26, t0.phone AS phone27, t0.facebook_uid AS facebook_uid28, t0.facebook_name AS facebook_name29, t0.facebook_data AS facebook_data30, t0.twitt er_uid AS twitter_uid31, t0.twitter_name AS twitter_name32, t0.twitter_data AS twitter_data33, t0.gplus_uid AS gplus_uid34, t0.gplus_name AS gplus_name35, t0.gplus_data AS gplus_data36, t0.token AS token37, t0.two_step_code AS two_step_code38, t0. id39, t0.company_id AS company_id40 FROM user t0 WHERE t0.id = ? LIMIT 1' 带参数1:

SQLSTATE[42S22]：找不到列：1054 未知列 't0.updated_at' 在“字段列表”中

我该如何解决这个问题？

【问题讨论】：

你必须在你的类中实现缺失的方法。这就是错误信息告诉你的全部内容。

遇到了同样的问题，在收到这个 sql 错误后，我不得不删除与此相关的表（fos_user、fos_group 和 fos_user_group）、所有迁移文件并重新创建它们。更改现有表不起作用。

【参考方案1】：

您的 User 类从 FOSUserBundle 扩展，而不是 SonataUserBundle。你必须改变它：

//use FOS\UserBundle\Entity\User as BaseUser;
use Sonata\UserBundle\Entity\BaseUser as BaseUser;

查看https://github.com/sonata-project/SonataUserBundle/issues/459

编辑：如果你不想使用这个类（里面有很多无用的字段），那么你必须为你的 User 实体创建自己的管理类。这个页面有一个完整的指南：http://m2mdas.github.io/blog/2013/11/18/integrate-fosuserbundle-and-sonatauserbundle-easily/

更新后更新： 更改实体扩展的类后，您必须更新数据库架构以匹配您的模型：

php app/console doctrine:schema:update --force

【讨论】：

我已经更新了我的主题，有没有办法在不编写自己的管理类的情况下绕过它？

我已经更新了我的答案。您要么必须扩展适当的类，要么编写自己的管理类。