Highcharts Mysql Json 数组 PHP

Posted 2023-02-24

【中文标题】Highcharts Mysql Json 数组 PHP

【英文标题】：Highcharts Mysql Json arrays PHP

【发布时间】：2018-03-23 01:45:00

【问题描述】：

我正在尝试为我的 highchart 散点图获取正确的 Json 输出，请参阅 example。

我想要的Json输出：

[
        "name": "Female",
        "color": "red",
        "data": [
            "name": "Anna",
            "x": 161.2,
            "y": 51.6
        , 
            "name": "Clair",
            "x": 167.5,
            "y": 59.0
        ]
    ,
    
        "name": "Male",
        "color": "blue",
        "data": [
            "name": "James",
            "x": 174.0,
            "y": 65.6
        ]
    ,
    
        "name": "Peet",
        "color": "black",
        "data": [
            "name": "Peet",
            "x": 175.3,
            "y": 71.8
        ]
    
]

数据.php

<?php

$arr    = array();
$arr1   = array();
$arr2   = array();
$result = array();

$sql = "SELECT `gender`, `name`, `length`, `weight`
            FROM `highcharts_data`
            WHERE `gender` = 'Female'";
$q   = mysqli_query($mysqli,$sql);

while($row = mysqli_fetch_assoc($q))
$arr['name'] = 'Female';
$arr['data'] = array([(float)$row['length'], (float)$row['weight']]);
$arr['color'] = 'red';

array_push($result,$arr);


$sql1 = "SELECT `gender`, `name`, `length`, `weight`
            FROM `highcharts_data`
            WHERE `gender` = 'Male' AND `name` != 'Peet'";
$q1  = mysqli_query($mysqli,$sql1);

while($row = mysqli_fetch_assoc($q1))
$arr1['name'] = 'Male';
$arr1['data'] = array([(float)$row['length'], (float)$row['weight']]);
$arr1['color'] = 'blue';

array_push($result,$arr1);


$sql2 = "SELECT `gender`, `name`, `length`, `weight`
            FROM `highcharts_data`
            WHERE `gender` = 'Male' AND `name` = 'Peet'";
$q2  = mysqli_query($mysqli,$sql2);

while($row = mysqli_fetch_assoc($q2))
$arr2['name'] = 'Peet';
$arr2['data'] = array([(float)$row['length'], (float)$row['weight']]);
$arr2['color'] = 'black';

array_push($result,$arr2);


print json_encode($result, JSON_NUMERIC_CHECK);
mysqli_close($mysqli);
?>

我得到的 JSON 输出：

[
    "name": "Female",
    "data": [
        [161.2, 51.6]
    ],
    "color": "red"
, 
    "name": "Female",
    "data": [
        [167.5, 59]
    ],
    "color": "red"
, 
    "name": "Male",
    "data": [
        [174, 65.6]
    ],
    "color": "blue"
, 
    "name": "Peet",
    "data": [
        [175.3, 71.8]
    ],
    "color": "black"
]

谁能告诉我如何更改 data.php 文件，以便我得到正确的 Json 输出！

谢谢！

【问题讨论】：

数据：[name: 'Anna',x: 161.2,y: 51.6，你在哪里得到这个名字？

【参考方案1】：

这是一个如何将 PHP 格式化为 JSON 的工作示例。这不包括 mysql 部分，但这应该不很难弄清楚。

2017 年 10 月 12 日更新，更正了双重数据的错误：

2017 年 10 月 16 日更新，更正了没有数组推送的错误：

<?php
$males   = array();
$malepersons = array();
$females = array();
$femalepersons = array();
$result  = array();

$values = [[
    "name" => 'Anna',
    "height" => 175,
    "weight" => 53.4,
    "gender" => 'Female'
    ],[
    "name" => 'Dan',
    "height" => 185.1,
    "weight" => 90.4,
    "gender" => 'Male'
    ] ];

//Simplified for loop
foreach ($values as $row)
    $person = array();
    $person['name'] = $row['name'];
    $person['x'] = $row['height'];
    $person['y'] = $row['weight'];

    if($row['gender'] == 'Male')
        array_push($malepersons, $person);        
     elseif($row['gender'] == 'Female') 
        array_push($femalepersons, $person);
    


//took these out of the for loop, only need to be set once
$males['color'] = 'black'; 
$males['name'] = 'Male';
$males['data'] = $malepersons;
$females['color'] = 'green';
$females['name'] = 'Female';
$females['data'] = $femalepersons;


array_push($result, $males);
array_push($result, $females);
print json_encode($result, JSON_NUMERIC_CHECK);
?>

这将为您提供如下所示的 JSON：

[
  "color": "black",
  "name": "Male",
  "data": [
    "name": "Dan",
    "x": 185.1,
    "y": 90.4
  ]
, 
  "color": "green",
  "name": "Female",
  "data": [
    "name": "Anna",
    "x": 175,
    "y": 53.4
  ]
]

highcharts 希望作为系列输入。

在您的情况下，$values 数组实际上是 SQL 返回的数据，您只需将循环更改为循环您想要循环的内容。

添加了工作示例：https://ideone.com/RPp3DO

键控数组上的 PHP DOCS：http://php.net/manual/en/language.types.array.php

【讨论】：

您好 Ewolden，感谢您的快速回复！这和我的想法很接近。在您的 Json 输出中，“数据”被提及两次。这在示例文件中不起作用。我是 php 和 Json 领域的绝对初学者。我已经开始使用以下 data.php 文件（下一篇文章），但这是我目前得到的输出：["color":"black","name":"Male","data":"name":"Peet","data":"x":175.3,"y":71.8,"color":"green","name":"Female","data":"name":"Clair","data":"x":167.5,"y":59].

Part1: <?php $result = array(); $sql = "SELECT gender, name, length, weight` FROM highcharts_data"; $q = mysqli_query($mysqli,$sql); while ($row = mysqli_fetch_assoc($q)) $person = array(); if($row['gender'] == 'Male') $person['name'] = $row['name']; $person['数据'] = ['x' => $row['length'], 'y' => $row['weight']]; $males['color'] = 'black'; $males['name' ] = '男性'; $males['data'] = $person; `

elseif($row['gender'] == 'Female') $person['name'] = $row['name']; $person['data'] = ['x' => $row['length'], 'y' => $row['weight']]; $females['color'] = '绿色'; $females['name'] = '女'; $females['data'] = $person; array_push($result, $males); array_push($result, $females);打印 json_encode($result, JSON_NUMERIC_CHECK); mysqli_close($mysqli); ?>

再次感谢！输出以正确的方式显示，但缺少部分。目前我有两个组，即女性和男性。我想念第三组“Peet”。我想让这个人与其他群体分开。你能在你的例子中添加这个吗？我还将添加一个新答案，其中包含我迄今为止所做的更改。

对不起，我错过了一部分。循环不起作用。我只得到一个人的数据，而我期望两个人的数据，就像我的例子一样。能不能也看看这部分。