将发布日期与codeigniter中的时间戳进行比较

Posted 2023-02-24

【中文标题】将发布日期与codeigniter中的时间戳进行比较

【英文标题】：Compare post date with timestamp in codeigniter

【发布时间】：2014-09-30 12:53:12

【问题描述】：

我有registered_customers_bod 函数，我想在两个日期之间得到结果。为此，我正在使用 to 和 from where 子句。但我面临一个问题，数据库中的记录包含一个时间戳，我发布的日期为 YYYY-MM-DD 格式。谁能帮我把这个时间戳记为 YYYY-MM-DD 格式或任何其他解决方案。

谢谢！！！！

 function registered_customers_bod()
        $this->db->select(array(
            'tbl_customer_registration.cus_name',
            'tbl_customer_registration.cus_email',
            'tbl_customer_registration.cus_phone',
            'tbl_customer_registration.cus_mobile',
            'tbl_customer_registration.cus_addr_no',
            'tbl_customer_registration.cus_addr_street',
            'tbl_customer_registration.cus_addr_city',
            'tbl_user_registration.user_status',
            'tbl_user_registration.user_reason_status',
            'tbl_user_registration.user_timestamp',
        ));
        $this->db->from('tbl_customer_registration');
        $this->db->join('tbl_user_registration', 'tbl_user_registration.user_id=tbl_customer_registration.user_id');
        $this->db->group_by("tbl_customer_registration.cus_id"); //view single record that contain two contact numbers
        $this->db->where('user_timestamp >=',$this->input->post('to'));
        $this->db->where('user_timestamp <=',$this->input->post('from'));
        $query = $this->db->get();
        return $query->result();
    

【参考方案1】：

下面会将日期字符串转换为 DateTime 对象，然后您可以使用该对象获取时间戳。

    $to = new DateTime($this->input->post('to'));
    $from = new DateTime($this->input->post('from'));

    $this->db->select(array(
        'tbl_customer_registration.cus_name',
        'tbl_customer_registration.cus_email',
        'tbl_customer_registration.cus_phone',
        'tbl_customer_registration.cus_mobile',
        'tbl_customer_registration.cus_addr_no',
        'tbl_customer_registration.cus_addr_street',
        'tbl_customer_registration.cus_addr_city',
        'tbl_user_registration.user_status',
        'tbl_user_registration.user_reason_status',
        'tbl_user_registration.user_timestamp',
    ));
    $this->db->from('tbl_customer_registration');
    $this->db->join('tbl_user_registration', 'tbl_user_registration.user_id=tbl_customer_registration.user_id');
    $this->db->group_by("tbl_customer_registration.cus_id"); //view single record that contain two contact numbers


    $this->db->where('user_timestamp >=',$to->getTimestamp());
    $this->db->where('user_timestamp <=',$from->getTimestamp());
    $query = $this->db->get();
    return $query->result();

希望这会有所帮助！

【参考方案2】：

这是解决方案...

function registered_customers_bod()
        $this->db->select(array(
            'tbl_customer_registration.cus_name',
            'tbl_customer_registration.cus_email',
            'tbl_customer_registration.cus_phone',
            'tbl_customer_registration.cus_mobile',
            'tbl_customer_registration.cus_addr_no',
            'tbl_customer_registration.cus_addr_street',
            'tbl_customer_registration.cus_addr_city',
            'tbl_user_registration.user_status',
            'tbl_user_registration.user_reason_status',
            'tbl_user_registration.user_timestamp',
        ));
        $this->db->from('tbl_customer_registration');
        $this->db->join('tbl_user_registration', 'tbl_user_registration.user_id=tbl_customer_registration.user_id');
        $this->db->group_by("tbl_customer_registration.cus_id"); //view single record that contain two contact numbers
        $this->db->where('STR_TO_DATE(user_timestamp, "%Y-%m-%d") >=',$this->input->post('to'));
        $this->db->where('STR_TO_DATE(user_timestamp, "%Y-%m-%d") <=',$this->input->post('from'));
        $query = $this->db->get();
        return $query->result();
    

希望对你有所帮助....

【讨论】：

这个答案会起作用，但是，我会尽量避免在 where 子句中使用 SQL 函数，因为这可能会影响性能。