使用 org.apache.http 发送带有 SOAP 操作的 HTTP Post 请求

Posted 2023-02-24

【中文标题】使用 org.apache.http 发送带有 SOAP 操作的 HTTP Post 请求

【英文标题】：Sending HTTP Post request with SOAP action using org.apache.http

【发布时间】：2012-05-27 03:23:47

【问题描述】：

我正在尝试使用 org.apache.http api 编写带有 SOAP 操作的硬编码 HTTP Post 请求。 我的问题是我没有找到添加请求正文的方法（在我的情况下 - SOAP 操作）。 很高兴得到一些指导。

import java.net.URI;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.impl.client.RequestWrapper;
import org.apache.http.protocol.HTTP;

public class HTTPRequest

    @SuppressWarnings("unused")
    public HTTPRequest()
    
        try 
            HttpClient httpclient = new DefaultHttpClient();
            String body="DataDataData";
            String bodyLength=new Integer(body.length()).toString();
            System.out.println(bodyLength);
//          StringEntity stringEntity=new StringEntity(body);

            URI uri=new URI("SOMEURL?Param1=1234&Param2=abcd");
            HttpPost httpPost = new HttpPost(uri);
            httpPost.addHeader("Test", "Test_Value");

//          httpPost.setEntity(stringEntity);

            StringEntity entity = new StringEntity(body, "text/xml",HTTP.DEFAULT_CONTENT_CHARSET);
            httpPost.setEntity(entity);

            RequestWrapper requestWrapper=new RequestWrapper(httpPost);
            requestWrapper.setMethod("POST");
            requestWrapper.setHeader("LuckyNumber", "77");
            requestWrapper.removeHeaders("Host");
            requestWrapper.setHeader("Host", "GOD_IS_A_DJ");
//          requestWrapper.setHeader("Content-Length",bodyLength);          
            HttpResponse response = httpclient.execute(requestWrapper);
         catch (Exception e) 
            e.printStackTrace();
        
    

【问题讨论】：

你写的代码在哪里

【参考方案1】：

这是一个完整的工作示例：

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost; 
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;

public void callWebService(String soapAction, String soapEnvBody)  throws IOException 
    // Create a StringEntity for the SOAP XML.
    String body ="<?xml version=\"1.0\" encoding=\"UTF-8\"?><SOAP-ENV:Envelope xmlns:SOAP-ENV=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:ns1=\"http://example.com/v1.0/Records\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:SOAP-ENC=\"http://schemas.xmlsoap.org/soap/encoding/\" SOAP-ENV:encodingStyle=\"http://schemas.xmlsoap.org/soap/encoding/\"><SOAP-ENV:Body>"+soapEnvBody+"</SOAP-ENV:Body></SOAP-ENV:Envelope>";
    StringEntity stringEntity = new StringEntity(body, "UTF-8");
    stringEntity.setChunked(true);

    // Request parameters and other properties.
    HttpPost httpPost = new HttpPost("http://example.com?soapservice");
    httpPost.setEntity(stringEntity);
    httpPost.addHeader("Accept", "text/xml");
    httpPost.addHeader("SOAPAction", soapAction);

    // Execute and get the response.
    HttpClient httpClient = new DefaultHttpClient();
    HttpResponse response = httpClient.execute(httpPost);
    HttpEntity entity = response.getEntity();

    String strResponse = null;
    if (entity != null) 
        strResponse = EntityUtils.toString(entity);
    

【讨论】：

我正在尝试您的代码并收到此异常：java.net.SocketException: Software caused connection abort: recv failed。我的类路径中有 httpclient-4.5.2.jar 和 httpcore-4.4.4.jar。有什么想法吗？

【参考方案2】：

这是我尝试过的示例，它对我有用：

创建 XML 文件 SoapRequestFile.xml

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:tem="http://tempuri.org/">
       <soapenv:Header/>
       <soapenv:Body>
          <tem:GetConversionRate>
             <!--Optional:-->
             <tem:CurrencyFrom>USD</tem:CurrencyFrom>
             <!--Optional:-->
             <tem:CurrencyTo>INR</tem:CurrencyTo>
             <tem:RateDate>2018-12-07</tem:RateDate>
          </tem:GetConversionRate>
       </soapenv:Body>
    </soapenv:Envelope>

这里是java中的代码：

import java.io.File;
import java.io.FileInputStream;

import org.apache.http.client.methods.CloseableHttpResponse;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.InputStreamEntity;
import org.apache.http.impl.client.CloseableHttpClient;
import org.apache.http.impl.client.HttpClients;
import org.apache.http.util.EntityUtils;
import org.junit.Assert;
import org.testng.annotations.Test;

import io.restassured.path.json.JsonPath;
import io.restassured.path.xml.XmlPath;
@Test
            public void getMethod() throws Exception  
                //wsdl file :http://currencyconverter.kowabunga.net/converter.asmx?wsdl
                File soapRequestFile = new File(".\\SOAPRequest\\SoapRequestFile.xml");

                CloseableHttpClient client = HttpClients.createDefault(); //create client
                HttpPost request = new HttpPost("http://currencyconverter.kowabunga.net/converter.asmx"); //Create the request
                request.addHeader("Content-Type", "text/xml"); //adding header
                request.setEntity(new InputStreamEntity(new FileInputStream(soapRequestFile)));
                CloseableHttpResponse response =  client.execute(request);//Execute the command

                int statusCode=response.getStatusLine().getStatusCode();//Get the status code and assert
                System.out.println("Status code: " +statusCode );
                Assert.assertEquals(200, statusCode);

                String responseString = EntityUtils.toString(response.getEntity(),"UTF-8");//Getting the Response body
                System.out.println(responseString);


                XmlPath jsXpath= new XmlPath(responseString);//Converting string into xml path to assert
                String rate=jsXpath.getString("GetConversionRateResult");
                System.out.println("rate returned is: " +  rate);



        

【参考方案3】：

它给出了 415 Http 响应代码作为错误，

所以我加了

httppost.addHeader("Content-Type", "text/xml; charset=utf-8");

现在一切正常，Http：200

【讨论】：

你能解释一下为什么添加这个有助于解决错误吗？

【参考方案4】：

在通过 java 客户端调用 WCF 服务时，识别需要在 soap 操作上设置什么的最简单方法是加载 wsdl，转到与服务匹配的操作名称。从那里获取操作 URI 并将其设置在肥皂操作标头中。你已经完成了。

例如：来自 wsdl

<wsdl:operation name="MyOperation">
  <wsdl:input wsaw:Action="http://tempuri.org/IMyService/MyOperation" message="tns:IMyService_MyOperation_InputMessage" />
  <wsdl:output wsaw:Action="http://tempuri.org/IMyService/MyServiceResponse" message="tns:IMyService_MyOperation_OutputMessage" />

现在在 java 代码中，我们应该将 soap 动作设置为动作 URI。

//The rest of the httpPost object properties have not been shown for brevity
string actionURI='http://tempuri.org/IMyService/MyOperation';
httpPost.setHeader( "SOAPAction", actionURI);

【参考方案5】：

... using org.apache.http api. ...

您需要在请求中包含SOAPAction 作为标头。由于您有httpPost 和requestWrapper 句柄，因此可以通过三种方式添加标题。

 1. httpPost.addHeader( "SOAPAction", strReferenceToSoapActionValue );
 2. httpPost.setHeader( "SOAPAction", strReferenceToSoapActionValue );
 3. requestWrapper.setHeader( "SOAPAction", strReferenceToSoapActionValue );

唯一的区别是addHeader 允许多个具有相同标头名称的值，而setHeader 仅允许唯一标头名称。 setHeader(... over 写入同名的第一个标头。

您可以根据自己的要求使用其中任何一种。

【讨论】：

@Ravinder 你能看看我朋友的问题吗：***.com/questions/12827900/…

【参考方案6】：

soapAction 必须作为 http-header 参数传递 - 使用时，它不是 http-body/payload 的一部分。

在这里查看使用 apache httpclient 的示例：http://svn.apache.org/repos/asf/httpcomponents/oac.hc3x/trunk/src/examples/PostSOAP.java

【讨论】：

你能看看我朋友的问题吗：***.com/questions/12827900/…