条件绑定的初始化程序必须具有可选类型，而不是“UIView”

Posted 2023-02-24

【中文标题】条件绑定的初始化程序必须具有可选类型，而不是“UIView”

【英文标题】：Initializer for conditional binding must have Optional type, not "UIView"

【发布时间】：2016-10-11 03:55:24

【问题描述】：

我最近下载了这个项目并将其转换为最新的 swift 语法。我不明白为什么我继续收到错误“

在线出错：

let containerView = transitionContext.containerView

这里是完整的代码：

func animateTransition(using transitionContext: UIViewControllerContextTransitioning) 
    guard
        let fromVC = transitionContext.viewController(forKey: UITransitionContextViewControllerKey.from),
        let toVC = transitionContext.viewController(forKey: UITransitionContextViewControllerKey.to),
        let containerView = transitionContext.containerView
        else 
            return

    

    containerView.insertSubview(toVC.view, belowSubview: fromVC.view)

    let screenBounds = UIScreen.main.bounds
    let bottomLeftCorner = CGPoint(x: 0, y: screenBounds.height)
    let finalFrame = CGRect(origin: bottomLeftCorner, size: screenBounds.size)

    UIView.animate(
        withDuration: transitionDuration(using: transitionContext),
        animations: 
            fromVC.view.frame = finalFrame
        ,
        completion:  _ in
            transitionContext.completeTransition(!transitionContext.transitionWasCancelled)
        
    )

【问题讨论】：

只需将let containerView = transitionContext.containerView移出保护语句并将其放在containerView.insertSubview(toVC.view, belowSubview: fromVC.view)上方

【参考方案1】：

这是因为containerView 属性不是可选类型。正如您在此处看到的（取自 UIViewControllerContextTransitioing 上的文档 (command + LMB)）：

...
public protocol UIViewControllerContextTransitioning : NSObjectProtocol 


    // The view in which the animated transition should take place.

    @available(ios 2.0, *)
    public var containerView: UIView  get 
...

您可以将错误的行放在guard 语句之后。