使用django时如何在ajax调用中传递request.user?
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【中文标题】使用django时如何在ajax调用中传递request.user?【英文标题】:How to pass request.user in ajax call when using django? 【发布时间】:2017-12-24 17:57:28 【问题描述】:我正在尝试将 json 数据发送到我网站上的 django 后端。当我想在视图函数中获取用户对象时,我收到了这个“AnonymousUser”错误。 以下是我的代码:
我的 api 视图:
@api_view(['GET','POST'])
def add_vote(request):
if request.method =='POST':
#I think this is where I can't figure out a way to deal with
user = request.user
serializer = VoteSerializer(data=request.data)
if serializer.is_valid():
instance = serializer.save(creator=user)
return redirect(instance)
return Response(serializer.errors)
if request.method == 'GET':
votes = VoteTitle.objects.all()
serializer = VoteSerializer(votes,many=True)
print(request.user)
return Response(serializer.data)
这是我的发送函数(一个反应类函数):
sent_json()
let send_json =
title: this.state.title,
subjects: [],
;
send_json.subjects = this.state.subjects.map((object) => (
name: object
));
send_json = JSON.stringify(send_json);
console.log(send_json);
let csrftoken = Cookies.get('csrftoken');
console.log(csrftoken);
let header =
"method": 'POST',
"body": send_json,
"headers":
"X-CSRFToken": csrftoken,
"Accept": "application/json",
"Content-Type": "application/json",
;
fetch('http://127.0.0.1:8000/voteapp/add/', header).then(function(response)
console.log(response);
return response.json();
).then(function(response)
console.log(response);
).catch(function(error)
alert(error);
);
django 后端显示的错误消息:
Internal Server Error: /voteapp/add/
Traceback (most recent call last):
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/core/handlers/exception.py", line 42, in inner
response = get_response(request)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/core/handlers/base.py", line 187, in _get_response
response = self.process_exception_by_middleware(e, request)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/core/handlers/base.py", line 185, in _get_response
response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/views/decorators/csrf.py", line 58, in wrapped_view
return view_func(*args, **kwargs)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/views/generic/base.py", line 68, in view
return self.dispatch(request, *args, **kwargs)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/rest_framework/views.py", line 489, in dispatch
response = self.handle_exception(exc)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/rest_framework/views.py", line 449, in handle_exception
self.raise_uncaught_exception(exc)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/rest_framework/views.py", line 486, in dispatch
response = handler(request, *args, **kwargs)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/rest_framework/decorators.py", line 52, in handler
return func(*args, **kwargs)
File "/Users/phil/Desktop/Web-Development/mini-blog/blog/voteapp/views.py", line 19, in add_vote
instance = serializer.save(creator=user)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/rest_framework/serializers.py", line 215, in save
self.instance = self.create(validated_data)
File "/Users/phil/Desktop/Web-Development/mini-blog/blog/voteapp/serializers.py", line 17, in create
vote = VoteTitle.objects.create(**data)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/db/models/manager.py", line 85, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/db/models/query.py", line 397, in create
obj = self.model(**kwargs)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/db/models/base.py", line 537, in __init__
setattr(self, field.name, rel_obj)
File "/Users/phil/Desktop/Web-Development/mini-blog/env/lib/python3.5/site-packages/django/db/models/fields/related_descriptors.py", line 211, in __set__
self.field.remote_field.model._meta.object_name,
ValueError: Cannot assign "<django.contrib.auth.models.AnonymousUser object at 0x1045995f8>": "VoteTitle.creator" must be a "User" instance.
提示错误消息:
SyntaxError (DOM Exception 12): The string did not match the expected pattern.
浏览器中的错误信息:
Failed to load resource: the server responded with a status of 500 (Internal Server Error)
我确定我已经登录了,所以我一定错过了什么。
【问题讨论】:
您能否在代码中使用console.log(csrftoken);
这一行打印 csrf 令牌。当您执行获取请求时会发生什么
yeah csrftoken 打印成功。我最近会在问题中添加响应对象。
如果在request.user下的视图函数中打印用户呢?
@hansTheFranz 我得到了“AnonymousUser”。
【参考方案1】:
在您的 javascript 中,使用 fetch
时包含凭据:
let header =
"method":'POST',
"body": send_json,
"credentials": 'include',
"headers":
"X-CSRFToken": csrftoken,
"Accept": "application/json",
"Content-Type": "application/json",
;
在 Django 视图中,您应该使用request.user
,就像您已经在使用的那样。
【讨论】:
是的,这行得通。请问为什么我仍然收到此错误消息“SyntaxError (DOM Exception 12): The string does not match the expected pattern.”发帖成功后 抱歉,我的 Python/Django 比我的 JavaScript 好得多,所以我无能为力。以上是关于使用django时如何在ajax调用中传递request.user?的主要内容,如果未能解决你的问题,请参考以下文章
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