将 xml xmpp 消息反序列化为对象

Posted 2023-02-24

【中文标题】将 xml xmpp 消息反序列化为对象

【英文标题】：Deserialize xml xmpp message to object

【发布时间】：2015-07-21 11:30:53

【问题描述】：

我正在尝试将 xml 字符串反序列化为 c# 对象。这是消息：

<message from='test1@localhost' to='test2@localhost'><result xmlns='urn:xmpp:mam:tmp' id='A6QV1I4TKO81'><forwarded xmlns='urn:xmpp:forward:0'><delay xmlns='urn:xmpp:delay' from='test1@localhost' stamp='2015-07-21T09:12:09Z'></delay><message type='mchat'><subject/><body/></message></forwarded></result></message>

这就是类

public class Delay 
    [XmlAttribute(AttributeName="xmlns")]
    public string Xmlns  get; set; 
    [XmlAttribute(AttributeName="from")]
    public string From  get; set; 
    [XmlAttribute(AttributeName="stamp")]
    public string Stamp  get; set; 


public class Active 
    [XmlAttribute(AttributeName="xmlns")]
    public string Xmlns  get; set; 


public class XmppMessage 
    [XmlElement(ElementName="body")]
    public string Body  get; set; 
    [XmlAttribute(AttributeName="lang")]
    public string Lang  get; set; 
    [XmlAttribute(AttributeName="type")]
    public string Type  get; set; 
    [XmlAttribute(AttributeName="id")]
    public string Id  get; set; 
    [XmlAttribute(AttributeName="to")]
    public string To  get; set; 


public class Forwarded 
    [XmlElement(ElementName="delay")]
    public Delay Delay  get; set; 
    [XmlElement(ElementName="message")]
    public XmppMessage Message  get; set; 
    [XmlAttribute(AttributeName="xmlns")]
    public string Xmlns  get; set; 


public class Result 
    [XmlElement(ElementName="forwarded")]
    public Forwarded Forwarded  get; set; 
    [XmlAttribute(AttributeName="xmlns")]
    public string Xmlns  get; set; 
    [XmlAttribute(AttributeName="id")]
    public string Id  get; set; 


[XmlRoot(ElementName="message")]
public class MessageHistory 
    [XmlElement(ElementName="result")]
    public Result Result  get; set; 
    [XmlAttribute(AttributeName="from")]
    public string From  get; set; 
    [XmlAttribute(AttributeName="to")]
    public string To  get; set; 

这是反序列化的代码：

MessageHistory messageNode;             
XmlSerializer serializer = new XmlSerializer(typeof(MessageHistory));
using (StringReader reader = new StringReader(message))
                    
                        messageNode = (MessageHistory)(serializer.Deserialize(reader));
                    

对象属性“from”和“to”没问题，但“Result”返回空值。我无法理解我在这里错过了什么......

【问题讨论】：

将 [XmlRoot(ElementName="..")] 添加到所有类。该名称区分大小写，因此您的类名称为“Forwarded”，标签名称为“forwarded”。添加 XmlRoot 将允许标记为小写，类名为大写。

MessageHistory 类上的 XmlRoot 就足够了，问题出在命名空间...还是谢谢你

【参考方案1】：

问题在于 XML 中的命名空间。您必须明确指定命名空间，如下所示：

public class Forwarded

    [XmlElement(ElementName = "delay", Namespace = "urn:xmpp:delay")]
    public Delay Delay  get; set; 
    [XmlElement(ElementName = "message")]
    public XmppMessage Message  get; set; 
    [XmlAttribute(AttributeName = "xmlns")]
    public string Xmlns  get; set; 


public class Result

    [XmlElement(ElementName = "forwarded", Namespace = "urn:xmpp:forward:0")]
    public Forwarded Forwarded  get; set; 
    [XmlAttribute(AttributeName = "xmlns")]
    public string Xmlns  get; set; 
    [XmlAttribute(AttributeName = "id")]
    public string Id  get; set; 


[XmlRoot(ElementName = "message")]
public class MessageHistory

    [XmlElement(ElementName = "result", Namespace = "urn:xmpp:mam:tmp")]
    public Result Result  get; set; 
    [XmlAttribute(AttributeName = "from")]
    public string From  get; set; 
    [XmlAttribute(AttributeName = "to")]
    public string To  get; set; 

【讨论】：

它现在可以工作了！非常感谢你！我不知道需要命名空间：/