如何使用 Gremlin 从我在 Titan 中关注的所有用户（边缘）获取帖子（顶点）

Posted 2023-02-23

【中文标题】如何使用 Gremlin 从我在 Titan 中关注的所有用户（边缘）获取帖子（顶点）

【英文标题】：How to get Post (Vertex) from all users whom I've followed (Edge) in Titan using Gremlin

【发布时间】：2016-09-05 04:28:45

【问题描述】：

我正在使用以下查询获取我关注的所有用户的列表：-

g.v(2304).out('关注')

回应：

"success": true,
"results": 

[



"Type": "User",
"CreatedTime": "2016-03-16T18:39:48.5000845Z",
"Username": "[e-mail]",
"FirstName": "Joany",
"CoverImageUrl": "https://s3-ap-southeast-1.amazonaws.com/urnotice/OrbitPage/User/Sumit/WallPost/947174ae-3e60-4dd0-877f-cc988fae3888.jpg",
"ImageUrl": "https://s3-ap-southeast-1.amazonaws.com/urnotice/OrbitPage/User/Sumit/WallPost/f4f6901c-64c4-425b-929b-43936c53eaba.png",
"LastName": "Ashtana",
"Gender": "male",
"_id": ​768,
"_type": "vertex"

,


"Type": "User",
"CreatedTime": "2016-04-05T16:36:49.3740440Z",
"Username": "[e-mail]",
"FirstName": "Maria",
"CoverImageUrl": "https://s3-ap-southeast-1.amazonaws.com/urnotice/images/companyRectangleImageNotAvailable.png",
"ImageUrl": "https://s3-ap-southeast-1.amazonaws.com/urnotice/users/female_professional.png",
"LastName": "Sharapova",
"Gender": "female",
"_id": ​5120256,
"_type": "vertex"

,


"Type": "User",
"CreatedTime": "2016-04-12T07:42:18.8036554Z",
"Username": "[e-mail]",
"FirstName": "Abhi",
"CoverImageUrl": "https://s3-ap-southeast-1.amazonaws.com/urnotice/OrbitPage/User/Sumit/WallPost/afd0d047-0d1c-4391-8f88-95f7775c615f.jpg",
"ImageUrl": "https://s3-ap-southeast-1.amazonaws.com/urnotice/OrbitPage/User/Sumit/WallPost/fd0842d4-579b-4896-9525-945f8f718816.JPG",
"LastName": "Sri",
"Gender": "male",
"_id": ​12800512,
"_type": "vertex"

,


"Type": "User",
"CreatedTime": "2016-04-15T07:51:34.3867249Z",
"Username": "[e-mail]",
"FirstName": "Goop",
"CoverImageUrl": "",
"ImageUrl": "https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg",
"LastName": "Chup",
"Gender": "NA",
"_id": ​17928960,
"_type": "vertex"

,


"Type": "User",
"CreatedTime": "2016-04-20T03:25:30.0753729Z",
"Username": "[e-mail]",
"FirstName": "Kunal",
"CoverImageUrl": "https://s3-ap-southeast-1.amazonaws.com/urnotice/OrbitPage/User/Sumit/WallPost/ee167d15-52bb-4f4f-99fb-038f27eee1dc.jpeg",
"ImageUrl": "https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg",
"LastName": "Sharma",
"Gender": "NA",
"_id": ​23041024,
"_type": "vertex"


],
"version": "2.5.0",
"queryTime": ​21.94298

我正在使用以下查询获取特定用户的帖子：

gv(396800).in('WallPost').sort a, b -> b.PostedTime a.PostedTime .()[0..3].transform [postInfo :它，cmetsInfo: it.in('Comment').sort a, b -> b.PostedTime a.PostedTime .()[0..5].transform[commentInfo:it , 评论者：it.in('Created')],userInfo:it.in('Created')]

我得到了回应：

"success": true,
"results": [

  "postInfo": 
    "PostImage": "",
    "Type": "Post",
    "PostedByUser": "[e-mail]",
    "PostedTime": "2016-04-29T11:48:17.5069984Z",
    "PostedTimeLong": ​635975272975069984,
    "PostMessage": "testing new post. on pooja",
    "_id": ​30729984,
    "_type": "vertex"
  ,
  "commentsInfo": [

  ],
  "userInfo": [
    
      "Type": "User",
      "CreatedTime": "2016-04-20T03:25:30.0753729Z",
      "Username": "[e-mail]",
      "FirstName": "Kunal",
      "CoverImageUrl": "https://s3-ap-southeast-1.amazonaws.com/urnotice/OrbitPage/User/Sumit/WallPost/ee167d15-52bb-4f4f-99fb-038f27eee1dc.jpeg",
      "ImageUrl": "https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg",
      "LastName": "Sharma",
      "Gender": "NA",
      "_id": ​23041024,
      "_type": "vertex"
    
  ]

],
"version": "2.5.0",
"queryTime": ​383.759295

我想获取我关注的所有用户的帖子，并根据 post Vertex 的 PostTime 降序排列。 我已经尝试了很多，但我没有得到任何方法来实现这一点。

【参考方案1】：

你做得对。只需首先获取您关注的所有顶点，然后在所有顶点上应用您的 get wall post 逻辑，它就会给您想要的结果。

g.v(2304).out('Follow').in('WallPost').sort 
    a, b -> b.PostedTime <=> a.PostedTime
.()[0..3]
.transform 
    [
        postInfo: it,
        commentsInfo: it.in('Comment').sort 
            a, b -> b.PostedTime <=> a.PostedTime
        .()[0..5].
        transform 
            [
                commentInfo: it,
                commentedBy: it.in('Created')
            ]
        ,
        userInfo:it.in('Created')
    ]

因此它会为您提供您关注的所有帖子的列表，并按PostedTime 的降序排列。