将值替换为数据集列上的整数

Posted 2023-02-23

【中文标题】将值替换为数据集列上的整数

【英文标题】：Replacement Values into the integer on dataset columns

【发布时间】：2022-01-03 06:00:11

【问题描述】：

	House Number	Street	First Name	Surname	Age	Relationship to Head of House	Marital Status	Gender	Occupation	Infirmity	Religion
0	1	Smith Radial	Grace	Patel	46	Head	Widowed	Female	Petroleum engineer	None	Catholic
1	1	Smith Radial	Ian	Nixon	24	Lodger	Single	Male	Publishing rights manager	None	Christian
2	2	Smith Radial	Frederick	Read	87	Head	Divorced	Male	Retired TEFL teacher	None	Catholic
3	3	Smith Radial	Daniel	Adams	58	Head	Divorced	Male	Therapist, music	None	Catholic
4	3	Smith Radial	Matthew	Hall	13	Grandson	NaN	Male	Student	None	NaN
5	3	Smith Radial	Steven	Fletcher	9	Grandson	NaN	Male	Student	None	NaN
6	4	Smith Radial	Alison	Jenkins	38	Head	Single	Female	Physiotherapist	None	Catholic
7	4	Smith Radial	Kelly	Jenkins	12	Daughter	NaN	Female	Student	None	NaN
8	5	Smith Radial	Kim	Browne	69	Head	Married	Female	Retired Estate manager/land agent	None	Christian
9	5	Smith Radial	Oliver	Browne	69	Husband	Married	Male	Retired Merchandiser, retail	None	None

你好，

我有一个数据集，您可以在下面看到。当我尝试将 Age 转换为 int 时。我得到了那个错误： ValueError: invalid literal for int() with base 10: '43.54302670766108'

这意味着该数据中存在浮点数据。我试图替换“。”到 '0' 然后尝试转换但我失败了。你能帮我做吗？

df['Age'] = df['Age'].replace('.','0')
df['Age'] = df['Age'].astype('int')

我仍然遇到同样的错误。我认为替换线不起作用。你知道为什么吗？

谢谢

【参考方案1】：

试试：

df['Age'] = df['Age'].replace('\..*$', '', regex=True).astype(int)

或者，更激烈：

df['Age'] = df['Age'].replace('^(?:.*\D.*)?$', '0', regex=True).astype(int)

【讨论】：

仍然得到：ValueError: int() 以 10 为基数的无效文字：' ' –

@asli 你能测试第二个命令吗

感谢您的帮助。你能检查我的另一个问题吗？它与那个相似。 ***.com/questions/70086440/…

【参考方案2】：

您不需要操纵字符串；您可能首先将值转换为浮点数，然后转换为 int，例如：

df["Age"] = df["Age"].astype('float').astype('int') 

【讨论】：

我收到“无法将字符串转换为浮点数：''”错误。他们首先是反对和刺痛