JavaScript，JSON：如何在特定时间内运行 for 循环？

Posted 2023-02-14

【中文标题】JavaScript，JSON：如何在特定时间内运行 for 循环？

【英文标题】：JavaScript, JSON : how can I run a foor loop a specific amount of time?

【发布时间】：2022-01-17 08:15:33

【问题描述】：

我有这个代码 - 它有点棘手：

let i = 0;
const inputBuffer = [];

const randomnumber = (min, max) => 
    return Math.floor(Math.random() * (max - min + 1) + min);


for (let k = 0; k < 10; k++) 
    console.log(convert(randomnumber(0, 1982)));


function convert(input) 
    inputBuffer.push(input);
    const output = "current" : "0";
    
    if (i % 3 == 0) 
        let sum = 0;
        for (let ii = 0; ii < i; ii++) 
            sum += inputBuffer[ii];
        
        output.sum = sum;
    
    i++;
    output.current = input;
   
    return JSON.stringify(output);

输出如下：

"current":605,"sum":0
"current":708
"current":456
"current":1838,"sum":1769
"current":1619
"current":1404
"current":1068,"sum":6630
"current":1178
"current":989
"current":1280,"sum":9865

但我希望它看起来像这样：

"current": 605
"current": 708
"current": 456
"current": 1838,"sum":1769
"current": 1619
"current": 1404
"current": 1068,"sum":6630
"current": 1178
"current": 989
"current": 1280,"sum":9865

let i = 0;
const inputBuffer = [];

const randomnumber = (min, max) => 
  return Math.floor(Math.random() * (max - min + 1) + min);


for (let k = 0; k < 10; k++) 
  console.log(convert(randomnumber(0, 1982)));


function convert(input) 
  inputBuffer.push(input);
  const output = 
    "current": "0"
  ;
  if (i % 3 == 0) 
    let sum = 0;
    for (let ii = 0; ii < i; ii++) 
      sum += inputBuffer[ii];
    
    output.sum = sum;
  
  i++;
  output.current = input;

  return JSON.stringify(output);

我不想第一次显示总和，但以后每 3 次显示一次

有什么想法吗？ :D

PS。我更喜欢保持基本，只使用 for 循环

祝你有个愉快的夜晚

【参考方案1】：

您可以在分配output.sum 的值时检查i 是否不为零吗？

类似于以下内容：

let i = 0;
const inputBuffer = [];

const randomnumber = (min, max) => 
    return Math.floor(Math.random() * (max - min + 1) + min);


for (let k = 0; k < 10; k++) 
    console.log(convert(randomnumber(0, 1982)));


function convert(input) 
    inputBuffer.push(input);
    const output = "current" : "0";
    
    
    if (i % 3 == 0) 
        let sum = 0;
        for (let ii = 0; ii < i; ii++) 
            sum += inputBuffer[ii];
        
        if (i !== 0) output.sum = sum; // HERE
    
    i++;
    output.current = input;
   
    return JSON.stringify(output);

【讨论】：

是的，就是这样，我也用 debounce 做到了，谢谢：D

【参考方案2】：

我发现了这一点，你的显然更短，但这是我的想法：D

let i = 0;
const inputBuffer = [];
let db = false;
const randomnumber = (min, max) => 
    return Math.floor(Math.random() * (max - min + 1) + min);


for (let k = 0; k < 10; k++) 
    console.log(convert(randomnumber(0, 1982)));


function convert(input) 
    inputBuffer.push(input);
    
    const output = "current" : "0";
    

    if (db && i % 3 == 0) 
        let sum = 0;
        for (let ii = 0; ii < i; ii++) 
            sum += inputBuffer[ii];
        
        output.sum = sum;
    
    i++
    db = true;
    
    output.current = input;
   
    return JSON.stringify(output);