api调用成功后flutter返回消息
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【中文标题】api调用成功后flutter返回消息【英文标题】:Flutter return a message after successful Api call 【发布时间】:2020-07-02 01:37:02 【问题描述】:您好,我是 Flutter 的新手,我决定制作 TodoList 应用程序来提高我的技能并习惯于 Flutter 和使用 api
我想要做的是我想在向 api 提交数据后显示一条用我们的语言编写的消息
代码
Future<Todo> sendData(String title, String body) async
final http.Response response = await http.post(
'http://192.168.1.20/Todo_api/public/todos/store',
headers: <String , String>
'Content-Type' : 'application/json; charset=UTF-8',
,
body: jsonEncode(<String,String>
'title' : title,
'body' : body,
),
);
if(response.statusCode == 200)
//200 Created
//parse json
return Todo.fromJson(jsonDecode(response.body)) ;
else
throw Exception('Failed to submit Contact the Devolopers please ');
如您所见,如果代码为 200(成功),我想向用户显示一条消息,而不是解析对用户的 json 响应,因为他不会得到它,而且我想调用 Navigator.pop( ) 以便用户可以返回主屏幕 我尝试了返回函数,小部件,字符串,...等,但它没有工作并一直抛出这个错误
错误:无法返回类型为“Null Function()”的值 函数“sendData”,因为它的返回类型为“Future”。 (return_of_invalid_type at [todolist] lib\CreateTodo.dart:35)
所以我想做之前提到的我想回到主屏幕并像在 laravel 中一样为用户显示友好的消息
return redirect("/")->with('success' , 'Todo Stored Successfully');
就是这样 感谢您查看我的帖子并提前致谢
更新:通过对我的变量执行 if 语句来解决它
完整代码
import 'dart:convert';
import 'dart:async';
import 'package:flutter/material.dart';
import 'package:http/http.dart' as http;
import 'package:rflutter_alert/rflutter_alert.dart';
import 'main.dart';
class Todo
final title;
final body;
Todo (this.title , this.body);
factory Todo.fromJson(Map<String , dynamic> json)
return Todo(
title: json['title'],
body: json['body'],
);
Future<Todo> sendData(String title, String body) async
final http.Response response = await http.post(
'http://192.168.1.20/Todo_api/public/todos/store',
headers: <String , String>
'Content-Type' : 'application/json; charset=UTF-8',
,
body: jsonEncode(<String,String>
'title' : title,
'body' : body,
),
);
if(response.statusCode == 201)
return Todo.fromJson(jsonDecode(response.body));
else
return null;
class CreateTodo extends StatefulWidget
@override
_CreateTodoState createState() => _CreateTodoState();
class _CreateTodoState extends State<CreateTodo>
Future<Todo> _futureTodo;
String title = "";
String body = "";
@override
Widget build(BuildContext context)
return Scaffold(
appBar: AppBar(
title: Text("Create Todo"),
),
body: Center(
child : ListView(
children: <Widget>[
Padding(
padding: const EdgeInsets.all(8.0),
child: TextField(
onChanged: (text)
title = text;
,
decoration: InputDecoration(hintText: 'Enter Title'),
),
),
Padding(
padding: const EdgeInsets.all(8.0),
child: TextField(
onChanged: (text)
body = text;
,
decoration: InputDecoration(hintText: 'Enter Body'),
),
),
IconButton(
icon: Icon(Icons.send),
//if contains data then send else block
onPressed: ()
if (title == '' || body == '')
Alert(context: context, title: "Error", desc: "Please fill the form", type: AlertType.error).show();
else
_futureTodo = sendData(title,body);
Alert(context: context, title: "Success", desc: "Stored Successfully", type: AlertType.success,
buttons: [
DialogButton(
child: Text(
"Home",
style: TextStyle(color: Colors.white, fontSize: 20),
),
onPressed: ()
Navigator.push(
context,
MaterialPageRoute(builder: (context) => MyApp()),
);
,
width: 120,
),
DialogButton(
child: Text(
"Back",
style: TextStyle(color: Colors.white, fontSize: 20),
),
onPressed: ()
Navigator.push(
context,
MaterialPageRoute(builder: (context) => CreateTodo()),
);
,
),
]
).show();
,
),
],
),
),
);
【问题讨论】:
【参考方案1】:这应该对你有帮助
class Api extends StatelessWidget
@override
Widget build(BuildContext context)
return Scaffold(
floatingActionButton: Builder(
builder: (context)
return FloatingActionButton(
onPressed: ()
sendData("default", "default").then((value)
Scaffold.of(context).showSnackBar(SnackBar(content: Text("Welcome"),))
);
,
);
,
),
);
Future<bool> sendData(String title, String body) async
final http.Response response = await http.post(
'http://192.168.1.20/Todo_api/public/todos/store',
headers: <String , String>
'Content-Type' : 'application/json; charset=UTF-8',
,
body: jsonEncode(<String,String>
'title' : title,
'body' : body,
),
);
if(response.statusCode == 200)
//200 Created
//parse json
return true;
else
throw Exception('Failed to submit Contact the Devolopers please ');
【讨论】:
嗯,这对我不起作用,因为主要是你不能在这个函数中返回 bool,而且小吃店也因为某种原因没有出现,但我会接受它作为答案,因为你给了我解决问题的字符串以上是关于api调用成功后flutter返回消息的主要内容,如果未能解决你的问题,请参考以下文章
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