如何从数组 eloquent laravel 中获取权限名称值
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【中文标题】如何从数组 eloquent laravel 中获取权限名称值【英文标题】:How to get permission name value from array eloquent laravel 【发布时间】:2020-12-12 02:59:45 【问题描述】:如果我的英语有点奇怪,我很抱歉,如果你不明白我的问题,请问我。 所以,我想要这样的逻辑。当我尝试使用像下面这样的简单数组时,它可以工作。
$a = array('car', 'bicycle', 'plane');
$b = array('car', 'boat', 'truck');
foreach ($a as $c)
if (in_array($c,$b))
echo "<b>" . $c . "</b>";
echo "\r\n";
else
echo $c;
echo "\r\n";
但是当我尝试在数组 laravel eloqeunt 中应用它时,看起来我无法从数组中获取值。我想匹配数据库中的数组(权限名称)。我想显示“权限”表中的所有权限名称,然后如果“权限名称”已经应用于“角色”,我希望它显示为选中状态。这是我的代码:
$roles = Role::where('id', '=', 2)->with(['permissions'])->get();
$permissions = Permission::all();
foreach ($roles as $role)
foreach ($permissions as $permission)
$roleper = array($role['permissions']);
$pername = array($permissions);
if (in_array($pername,$roleper))
echo "<b>" . $permission['name'] . "</b>";
echo "\r\n";
else
echo $permission['name'];
echo "\r\n";
当我返回 $roleper 时,结果如下:
[["id":1,"name":"Add Color","guard_name":"web","created_at":"2020-08-10 02:49:25","updated_at":"2020-08-10 02:49:25","pivot":"role_id":2,"permission_id":1,"id":2,"name":"Edit Color","guard_name":"web","created_at":"2020-08-10 02:50:49","updated_at":"2020-08-10 02:50:49","pivot":"role_id":2,"permission_id":2,"id":3,"name":"Delete Color","guard_name":"web","created_at":"2020-08-10 02:50:57","updated_at":"2020-08-10 02:50:57","pivot":"role_id":2,"permission_id":3]]
当我返回 $pername 时,结果如下:
[["id":1,"name":"Add Color","guard_name":"web","created_at":"2020-08-10 02:49:25","updated_at":"2020-08-10 02:49:25","id":2,"name":"Edit Color","guard_name":"web","created_at":"2020-08-10 02:50:49","updated_at":"2020-08-10 02:50:49","id":3,"name":"Delete Color","guard_name":"web","created_at":"2020-08-10 02:50:57","updated_at":"2020-08-10 02:50:57","id":4,"name":"Add Material","guard_name":"web","created_at":"2020-08-10 03:11:16","updated_at":"2020-08-10 03:11:16","id":5,"name":"Edit Material","guard_name":"web","created_at":"2020-08-10 03:11:25","updated_at":"2020-08-10 03:11:25","id":6,"name":"Delete Material","guard_name":"web","created_at":"2020-08-10 03:11:36","updated_at":"2020-08-10 03:11:36","id":7,"name":"Add Brand","guard_name":"web","created_at":"2020-08-10 03:11:48","updated_at":"2020-08-10 03:11:48","id":8,"name":"Edit Brand","guard_name":"web","created_at":"2020-08-10 03:11:54","updated_at":"2020-08-10 03:11:54","id":9,"name":"Delete Brand","guard_name":"web","created_at":"2020-08-10 03:12:00","updated_at":"2020-08-10 03:12:00","id":10,"name":"Add Product","guard_name":"web","created_at":"2020-08-10 03:12:09","updated_at":"2020-08-10 03:12:09","id":11,"name":"Edit Product","guard_name":"web","created_at":"2020-08-10 03:12:17","updated_at":"2020-08-10 03:12:17","id":12,"name":"Delete Product","guard_name":"web","created_at":"2020-08-10 03:12:23","updated_at":"2020-08-10 03:12:23"]]
【问题讨论】:
【参考方案1】:您可以使用内置方法array_intersect、array_diff 来获取两个数组之间的共同和不同元素
$permissions = Permission::all()->pluck('name')->toArray();
foreach ($roles as $role)
$rolePermissions = $role['permissions']->pluck('name')->toArray();
$maches = array_intersect($permissions, $rolePermissions);
$differences = array_diff($permissions, $rolePermissions);
//... loop $matches and $differences
【讨论】:
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