d3.js - 在力有向图组上添加背景矩形
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【中文标题】d3.js - 在力有向图组上添加背景矩形【英文标题】:d3.js - Add background rectangle on force directed diagram groups 【发布时间】:2021-09-16 12:50:45 【问题描述】:我想在第2组中添加一个背景矩形,想法是添加一个g元素并将所有第2组节点附加到g元素,然后使用g元素bbox绘制一个矩形。
但我不知道如何将现有节点移动到 g 元素! (也许不可能?)。
示例代码如下:
var graph =
nodes:[
id: "A",name:'AAAA', group: 1,
id: "B", name:'BBBB',group: 2,
id: "C", name:'CCCC',group: 2,
id: "D", name:'DDDD',group: 2,
id: "E", name:'EEEE',group: 2,
id: "F", name:'FFFF',group: 3,
id: "G", name:'GGGG',group: 3,
id: "H", name:'HHHH',group: 3,
id: "I", name:'IIII',group: 3
],
links:[
source: "A", target: "B", value: 1,
source: "A", target: "C", value: 1,
source: "A", target: "D", value: 1,
source: "A", target: "E", value: 1,
source: "A", target: "F", value: 1,
source: "A", target: "G", value: 1,
source: "A", target: "H", value: 1,
source: "A", target: "I", value: 1,
]
;
var width = 400
var height = 200
var svg = d3.select('body').append('svg')
.attr('width',width)
.attr('height',height)
.style('border','1px solid red')
var color = d3.scaleOrdinal(d3.schemeCategory10);
var simulation = d3.forceSimulation()
.force("link", d3.forceLink().id(function(d) return d.id; ).distance(100))
.force("charge", d3.forceManyBody())
.force("x", d3.forceX(function(d)
if(d.group === 2)
return width/3
else if (d.group === 3)
return 2*width/3
else
return width/2
))
.force("y", d3.forceY(height/2))
.force("center", d3.forceCenter(width / 2, height / 2));
var g = svg.append("g")
.attr("class", "nodes")
.selectAll("circle")
.data(graph.nodes)
.enter()
var w = 80
var txts = g.append('text')
.attr('class','text')
.attr('text-anchor','middle')
.attr("dominant-baseline", "central")
.attr('fill','black')
.text(d => d.name)
.each((d,i,n) =>
var bbox = d3.select(n[i]).node().getBBox()
var margin = 4
bbox.x -= margin
bbox.y -= margin
bbox.width += 2*margin
bbox.height += 2*margin
if (bbox.width < w)
bbox.width = w
d.bbox = bbox
)
var node = g
.insert('rect','text')
.attr('stroke','black')
.attr('width', d => d.bbox.width)
.attr('height',d => d.bbox.height)
.attr("fill", function(d) return color(d.group); )
.attr('fill-opacity',0.3)
.call(d3.drag()
.on("start", dragstarted)
.on("drag", dragged)
.on("end", dragended));
var link = svg.append("g")
.attr("class", "links")
.attr('stroke','black')
.selectAll("line")
.data(graph.links)
.enter().append("path")
.attr("stroke-width", function(d) return Math.sqrt(d.value); );
simulation
.nodes(graph.nodes)
.on("tick", ticked);
simulation.force("link")
.links(graph.links);
function ticked()
link
.attr("d", function(d)
var ax = d.source.x
var ay = d.source.y
var bx = d.target.x
var by = d.target.y
if (bx < ax)
ax -= w/2
bx += w/2
else
ax += w/2
bx -= w/2
var path = ['M',ax,ay,'L',bx,by]
return path.join(' ')
)
txts.attr('x',d => d.x)
.attr('y',d => d.y)
node
.attr("x", function(d) return d.x - d.bbox.width/2; )
.attr("y", function(d) return d.y - d.bbox.height/2; );
function dragstarted(event,d)
if (!event.active) simulation.alphaTarget(0.3).restart();
d.fx = d.x;
d.fy = d.y;
function dragged(event,d)
d.fx = event.x;
d.fy = event.y;
function dragended(event,d)
if (!event.active) simulation.alphaTarget(0);
d.fx = null;
d.fy = null;
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/6.7.0/d3.min.js"></script>
【问题讨论】:
【参考方案1】:力模拟不使用 DOM 做任何事情。它只是计算节点应该在哪里,如何渲染它们,如果你渲染它们,取决于你。因此,将一些节点放在g
中而不是其他节点不是问题。例如,我们可以为组 2 添加一个g
,遍历所有节点,如果它们来自组 2,则将它们从 DOM 中分离出来,然后将它们重新附加到新的g
:
var parent = d3.select("g").append("g").lower();
node.each(function(d)
if (d.group == 2)
d3.select(this).remove();
parent.append((d)=>this);
)
那么我们需要做的就是创建一个背景矩形:
var background = d3.select("g")
.append("rect")
.lower() // so it is behind the nodes.
....
并在勾选时使用g
的新边界框更新它,如下所示。
var graph =
nodes:[
id: "A",name:'AAAA', group: 1,
id: "B", name:'BBBB',group: 2,
id: "C", name:'CCCC',group: 2,
id: "D", name:'DDDD',group: 2,
id: "E", name:'EEEE',group: 2,
id: "F", name:'FFFF',group: 3,
id: "G", name:'GGGG',group: 3,
id: "H", name:'HHHH',group: 3,
id: "I", name:'IIII',group: 3
],
links:[
source: "A", target: "B", value: 1,
source: "A", target: "C", value: 1,
source: "A", target: "D", value: 1,
source: "A", target: "E", value: 1,
source: "A", target: "F", value: 1,
source: "A", target: "G", value: 1,
source: "A", target: "H", value: 1,
source: "A", target: "I", value: 1,
]
;
var width = 400
var height = 200
var svg = d3.select('body').append('svg')
.attr('width',width)
.attr('height',height)
.style('border','1px solid red')
var color = d3.scaleOrdinal(d3.schemeCategory10);
var simulation = d3.forceSimulation()
.force("link", d3.forceLink().id(function(d) return d.id; ).distance(100))
.force("charge", d3.forceManyBody())
.force("x", d3.forceX(function(d)
if(d.group === 2)
return width/3
else if (d.group === 3)
return 2*width/3
else
return width/2
))
.force("y", d3.forceY(height/2))
.force("center", d3.forceCenter(width / 2, height / 2));
var g = svg.append("g")
.attr("class", "nodes")
.selectAll("circle")
.data(graph.nodes)
.enter()
var w = 80
var txts = g.append('text')
.attr('class','text')
.attr('text-anchor','middle')
.attr("dominant-baseline", "central")
.attr('fill','black')
.text(d => d.name)
.each((d,i,n) =>
var bbox = d3.select(n[i]).node().getBBox()
var margin = 4
bbox.x -= margin
bbox.y -= margin
bbox.width += 2*margin
bbox.height += 2*margin
if (bbox.width < w)
bbox.width = w
d.bbox = bbox
)
var node = g
.insert('rect','text')
.attr('stroke','black')
.attr('width', d => d.bbox.width)
.attr('height',d => d.bbox.height)
.attr("fill", function(d) return color(d.group); )
.attr('fill-opacity',0.3)
.call(d3.drag()
.on("start", dragstarted)
.on("drag", dragged)
.on("end", dragended));
// Start Changes 1/2
var parent = d3.select("g").append("g").lower();
node.each(function(d)
if (d.group == 2)
d3.select(this).remove();
parent.append((d)=>this);
)
var background = d3.select("g")
.append("rect")
.lower()
.attr("ry", 5)
.attr("rx", 5)
.attr("fill","#ccc")
.attr("stroke","#999")
.attr("stroke-width", 1);
// End Changes 1/2
var link = svg.append("g")
.attr("class", "links")
.attr('stroke','black')
.selectAll("line")
.data(graph.links)
.enter().append("path")
.attr("stroke-width", function(d) return Math.sqrt(d.value); );
simulation
.nodes(graph.nodes)
.on("tick", ticked);
simulation.force("link")
.links(graph.links);
function ticked()
link
.attr("d", function(d)
var ax = d.source.x
var ay = d.source.y
var bx = d.target.x
var by = d.target.y
if (bx < ax)
ax -= w/2
bx += w/2
else
ax += w/2
bx -= w/2
var path = ['M',ax,ay,'L',bx,by]
return path.join(' ')
)
txts.attr('x',d => d.x)
.attr('y',d => d.y)
node
.attr("x", function(d) return d.x - d.bbox.width/2; )
.attr("y", function(d) return d.y - d.bbox.height/2; );
// Start changes 2/2
var box = parent.node().getBBox()
background.attr("width", box.width+10)
.attr("height",box.height+10)
.attr("x", box.x-5)
.attr("y", box.y-5);
//End Changes 2/2
function dragstarted(event,d)
if (!event.active) simulation.alphaTarget(0.3).restart();
d.fx = d.x;
d.fy = d.y;
function dragged(event,d)
d.fx = event.x;
d.fy = event.y;
function dragended(event,d)
if (!event.active) simulation.alphaTarget(0);
d.fx = null;
d.fy = null;
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/6.7.0/d3.js"></script>
如果您想要多个组,或者有动态数据,这种方法并不理想 - 需要对连接或数据结构进行一些修改以使更规范的方法起作用 - 我可能会重新审视今晚晚些时候有一个替代方案。就目前而言,这种解决方案可能是对您现有代码的侵入性最小的解决方案。
【讨论】:
GAndrew Reid 很好的答案,如果我们可以为每个组添加背景矩形是个好主意。以上是关于d3.js - 在力有向图组上添加背景矩形的主要内容,如果未能解决你的问题,请参考以下文章