获取给定路径中的所有文件和子文件夹 - C/C++ 中的语言兼容性
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【中文标题】获取给定路径中的所有文件和子文件夹 - C/C++ 中的语言兼容性【英文标题】:Getting all files and subfolders in given path - language compatibility in C/C++ 【发布时间】:2014-08-27 20:28:44 【问题描述】:所以基本上我需要列出所有文件和子文件夹以及其中的文件等,直到检查完所有路径,从每个对象中读取数据并将其全部打包到一个文件中。
我不想使用 boost 或 minizip,因为对于如此简单的事情来说似乎太多了,所以我只是自己通过 dirent 编写的 - 一切正常我只是对标题中包含非 ANSI 字符的目录和文件有问题(我m 来自波兰)如ąęóźż 等。 我可以毫无问题地打开它们并从中读取所有数据,但是当我将它们的文件名打包到 std::string 时 - 它被损坏并且碰巧是:
TEST~1 代替 TESTąę
我如何将文件和目录打包成单个文件:
我通过dirent读取主目录的内容,如果我找到文件-我只是读取它的路径和结构数据,如果我找到另一个目录-我只是读取它的结构路径并在该目录上递归调用搜索函数。
我使用 fopen,fwrite,fread 读写文件。
请注意,文件内的数据正在写入没有问题 - 所有特殊字符都没有问题存储。
对此的任何帮助将不胜感激。
代码:
#include <list>
#include <string>
#include <dirent.h>
#include <cstdio>
#include <windows.h>
typedef struct
std::string path;
unsigned lenght_of_path;
char type;
unsigned size;
char *data;
single_element;
int pack(std::string root_directory, std::list<single_element> *all_elements)
//packs all files and subfolder and files and subfolder inside them etc into a std::list of structures
//please don't mind 0 error checks but I just want to get that language thing first
single_element temp;
temp.data = NULL;
FILE *processed;
DIR *directory;
struct dirent *ent;
if ((directory = opendir(root_directory.c_str())) != NULL)
while ((ent = readdir(directory)) != NULL)
std::string actual_path = root_directory;
std::string packed_file = ent->d_name;
if (packed_file != "." && packed_file != "..") //ignore .. and . in listing
if (ent->d_type == 16384) //if we found a directory
actual_path += "\\";
actual_path += packed_file;
temp.data = NULL;
temp.type = 'D'; // D is for directory, used later when extracting
temp.path = actual_path;
temp.lenght_of_path = actual_path.length();
temp.size = 0;
all_elements->push_back(temp);
pack(actual_path,all_elements); //recursively scan subfolder
else //we got file - I know there also can be other things as symbolic link but its only for test and I'm going to fix it once it works
actual_path += "\\";
actual_path += packed_file;
processed = fopen(actual_path.c_str(),"rb");
if (processed != NULL)
temp.path = actual_path;
temp.lenght_of_path = actual_path.length();
temp.type = 'F'; //F is for FILE;
fseek (processed,0,SEEK_END);
temp.size = ftell(processed);
all_elements->push_back(temp);
all_elements->back().data = new char[all_elements->back().size];
rewind(processed);
fread(all_elements->back().data,all_elements->back().size,1,processed);
fclose(processed);
closedir (directory);
return 0;
int save(std::string file_name, std::list<single_element> all_elements)
//write all_elements to single file
file_name += ".pak";
FILE *packed = fopen(file_name.c_str(),"wb");
int ammount = all_elements.size();
fwrite((const void*)&ammount,sizeof(int),1,packed); //fist write how many elements there are to be packed
for (std::list<single_element>::iterator i = all_elements.begin(); i != all_elements.end(); i++) //write each element
fwrite((const void*)&i->lenght_of_path,sizeof(unsigned),1,packed);
fwrite(i->path.c_str(),i->lenght_of_path,1,packed);
fwrite((const void*)&i->type,sizeof(char),1,packed);
if (i->type == 'F') //if its file write also data and it's size
fwrite((const void*)&i->size,sizeof(unsigned),1,packed);
fwrite(i->data,i->size,1,packed);
fclose(packed);
return 0;
int load(std::string file, std::list<single_element> *all_elements)
//load elements from file to list of structures
char *buf = NULL;
file += ".pak";
FILE *packed = fopen(file.c_str(),"rb");
single_element temp;
int ammount;
fread((void*)&ammount,sizeof(int),1,packed); //first read how many elements there are
for (int i = 0; i < ammount; i++)
fread((void*)&temp.lenght_of_path,sizeof(unsigned),1,packed);
buf = new char[temp.lenght_of_path+1];
fread(buf,temp.lenght_of_path,1,packed);
buf[temp.lenght_of_path] = '\0';
temp.path = buf;
delete buf;
buf = NULL;
fread((void*)&temp.type,sizeof(char),1,packed);
all_elements->push_back(temp);
if (temp.type == 'F') //if its file, also read its data and size
fread((void*)&all_elements->back().size,sizeof(unsigned),1,packed);
all_elements->back().data = new char[all_elements->back().size];
fread(all_elements->back().data,all_elements->back().size,1,packed);
else //else we got directory so just write 0 to size and NULL to data
all_elements->back().size = 0;
all_elements->back().data = NULL;
fclose(packed);
return 0;
int extract(std::string root_directory, std::list<single_element> all_elements)
CreateDirectory(root_directory.c_str(),NULL); //create root directory
std::list<single_element>::iterator i = all_elements.begin();
while (i != all_elements.end()) //first create all directories
if (i->type == 'D') //if we got a directory create it and erase from list
CreateDirectory(i->path.c_str(),NULL);
i = all_elements.erase(i);
else ++i;
i = all_elements.begin();
while (i != all_elements.end()) //now extract all files
FILE *extracted;
extracted = fopen(i->path.c_str(),"wb");
fwrite(i->data,i->size,1,extracted);
fclose(extracted);
++i;
return 0;
int main()
std::list<single_element> all;
std::string root = "Test";
pack(root,&all);
save(root,all);
load(root,&all);
extract(root,all);
return 0;
【问题讨论】:
为什么要提供这么多不相关的信息,而不是提供代码示例来显示您的问题?I did not want to use boost or minizip because it seems too much for something so easy
如果这很容易,你为什么会遇到麻烦?
也许他认为 boost 库太多,而他认为应该是一项微不足道的任务?
TEST~1
vs. TESTąę
暗示读取文件名的代码限制为 8.3 个字符 - 可能是一些旧的库代码。最好展示你的代码。
在哪个操作系统和哪个文件系统上?标准 C 不知道目录....
【参考方案1】:
我有 3 条建议:
1)
如果要遍历目录结构查找所有文件和目录并读取其内容,可以使用文件树遍历功能。
#include <stdio.h>
#include <ftw.h>
int callback_function(const char *name, const struct stat *s, int type)
// Here you can read the filename and contents of a file and save it in your own format.
printf("%s\n", name);
// type can have one of the following values and meaning:
// FTW_F File
// FTW_D Directory
// FTW_DNR Directory not readable
// FTW_SL Symbolic link
// FTW_NS The object is NOT a symbolic link and is one for which stat() could not be executed
return 0;
int main()
ftw(".", callback_function, 1);
return 0;
2)
使用 libtar http://www.feep.net/libtar/ 以标准文件格式将文件连接成单个文件。
3)
依赖外部可执行文件,如 tar、zip、rar 等,并使用 system() 函数调用来调用它。
【讨论】:
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