加载文本文档并根据重复单词的数量对它们进行排名的 Java 程序 - 不断获取文件未找到错误
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【中文标题】加载文本文档并根据重复单词的数量对它们进行排名的 Java 程序 - 不断获取文件未找到错误【英文标题】：Java Program that loads text documents and ranks them based on amount of repeated words - keep getting file not found error 【发布时间】：2022-01-10 07:03:09 【问题描述】：我正在创建一个 Java 程序，它可以加载不同的文本文档（在本例中，是四本不同小说的第一章左右），然后按照词汇排名的顺序将它们打印出来。换句话说，它们是根据章节中单词重复的次数来排名的。这个程序包括三个类：
hw5.java:
public class hw5
//main method
public static void main(String[] args) throws FileNotFoundException
//stores user entered data
String userInput = "";
//Scanner class object created
Scanner in = new Scanner(System.in);
System.out.println("Write a file name to include in your ranks, '?' to list ranks, and ! to exit program");
//Accepts user choice and loops while user choice is not "!"
while(!userInput.equals("!"))
System.out.print(">> ");
userInput = in.next();
//if user choice is "!", the program stops
if (userInput.equals("!"))
System.out.println("\nGood Bye :)");
//if user choice is "?", the program stops
else if(userInput.equals("?"))
//calls printRanks() method from StoryRanker to display file name and word count
StoryRanker.printRanks();
//Otherwise it's a file name
else
//Uses default constructor to pass the file name to Story class
Story myStory = new Story(userInput);
//if getWordCount method from Story is greater than 0, call addStory() method from StoryRanker and pass the object
if(myStory.getWordCount()>0)
StoryRanker.addStory(myStory);
Story.java：
public class Story
//stores word count
int wordCount;
//stores file name
String title;
//Scanner class object for reading file
Scanner fileRead;
//file object
File file;
//Constructor for receiving file name
Story(String fileName)
//initializes file object by file name
file = new File(fileName);
//extracts file extension
title = fileExtension(fileName);
//Method that returns number of words in the file
int getWordCount()
//try block
try
//file is read
fileRead = new Scanner(file);
//Checks for data
while(fileRead.hasNextLine())
//Word is read
fileRead.next();
//wordCount increases
wordCount++;
//File is closed
fileRead.close();
//Catch for FileNotFoundException
catch (FileNotFoundException e)
System.out.println("File Not Found");
//returns wordCount
return wordCount;
//method that returns file name from complete file name with extension
static String fileExtension(String str)
//null case
if(str == null)
return null;
//gets position of last "."
int pos = str.lastIndexOf(".");
//if there's no "." return the string as it is
if(pos == -1)
return str;
//returns string up to "."
return str.substring(0,pos);
和 StoryRanker.java：
class Data
//Stores file name
String fileName;
//stores word count
int wordCount;
class MyNewStack
//stores 100 file names and word count
Data myData[] = new Data[100];
//points to top
int top;
//stores length
int length;
//default constructor
void MyNewStack()
top = -1;
length = 0;
//Returns false if top = -1, but otherwise returns true
boolean isEmpty()
if(top == -1)
return false;
else
return true;
//method pushes object to stack
void push (Data d)
//Checks is stack is full
if (top == 99)
System.out.println("Stack is full");
//if stack isn't full
else
//increases top position of stack by one
++top;
//instantiates the array top index position
myData[top] = new Data();
//Stores file name and word count
myData[top].fileName = d.fileName;
myData[top].wordCount = d.wordCount;
//increases length by one
length++;
//method to pop the stack top position
Data pop()
//if stack top is less than zero, the stack is empty
if(top<0)
System.out.println("Stack Underflow.");
return null;
//Otherwise, decrease length by one and return stack top position object
else
length--;
return myData[top--];
//method to return stack a position
Data peek(int a)
//if stack top is less than zero, the stack is empty
if(top < 0)
System.out.println("Stack underflow.");
return null;
//otherwise returns stack a position object
else
return myData[a];
//establish StoryRanker public class
public class StoryRanker
//MyNewStack class objects
static MyNewStack stack1 = new MyNewStack();
static MyNewStack stack2 = new MyNewStack();
//Data class object
static Data d = new Data();
//Method to add file name and word count to stack
public static void addStory(Story myStory)
//Extract data from myStory and store it in Data object
d.fileName = myStory.title;
d.wordCount = myStory.wordCount;
//checks if stack is not empty
if(!stack1.isEmpty())
//Push object to first stack
stack1.push(d);
else
//loops until first stack top position
for(int a = 0; a <= stack1.top; a++)
//if stack word count is less than current file word count
if(stack1.peek(a).wordCount < myStory.wordCount)
//Push object to second stack
stack2.push(stack1.pop());
//puush current object to first stack
stack1.push(d);
//for loop until second stack top position
for(int a = 0; a < stack2.length; a++)
//extracts second stack object and pushes it to first stack
stack1.push(stack2.pop());
//Method to display first stack contents
public static void printRanks()
//loops until first stack top position
for(int a = 0; a <= stack1.top; a++)
System.out.println((a+1)+ ": " + stack1.peek(a).fileName + ", size = " + stack1.peek(a).wordCount);
这是运行程序时的样子：
Write a file name to include your ranks, '?' to list ranks, and ! to exit program
>>the_boy_who_lived.txt
>>?
1: the_boy_who_lived, size= 392.
>>dracula_chapter1.txt
>>?
1: dracula_chapter1, size= 1309.
2: the_boy_who_lived, size= 392.
>>!
Good Bye :)
我遇到的问题是，每当我输入我正在使用的文件之一时，它都会不断返回“找不到文件”。我尝试输入整个地址，包括末尾的 .txt，但似乎没有任何进展。有没有人可以帮助我？
【问题讨论】：
只是文件名的路径是“相对路径”——操作系统在当前程序的工作目录中查找文件。因此，如果您只想输入文件名，则需要确保它与您启动程序时所在的目录相同。 【参考方案1】：Story(String fileName)
//initializes file object by file name
String directory = "C:\\Users\\stlp\\IdeaProjects\\StoryCount\\src.\\" + fileName + ".txt";
file = new File(directory);
//extracts file extension
title = fileExtension(fileName);
将目录的第一个字符串替换为您的实际绝对目录。确保包括双斜杠。输入文件名时，只需输入名称即可，因为 .txt 已附加。
【讨论】：
这绝对有帮助。唯一的问题是现在我遇到了一个问题，它不允许我加载我用于该程序的四个文本文件中的两个。 你能澄清一下你的文本文件目录是什么样的吗？ C:\\Users\\myname\\eclipse-workspace\\program\\src\\excerpt_from_the_winds_of_winter.txt 您是否仍然收到未找到文件的异常或其他错误？以上是关于加载文本文档并根据重复单词的数量对它们进行排名的 Java 程序 - 不断获取文件未找到错误的主要内容，如果未能解决你的问题，请参考以下文章