如何只用我的 len() 打印我的字典中的项目一次而不打印数字 9、9 次 [关闭]

Posted 2023-02-19

【中文标题】如何只用我的 len() 打印我的字典中的项目一次而不打印数字 9、9 次 [关闭]

【英文标题】：How to print out my items in my dictionary only once with my len() without it printing the number 9, 9 times [closed]

【发布时间】：2022-01-19 22:08:46

【问题描述】：

如何只用我的 len() 将我的字典中的项目打印一次，而不打印数字 9、9 次。请帮帮我，我想不通。

这是我的代码：

d = 
  "Brand: ": "Honda",
  "model: ": "Pilot",
  "year: ": 2021

for x in d:
  print(len(d))

ls = ["Chevrolet", "Dodge", "Ford", "Honda", "Jeep", "Nissan", "Saturn", "Subaru", "Tesla", "Toyota"]
for x in ls:
  print(len(ls))

ri = raw_input("Enter 'd', if you want to see a dictionary for a car. Or enter 'ls', if you want to see a list of cars: ")

def cars(d, ls):
  print ri
  if ri == 'd':
    print d
  if ri == 'ls':
    print ls

cars(d, ls)

【问题讨论】：

喜欢print(d)?

你为什么写for x in d: print(len(d))？这确实可以满足您的要求。

为什么该代码混合了 python2 和 python3 代码？这是不可能的；）

将for x in d: print(len(d)) 更改为for x in d.values(): print(x) `

也许你想要的是for x in ls: print(len(x))

【参考方案1】：

for x in d: print(len(d))

你有一个 for 循环正在运行，它正在多次打印，将其切换为 print(len(d)) 即可修复它

【参考方案2】：

您正在打印len，这就是您所看到的，更改为您迭代的变量

d = "Brand: ": "Honda", "model: ": "Pilot", "year: ": 2021
for key, val in d.items():
    print(key, val)

ls = ["Chevrolet", "Dodge", "Ford", "Honda", "Jeep", "Nissan", "Saturn", "Subaru", "Tesla", "Toyota"]
for x in ls:
    print(x)

【参考方案3】：

您的需求未明确。这是我从您的需求中理解的实现。

d = 
  "Brand: ": "Honda",
  "model: ": "Pilot",
  "year: ": 2021


ls = ["Chevrolet", "Dodge", "Ford", "Honda", "Jeep", "Nissan", "Saturn", "Subaru", "Tesla", "Toyota"]

ri = raw_input("Enter 'd', if you want to see a dictionary for a car. Or enter 'ls', if you want to see a list of cars: ")

def cars(d, ls):
  print(ri)
  if ri == 'd':
    print(d)
  if ri == 'ls':
    print(len(ls))
    for l in ls:
        print(l)

cars(d, ls)