“致命错误：在 ajax 中尝试更新数据库时调用 boolean() 上的成员函数 execute()”
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【中文标题】“致命错误：在 ajax 中尝试更新数据库时调用 boolean() 上的成员函数 execute()”【英文标题】："Fatal error: Call to a member function execute() on boolean() "when trying to update database in ajax 【发布时间】：2019-07-24 06:57:27 【问题描述】：下面是我在网上找到的 index.php 文件。
我已经编写了所有代码，一切正常，除了表单没有提交并且没有显示“注册成功完成”的警报消息。
相反，我得到了这个错误：
致命错误：在线调用 boolean() 上的成员函数 execute() 25
我还在名为“charu”的数据库中创建了一个 tbl_register 表，该表包含 5 个空值列。
HTML：
<html>
<head>
<title>PHP Form Validation using Parsleys.js Library</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.0/jquery.min.js"></script>
<script src="http://parsleyjs.org/dist/parsley.js"></script>
</head>
<body>
<div class="container">
<br />
<br />
<br />
<div class="table-responsive">
<h3 align="center">PHP Form Validation using Parsleys.js Library</h3><br />
<div class="box">
<form id="validate_form">
<div class="row">
<div class="col-xs-6">
<div class="form-group">
<label>First Name</label>
<input type="text" name="first_name" id="first_name" placeholder="Enter First Name" required data-parsley-pattern="^[a-zA-Z]+$" data-parsley-trigger="keyup" class="form-control" />
</div>
</div>
<div class="col-xs-6">
<div class="form-group">
<label>Last Name</label>
<input type="text" name="last_name" id="last_name" placeholder="Last Name" required data-parsley-pattern="^[a-zA-Z ]+$" data-parsley-trigger="keyup" class="form-control" />
</div>
</div>
</div>
<div class="form-group">
<label for="email">Email</label>
<input type="text" name="email" id="email" placeholder="Email" required data-parsley-type="email" data-parsley-trigger="keyup" class="form-control" />
</div>
<div class="form-group">
<label for="password">Password</label>
<input type="password" name="password" id="password" placeholder="Password" required data-parsley-length="[8, 16]" data-parsley-trigger="keyup" class="form-control" />
</div>
<div class="form-group">
<label for="cpassword">Confirm Password</label>
<input type="password" name="confirm_password" id="confirm_password" placeholder="Confirm Password"data-parsley-equalto="#password" data-parsley-trigger="keyup" required class="form-control" />
</div>
<div class="form-group">
<label for="cpassword">Website</label>
<input type="text" id="website" name="website" placeholder="Website URL" data-parsley-type="url" data-parsley-trigger="keyup" class="form-control" />
</div>
<div class="form-group">
<div class="checkbox">
<label><input type="checkbox" id="check_rules" name="check_rules" required /> I Accept the Terms & Conditions</label>
</div>
</div>
<div class="form-group">
<input type="submit" id="submit" name="submit" value="Submit" class="btn btn-success" />
</div>
</form>
</div>
</div>
</div>
</body>
</html>
JQuery：
<script>
$(document).ready(function()
$('#validate_form').parsley();
$('#validate_form').on('submit', function(event)
event.preventDefault();
if($('#validate_form').parsley().isValid())
$.ajax(
url:"action.php",
method:"POST",
data:$(this).serialize(),
beforeSend:function()
$('#submit').attr('disabled','disabled');
$('#submit').val('Submitting...');
,
success:function(data)
$('#validate_form')[0].reset();
$('#validate_form').parsley().reset();
$('#submit').attr('disabled',false);
$('#submit').val('Submit');
alert(data);
);
);
);
</script>
action.php 文件：
<?php
sleep(5);
if(isset($_POST['first_name']))
$connect = new mysqli("localhost", "root", "","charu");
$data = array(
':first_name' => $_POST['first_name'],
':last_name' => $_POST['last_name'],
':email' => $_POST['email'],
':password' => $_POST['password'],
':website' => $_POST['website']
);
$query = "
INSERT INTO tbl_register
(first_name, last_name, email, password, website)
VALUES (:first_name, :last_name, :email, :password, :website)
";
$statement = $connect->prepare($query);
if($statement->execute($data))
echo 'Registration Completed Successfully...';
?>
【问题讨论】：
【参考方案1】：你应该使用bind_params();
替换这个
$data = array(
':first_name' => $_POST['first_name'],
':last_name' => $_POST['last_name'],
':email' => $_POST['email'],
':password' => $_POST['password'],
':website' => $_POST['website']
);
$query = "
INSERT INTO tbl_register
(first_name, last_name, email, password, website)
VALUES (:first_name, :last_name, :email, :password, :website)
";
$statement = $connect->prepare($query);
if($statement->execute($data))
echo 'Registration Completed Successfully...';
with
$query = "
INSERT INTO tbl_register
(first_name, last_name, email, password, website)
VALUES (?,?,?,?,?)
";
$statement = $connect->prepare($query);
$statement->bind_param('sssss',$_POST['first_name'],$_POST['last_name'],$_POST['email'],$_POST['password'],$_POST['website']);
//here 's' in sssss stands for string and all your parameters are string so five 's' are added
if($statement->execute())
echo 'Registration Completed Successfully...';
【讨论】：
非常感谢您的帮助。它工作得很好:)【参考方案2】：您必须将参数绑定到 SQL 查询并告诉数据库参数是什么。
// prepare sql and bind parameters
$query = "
INSERT INTO tbl_register
(first_name, last_name, email, password, website)
VALUES (:first_name, :last_name, :email, :password, :website)
";
$statement = $connect->prepare($query);
$statement->bindParam(':first_name', $_POST['first_name']);
$statement->bindParam(':last_name', $_POST['last_name']);
$statement->bindParam(':email', $_POST['email']);
$statement->bindParam(':password', $_POST['password']);
$statement->bindParam(':website', $_POST['website']);
if($statement->execute())
echo 'Registration Completed Successfully...';
【讨论】：
【参考方案3】：您必须自己打印错误才能查看实际原因。 做这个。在 if 语句之后
else
echo $connect->error;
echo $statement->error;
您可以复制和使用代码。我已经修改了。它有效。
if(isset($_POST['first_name']))
$connect = new mysqli("localhost", "root", "","charu");
$first_name = $_POST['first_name'];
$last_name = $_POST['last_name'];
$email = $_POST['email'];
$password = $_POST['password'];
$website = $_POST['website'];
$query = "
INSERT INTO tbl_register
(first_name, last_name, email, password, website)
VALUES (?, ?, ?, ?, ?)
";
if(!$statement = $connect->prepare($query))
echo $connect->error;
echo $statement->error;
else
$statement->bind_param("sssss", $first_name, $lastname, $email, $password, $website);
If(statement->execute())
echo 'Registration Completed Successfully...';
免费询问并让我知道反馈。
【讨论】：
我已复制此内容并替换为之前的内容，现在它显示“第 32 行解析错误语法错误，其中执行方法必须起作用。现在要做什么 第 32 行是哪一行？ 我以为你说的是 PDO。将 bindParam 更改为 bind_param("s", $firstname)以上是关于“致命错误：在 ajax 中尝试更新数据库时调用 boolean() 上的成员函数 execute()”的主要内容，如果未能解决你的问题，请参考以下文章