Codeigniter 上的动态相关下拉列表国家和州

Posted 2023-05-09

【中文标题】Codeigniter 上的动态相关下拉列表国家和州

【英文标题】：Dynamic Dependent Dropdown List Country and State on Code Igniter

【发布时间】：2019-05-25 23:38:02

【问题描述】：

我正在开发在 CodeIgniter 上使用动态或依赖下拉列表的项目。这是我的菜鸟逻辑，视图中的国家值传递给模型，然后模型从视图中获取具有相同国家值的状态数据，然后控制器从模型中获取状态数据并将其再次传递给视图。问题是状态下拉列表什么也没显示。 对不起，我是编码新手。

//This is the Controllers (Pkl.php)
$data['all_country'] = $this->Server_Model->get_country_model();
$data['all_state'] = $this->Server_Model->get_state_model();
$this->load->view('contents/page_dashboard', $data);

//This is the Models (Server_Model.php)
function get_country_model()
            $db_jarlap = $this->load->database('gis_bali', TRUE);
            $db_jarlap->select("*");
            $db_jarlap->from("country");
            $que = $db_jarlap->get();
            return $que->result();
        
function get_state_model()
            $kakakoko = filter_input(INPUT_POST, 'country_id');
            $db_jarlap = $this->load->database('gis_bali', TRUE);
            $db_jarlap->select("*");
            $db_jarlap->from("state");
            $db_jarlap->where(" id_country = $kakakoko ");
            $que = $db_jarlap->get();
            return $que->result();
        

//This is the Views Content (page_dashboard.php)
<script src="<?php echo base_url() ?>resources/js/jquery-3.3.1.min.js"</script>
<script>
            $(document).ready(function()
            $('#formCountry').change(function()
                  var country_id = $(this).val();

                  $.ajax(
                            url: "<?php echo base_url() ?            >application/models/Server_Model.php",
                        method: "POST", 
                        data: country_id:country_id, 
                        success: function(data)  
                        $('#formState').html(data);
                                            
                                    );
                                );
                            );
</script>

<select name="formCountry" id="formCountry">
<?php foreach($all_country as $semua_country): ?>
<option value="<?php echo $semua_country->id_country; ?>"><?php echo     $semua_country->nama_country; ?></option>
<?php endforeach; ?>
</select>

<select name="formState" id="formState" >
<?php foreach($all_state as $semua_state): ?>
<option value="<?php echo $semua_state->id_state; ?>"><?php echo $semua_state->nama_state; ?></option>
<?php endforeach; ?>
</select>

感谢您的帮助。

【参考方案1】：

你不应该直接调用模型，而是调用Pkl控制器，我假设你在Pkl控制器上使用index()方法：

$(document).ready(function () 
    $('#formCountry').change(function () 
        var country_id = $(this).val();

        $.ajax(
            url: "<?php echo base_url() ?>pkl", // using Pkl controller
            method: "POST",
            data: 
                country_id: country_id
            ,
            success: function (data) 
                $('#formState').html(''); // empty the select option element
                $.each(data, function() // format each option returned from Pkl controller
                    $("#formState").append('<option value="'+ this.id_state +'">'+ this.nama_state +'</option>');
                );
            
        );
    );
);