下拉列表设置从数据库中选择的值
Posted
技术标签:
【中文标题】下拉列表设置从数据库中选择的值【英文标题】:Dropdown list set put selected value from database 【发布时间】:2016-07-03 11:41:21 【问题描述】:我正在尝试创建一个下拉菜单,用于选择存储在数据库中的值。现在,代码创建了一个下拉列表,其中第一个选项被选中。我已经阅读了几个教程,并尝试应用它们,但我无法让它工作。我希望有人可以提供帮助。
<div class="form-group">
<label>Up-to-Date</label>
<select class="form-control" name="uptodate"/>
<option value="Ja">Ja</option>
<option value="Nee">Nee</option>
</select>
</div>
完整代码:
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
session_start();
include("../includes/connect.php");
if (isset($_SESSION['logged_in']))
if(isset($_POST['btnSlaOp']))
$id=$_POST['id'];
$uitgeleend=$_POST['uitgeleend'];
$nr=$_POST['nr'];
$model=$_POST['model'];
$serienummer=$_POST['serienummer'];
$capaciteit=$_POST['capaciteit'];
$uptodate=$_POST['uptodate'];
$persoon=$_POST['persoon'];
$datumuitgeleend=$_POST['datumuitgeleend'];
$datumretour=$_POST['datumretour'];
$opmerking=$_POST['opmerking'];
$sql="UPDATE ipads SET uitgeleend='$uitgeleend', nr='$nr', model='$model', serienummer='$serienummer', capaciteit='$capaciteit', uptodate='$uptodate', persoon='$persoon', datumuitgeleend='$datumuitgeleend', datumretour='$datumretour', opmerking='$opmerking' WHERE id='$id'";
$result=$db->query($sql);
header("location:overzicht-ipads.php");
else if (isset($_POST['btnSlaOpInGs']))
$id=$_POST['id'];
$uitgeleend=$_POST['uitgeleend'];
$nr=$_POST['nr'];
$model=$_POST['model'];
$serienummer=$_POST['serienummer'];
$capaciteit=$_POST['capaciteit'];
$uptodate=$_POST['uptodate'];
$persoon=$_POST['persoon'];
$datumuitgeleend=$_POST['datumuitgeleend'];
$datumretour=$_POST['datumretour'];
$opmerking=$_POST['opmerking'];
$sql ="UPDATE ipads SET nr='$nr', model='$model', serienummer='$serienummer', capaciteit='$capaciteit', uptodate='$uptodate', persoon='$persoon', datumuitgeleend='$datumuitgeleend', datumretour='$datumretour', opmerking='$opmerking' WHERE id='$id'";
$sql .="INSERT INTO geschiedenis (SELECT * FROM ipads WHERE id='$id')";
$sql .="UPDATE ipads SET uitgeleend='Nee', persoon='', datumuitgeleend='', datumretour='', opmerking='' WHERE id='$id'";
$result=mysqli_multi_query($db, $sql);
header("location:overzicht-ipads.php");
if(isset($_GET['id']))
$id=$_GET['id'];
$sql="SELECT id, uitgeleend, nr, model, serienummer, capaciteit, uptodate, persoon, datumuitgeleend, datumretour, opmerking FROM ipads WHERE id='$id'";
$result=$db->query($sql);
$rij=$result->fetch_assoc();
$uitgeleend=$rij['uitgeleend'];
$nr=$rij['nr'];
$model=$rij['model'];
$serienummer=$rij['serienummer'];
$capaciteit=$rij['capaciteit'];
$uptodate=$rij['uptodate'];
$persoon=$rij['persoon'];
$datumuitgeleend=$rij['datumuitgeleend'];
$datumretour=$rij['datumretour'];
$opmerking=$rij['opmerking'];
include("../includes/get_header_wn.php");
?>
<h1 class="page-title">Wijzigen</h1>
<ul class="breadcrumb">
<li><a href="index.php">Home</a> </li>
<li class="active">Leen iPad <?php echo $nr ?></li>
</ul>
</div>
<form id="gegevensForm" class="col-xs-4" form method="POST" action="overzicht-ipads-edit.php">
<input type="hidden" name="id" value="<?php echo $id?>">
<div class="form-group">
<label>Uitgeleend</label>
<input type="text" class="form-control" name="uitgeleend" value="<?php echo $uitgeleend ?>" />
</div>
<div class="form-group">
<label>Nr</label>
<input type="text" class="form-control" name="nr" value="<?php echo $nr ?>" />
</div>
<div class="form-group">
<label>Model</label>
<input type="text" class="form-control" name="model" value="<?php echo $model ?>" />
</div>
<div class="form-group">
<label>Serienummer</label>
<input type="text" class="form-control" name="serienummer" value="<?php echo $serienummer ?>" />
</div>
<div class="form-group">
<label>Capaciteit</label>
<input type="text" class="form-control" name="capaciteit" value="<?php echo $capaciteit ?>" />
</div>
<div class="form-group">
<label>Up-to-Date</label>
<select class="form-control" name="uptodate"/>
<option value="Ja">Ja</option>
<option value="Nee">Nee</option>
</select>
</div>
<div class="form-group">
<label>Persoon</label>
<input type="text" class="form-control" name="persoon" value="<?php echo $persoon ?>" />
</div>
<div class="form-group">
<label>Datum uitgeleend</label>
<input type="text" id="datepicker" class="form-control" name="datumuitgeleend" value="<?php echo $datumuitgeleend ?>" />
</div>
<div class="form-group">
<label>Datum retour</label>
<input type="text" id="datepicker1" class="form-control" name="datumretour" value="<?php echo $datumretour ?>" />
</div>
<div class="form-group">
<label for="comment">Opmerking</label>
<textarea class="form-control" rows="5" id="comment" name="opmerking" /><?php echo $opmerking ?></textarea>
</div>
<button class="btn btn-primary pull-right" name="btnSlaOp" input type="submit"><i class="fa fa-save"></i> Opslaan</button>
<a href="overzicht-ipads.php"><input type="button" name="btnCancel" value="Annuleer" class="btn btn-primary pull-left"></a>
<button class="btn btn-primary pull-middle" name="btnSlaOpInGs" type="submit"><i class="fa fa-save"></i> Opslaan & Archiveren</button>
<?php
include('../includes/get_footer.php');
?>
</form>
<?php
else
header("location:overzicht-ipads.php");
?>
【问题讨论】:
您如何从数据库中检索值?获得价值后,您可以使用$('select.form-control').val(databaseValue);
我还在学习中,我把整个代码放在上面了。如何在我的代码中应用它?
【参考方案1】:
php:if($selectedVal == "yourVal") echo "selected";
例如:
<div class="form-group">
<label>Up-to-Date</label>
<select class="form-control" name="uptodate"/>
<option value="Ja" <?php if($selectedVal == "Ja") echo "selected";?>>Ja</option>
<option value="Nee" <?php if($selectedVal == "Nee") echo "selected";?>>Nee</option>
</select>
</div>
编辑:在您的情况下,将 $selectedVal
替换为 $uptodate
【讨论】:
以上是关于下拉列表设置从数据库中选择的值的主要内容,如果未能解决你的问题,请参考以下文章
根据下拉列表中选择的值设置 datetimepicker 格式