如何从 Select2 Widget Yii2 将多个值保存到数据库

Posted 2023-05-07

【中文标题】如何从 Select2 Widget Yii2 将多个值保存到数据库

【英文标题】：How to save multiple values to database from Select2 Widget Yii2

【发布时间】：2017-01-08 00:19:37

【问题描述】：

我正在使用kartik - yii2-widget-select2 来允许在表单中创建时选择多个选项。

我想根据在 select2 小部件中选择的选项数量向数据库输入两行或多行。

表单中的 select2 小部件如下。

<?= $form->field($model, 'Assign_task_to')->widget(Select2::classname(), 
//$data = ArrayHelper::map(Employee::find()->all(),'Employee_ID','employee_name'),
[
'data' => ArrayHelper::map(Employee::find()->all(),'Employee_ID','employee_name'),
'language' => 'en',
'options' => ['placeholder' => 'Select an employee ...', 'multiple' => true],
'pluginOptions' => [
    'allowClear' => true
],
]); ?>

控制器actionCreate在下面。

public function actionCreate()


    // set default values
    $empModel = new Tasksemp();
    $model = new Tasks();
    $model->priotiy_level = 'medium';
    $model->start_date = date('Y-m-d'); //to get default date
    if ($model->load(Yii::$app->request->post())) 


        //Check if field input is empty

        $model->file = UploadedFile::getInstance($model, 'upload_documents');


        if($model->file)
        
            //get instance of uploaded file
            $fName = time();
            $model->file = UploadedFile::getInstance($model, 'upload_documents');
            $model->file->saveAs('uploads/'.$fName.'.'.$model->file->extension);

            $model->upload_documents = 'uploads/'.$fName.'.'.$model->file->extension;
        



        $model->save();

        //to save in task_emp table

            $empModel->Task_ID = $model->Task_ID;   
            $empModel->Employee_ID = $model->Assign_task_to;  //<---want to save multiple employee IDs with the same Task ID (multiple rows)
            $empModel->save(false);
            return $this->redirect(['view', 'id' => $model->Task_ID]);      

     else 
        return $this->render('create', [
            'model' => $model,
            'emp' => $empModel,
        ]);
    

如何将两个或多个值保存到数据库？如何迭代或如何知道选择了多少个值以便使用循环插入？

有人可以帮助我或提供任何建议吗？谢谢

【参考方案1】：

添加foreach 将项目保存到数据库

 public function actionCreate()
    

        // set default values
        $empModel = new Tasksemp();
        $model = new Tasks();
        $model->priotiy_level = 'medium';
        $model->start_date = date('Y-m-d'); //to get default date
        if ($model->load(Yii::$app->request->post())) 


            //Check if field input is empty

            $model->file = UploadedFile::getInstance($model, 'upload_documents');


            if($model->file)
            
                //get instance of uploaded file
                $fName = time();
                $model->file = UploadedFile::getInstance($model, 'upload_documents');
                $model->file->saveAs('uploads/'.$fName.'.'.$model->file->extension);

                $model->upload_documents = 'uploads/'.$fName.'.'.$model->file->extension;
            


            $model->save();

            //to save in task_emp table

               $array=$model->Assign_task_to; 
               foreach ($array as $value)  
                   $empModel = new Tasksemp(); 
                   $empModel->Task_ID = $model->Task_ID; 
                   $empModel->Employee_ID = $value; 
                   $empModel->save(false); 
                  

                return $this->redirect(['view', 'id' => $model->Task_ID]);      

         else 
            return $this->render('create', [
                'model' => $model,
                'emp' => $empModel,
            ]);
        
    

【讨论】：

你好，Jithin。我完全按照你说的尝试了，但它不起作用。它仍然只向数据库取一个值。

ur Assign_task_to 字段是否为整数？

是的，它是整数。

更改为 varchar 或 text 类型并更新模型

但它是一个 ID。不过我会试试你说的