想将listview数据发送到android中的另一个活动

Posted 2023-04-19

【中文标题】想将listview数据发送到android中的另一个活动

【英文标题】：want to send listview data to another activity in android

【发布时间】：2015-04-09 00:31:21

【问题描述】：

package com.example.selflistview;

import java.io.IOException;
import java.util.ArrayList;
import java.util.List;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.os.StrictMode;
import android.util.Log;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.TextView;
import android.widget.Toast;

public class MainActivity extends Activity 
 TextView text;
    @Override
    public void onCreate(Bundle savedInstanceState) 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
        StrictMode.setThreadPolicy(policy);

        connect();
    
    private void connect() 
      String data;
      List<String> r = new ArrayList<String>();
      ArrayAdapter<String>adapter=new ArrayAdapter<String>(getApplicationContext(), android.R.layout.simple_list_item_1,r);
      ListView list=(ListView)findViewById(R.id.listView1);
        try 
            DefaultHttpClient client = new DefaultHttpClient();
            HttpGet request = new HttpGet("http://localhost/listview.php");
            HttpResponse response = client.execute(request);
            HttpEntity entity=response.getEntity();
            data=EntityUtils.toString(entity);
            Log.e("STRING", data);
            try 

       JSONArray json=new JSONArray(data);
       for(int i=0;i<json.length(); i++)
       
        JSONObject obj=json.getJSONObject(i);
        String name=obj.getString("name");
        String year=obj.getString("year");
        String age=obj.getString("age");
        Log.e("STRING", name);
        r.add(name);
        //r.add(year);
        //r.add(age);
        list.setAdapter(adapter);

        list.setOnItemClickListener(new OnItemClickListener() 

            @Override
            public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,long arg3) 
                // TODO Auto-generated method stub
                //final String item = (String) arg0.getItemAtPosition(arg2);

                Toast.makeText(getBaseContext(), "arg2 : "+arg2, Toast.LENGTH_SHORT).show();
                Intent view_det = new Intent(getBaseContext(),ViewDetail.class);
                view_det.putExtra("position",arg2);
                startActivity(view_det);

            
        );
       

       catch (JSONException e) 
       // TODO Auto-generated catch block
       e.printStackTrace();
      

         catch (ClientProtocolException e) 
            Log.d("HTTPCLIENT", e.getLocalizedMessage());
         catch (IOException e) 
            Log.d("HTTPCLIENT", e.getLocalizedMessage());
         
    

我想将年份、姓名和年龄发送到另一个活动，我能够获得意向职位，但不能获得其他值。请帮忙...

我可以在列表中看到这些值，但无法在意图部分调用。

您的帮助将不胜感激..

【问题讨论】：

你可以从你的适配器那里得到这个。并且不要使用 list.setAdapter(adapter);在每次迭代中。设置一次适配器并使用 notifyDataSetChanged();

先生，您能帮帮我吗..，您可以帮我修改代码吗..？我是安卓新手

【参考方案1】：

这可能会有所帮助

Public class MainActivity extends Activity 
 TextView text;
List<String> r; //define list here
    @Override
    public void onCreate(Bundle savedInstanceState) 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
        StrictMode.setThreadPolicy(policy);
        connect();


    
    private void connect() 
      String data;
      r = new ArrayList<String>();
        try 
            DefaultHttpClient client = new DefaultHttpClient();
            HttpGet request = new HttpGet("http://localhost/listview.php");
            HttpResponse response = client.execute(request);
            HttpEntity entity=response.getEntity();
            data=EntityUtils.toString(entity);
            Log.e("STRING", data);
            try 

       JSONArray json=new JSONArray(data);
       for(int i=0;i<json.length(); i++)
       
        JSONObject obj=json.getJSONObject(i);
        String name=obj.getString("name");
        String year=obj.getString("year");
        String age=obj.getString("age");
        Log.e("STRING", name);
        r.add(name);
        //r.add(year);
        //r.add(age);
    
    ArrayAdapter<String>adapter=new ArrayAdapter<String>(getApplicationContext(), android.R.layout.simple_list_item_1,r);
        ListView list=(ListView)findViewById(R.id.listView1);
    list.setAdapter(adapter);

        list.setOnItemClickListener(new OnItemClickListener() 

            @Override
            public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,long arg3) 
                // TODO Auto-generated method stub
                //final String item = (String) arg0.getItemAtPosition(arg2);

                Toast.makeText(getBaseContext(), "arg2 : "+arg2, Toast.LENGTH_SHORT).show();
                Intent view_det = new Intent(getBaseContext(),ViewDetail.class);
                view_det.putExtra("position",arg2);
        String name = r.get(arg2);//add this line to get name from the arraylist of that position
        JSONObject obj=json.getJSONObject(arg2); //you can get other two values from json object
            String year=obj.getString("year");
            String age=obj.getString("age");
        view_det.putExtra("name",name); //add this
        view_det.putExtra("year",year); //add this
        view_det.putExtra("age",age); //add this
                startActivity(view_det);

            
        );
       catch (JSONException e) 
       // TODO Auto-generated catch block
       e.printStackTrace();
      

         catch (ClientProtocolException e) 
            Log.d("HTTPCLIENT", e.getLocalizedMessage());
         catch (IOException e) 
            Log.d("HTTPCLIENT", e.getLocalizedMessage());
         
    

【讨论】：

他也想得到名字和年份，也许你可以修改你的代码从JSON数组中得到这些？

使用位置从json数组中获取json对象，并得到最终编辑中所做的年份和年龄