如何反序列化 IPGeoLocation API 返回的 json 并在 .chtml 视图中使用

Posted 2023-04-12

【中文标题】如何反序列化 IPGeoLocation API 返回的 json 并在 .chtml 视图中使用

【英文标题】：How to deserialize json returned by IPGeoLocation API and Use it in .chtml View

【发布时间】：2020-01-04 05:35:26

【问题描述】：

我正在尝试编写一个代码来获取特定 IP 的数据，我使用了这个名为 Free IP GeoLocation API 的 API

https://rapidapi.com/jkosgei/api/free-ip-geolocation

我已尝试列出一些数据并尝试对其进行反序列化，但它没有返回任何内容。

"\n    \"ip\": \"72.255.29.148\",\n    \"is_eu\": false,\n    \"city\": \"Karachi\",\n    \"region\": \"Sindh\",\n    \"region_code\": \"SD\",\n    \"country_name\": \"Pakistan\",\n    \"country_code\": \"PK\",\n    \"continent_name\": \"Asia\",\n    \"continent_code\": \"AS\",\n    \"latitude\": 24.9043,\n    \"longitude\": 67.0817,\n    \"asn\": \"AS9541\",\n    \"organisation\": \"Cyber Internet Services (Pvt) Ltd.\",\n    \"postal\": \"12311\",\n    \"calling_code\": \"92\",\n    \"flag\": \"https://ipdata.co/flags/pk.png\",\n    \"emoji_flag\": \"\\ud83c\\uddf5\\ud83c\\uddf0\",\n    \"emoji_unicode\": \"U+1F1F5 U+1F1F0\",\n    \"languages\": [\n        \n            \"name\": \"English\",\n            \"native\": \"English\"\n        ,\n        \n            \"name\": \"Urdu\",\n            \"native\": \"\\u0627\\u0631\\u062f\\u0648\",\n            \"rtl\": 1\n        \n    ],\n    \"currency\": \n        \"name\": \"Pakistani Rupee\",\n        \"code\": \"PKR\",\n        \"symbol\": \"PKRs\",\n        \"native\": \"\\u20a8\",\n        \"plural\": \"Pakistani rupees\"\n    ,\n    \"time_zone\": \n        \"name\": \"Asia/Karachi\",\n        \"abbr\": \"PKT\",\n        \"offset\": \"+0500\",\n        \"is_dst\": false,\n        \"current_time\": \"2019-08-31T11:03:28.948199+05:00\"\n    ,\n    \"threat\": \n        \"is_tor\": false,\n        \"is_proxy\": false,\n        \"is_anonymous\": false,\n        \"is_known_attacker\": false,\n        \"is_known_abuser\": false,\n        \"is_threat\": false,\n        \"is_bogon\": false\n    ,\n    \"count\": \"11\"\n"

我得到了反序列化的空值，这是我的 api 调用和所有控制器代码

var client = new RestClient("https://jkosgei-free-ip-geolocation-v1.p.rapidapi.com/72.255.29.148?api-key=66b8727d81306cd56a5300b77ee8d4699c85d8a87ff91d42cb62f10e");
            var request = new RestRequest(Method.GET);
            request.AddHeader("x-rapidapi-host", "jkosgei-free-ip-geolocation-v1.p.rapidapi.com");
            request.AddHeader("x-rapidapi-key", "0fd0540211msh6eb28a39b114e5ap116f3fjsn60c6c9371c26");
            IRestResponse response = client.Execute(request);
            var CachedData = response.Content;
            string json = CachedData.ToString();
            var deserialized = JsonConvert.DeserializeObject<IPList>(json);
            return View(deserialized.IPData);

这是我用过的两个模型

public class IPList
    
        public IEnumerable<IP> IPData  get; set; 
    
    public class IP
    
        public int ip  get; set; 
        public int is_eu  get; set; 
        public int city  get; set; 
        public int region  get; set; 
        public int region_code  get; set; 
        public int country_name  get; set; 
        public int country_code  get; set; 
        public int continent_name  get; set; 
        public int continent_code  get; set; 
        public int latitude  get; set; 
        public int longitude  get; set; 
        public int asn  get; set; 
        public int organisation  get; set; 
        public int postal  get; set; 
        public int calling_code  get; set; 
        public int flag  get; set; 
        public int emoji_flag  get; set; 
        public int emoji_unicode  get; set; 
        public int currency  get; set; 
    

当我运行程序时，它在变量 deserialized 和 deserialized.IPData 中返回 null

我是反序列化的新手，所以请不要评判我

【参考方案1】：

问题在于 IP 类的结构不正确。 您提供的 json 的正确结构是这样的：

public class Language

    public string name  get; set; 
    public string native  get; set; 
    public int? rtl  get; set; 


public class Currency

    public string name  get; set; 
    public string code  get; set; 
    public string symbol  get; set; 
    public string native  get; set; 
    public string plural  get; set; 


public class TimeZone

    public string name  get; set; 
    public string abbr  get; set; 
    public string offset  get; set; 
    public bool is_dst  get; set; 
    public DateTime current_time  get; set; 


public class Threat

    public bool is_tor  get; set; 
    public bool is_proxy  get; set; 
    public bool is_anonymous  get; set; 
    public bool is_known_attacker  get; set; 
    public bool is_known_abuser  get; set; 
    public bool is_threat  get; set; 
    public bool is_bogon  get; set; 


public class IP

    public string ip  get; set; 
    public bool is_eu  get; set; 
    public string city  get; set; 
    public string region  get; set; 
    public string region_code  get; set; 
    public string country_name  get; set; 
    public string country_code  get; set; 
    public string continent_name  get; set; 
    public string continent_code  get; set; 
    public double latitude  get; set; 
    public double longitude  get; set; 
    public string asn  get; set; 
    public string organisation  get; set; 
    public string postal  get; set; 
    public string calling_code  get; set; 
    public string flag  get; set; 
    public string emoji_flag  get; set; 
    public string emoji_unicode  get; set; 
    public List<Language> languages  get; set; 
    public Currency currency  get; set; 
    public TimeZone time_zone  get; set; 
    public Threat threat  get; set; 
    public string count  get; set; 

此外，我想强调一下，如果尝试反序列化您在上面提供的 JSON，因为 IPList 应该不起作用。 如果您想反序列化该 JSON，您可能需要使用它：

var deserialized = JsonConvert.DeserializeObject<IP>(json);