使用 datagridview 将列表序列化为现有的 .Json 文件
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【中文标题】使用 datagridview 将列表序列化为现有的 .Json 文件【英文标题】：Serialize list to an existing .Json file, using a datagridview 【发布时间】：2021-12-29 12:25:03 【问题描述】：我有一个反序列化的 json 文件直接输出到 DGV，并且在 DGV 中对最终用户可见。当他们完成使用软件并关闭时，我想将更新的DGV 序列化到我的 json 文件中。
当我反序列化这个json文件时，代码如下：
代码
var v = JsonConvert.DeserializeObject<ToolJson>
(File.ReadAllText(@"\testLibrary.json"));
//set DGV source to our datums
toolDataGridView.DataSource = v.Datums.Cast<IInteresting>
().ToList();
当表单关闭时，我想将 DGV 读回我的 json 文件，格式与它已经完全相同。下面是 json 文件的 sn-p。我对 DGV 所做的只是跟踪数量、最后使用的员工以及是否需要退回工具。基本上是 json 文件的 5 个新条目。***属性。
Json 文件
"data": [
"BMC": "carbide",
"Cost": 0,
"Employee": "",
"GRADE": "Mill Generic",
"Location": "",
"description": "5/8-11\"",
"geometry":
"CSP": false,
"DC": 0.433,
"HAND": true,
"LB": 2,
"LCF": 0.5,
"NOF": 4,
"NT": 1,
"OAL": 5,
"SFDM": 0.625,
"TP": 0.0909091,
"shoulder-length": 1.969,
"thread-profile-angle": 60
,
"guid": "0112c196-8a79-421d-8dda-d4aa964aa6d7",
"holder":
"description": "Maritool CAT40-ER32-2.35",
"guid": "e800051b-e2d6-4699-a2b6-dad6466a0a0c",
"last_modified": 1485790626152,
"product-id": "CAT40-ER32-2.35",
"product-link": "",
"segments": [
"height": 0.148,
"lower-diameter": 1.5,
"upper-diameter": 1.97
,
"height": 0.836,
"lower-diameter": 1.97,
"upper-diameter": 1.97
,
"height": 0.176,
"lower-diameter": 1.57,
"upper-diameter": 1.57
,
"height": 0.09,
"lower-diameter": 1.57,
"upper-diameter": 1.75
,
"height": 0.425,
"lower-diameter": 1.75,
"upper-diameter": 1.75
,
"height": 0.05,
"lower-diameter": 1.75,
"upper-diameter": 1.85
,
"height": 0.03,
"lower-diameter": 2.442,
"upper-diameter": 2.502
,
"height": 0.145,
"lower-diameter": 2.502,
"upper-diameter": 2.502
,
"height": 0.079,
"lower-diameter": 2.502,
"upper-diameter": 2.215
,
"height": 0.118,
"lower-diameter": 2.215,
"upper-diameter": 2.215
,
"height": 0.079,
"lower-diameter": 2.215,
"upper-diameter": 2.502
,
"height": 0.143,
"lower-diameter": 2.502,
"upper-diameter": 2.502
,
"height": 0.03,
"lower-diameter": 2.502,
"upper-diameter": 2.442
,
"height": 0.125,
"lower-diameter": 1.75,
"upper-diameter": 1.75
],
"type": "holder",
"unit": "inches",
"vendor": "Maritool"
,
"onHandQty": 0,
"OrderQty": 5,
"post-process":
"break-control": false,
"comment": "",
"diameter-offset": 17,
"length-offset": 17,
"live": true,
"manual-tool-change": false,
"number": 17,
"turret": 0
,
"product-id": "GMDTTM58-11UN4FL",
"product-link": "6010",
"start-values":
"presets": [
"description": "",
"f_n": 0.012242786571039,
"f_z": 0.0031,
"guid": "eac33213-4083-35b8-afe3-17bd42a249f0",
"n": 4410.76054758139,
"n_ramp": 44110,
"name": "1018",
"tool-coolant": "flood",
"use-stepdown": false,
"use-stepover": false,
"v_c": 499.9999999999994,
"v_f": 54.6934307900093,
"v_f_leadIn": 54,
"v_f_leadOut": 54,
"v_f_plunge": 54,
"v_f_ramp": 54
,
"description": "",
"f_n": 0.010769117817118,
"f_z": 0.0028,
"guid": "f35f5601-68a9-477b-b4b0-2ffeedb3bef1",
"n": 1764.3042190325598,
"n_ramp": 1764,
"name": "4140",
"tool-coolant": "flood",
"use-stepdown": false,
"use-stepover": false,
"v_c": 200,
"v_f": 19.7602072531647,
"v_f_leadIn": 19,
"v_f_leadOut": 19,
"v_f_plunge": 19,
"v_f_ramp": 19
,
"description": "",
"f_n": 0.012091641057817,
"f_z": 0.0031,
"guid": "b118ce46-da35-4ed6-9806-b98e05ffe077",
"n": 2646.45632854884,
"n_ramp": 2646,
"name": "Tool Steel",
"tool-coolant": "flood",
"use-stepdown": false,
"use-stepover": false,
"v_c": 300,
"v_f": 32.8160584740056,
"v_f_leadIn": 32,
"v_f_leadOut": 32,
"v_f_plunge": 32,
"v_f_ramp": 32
,
"description": "",
"f_n": 0.01118476797848,
"f_z": 0.0028,
"guid": "0e1767f5-b0ef-422f-b49d-6cb8c3eb06ed",
"n": 3308.0704106860494,
"n_ramp": 3308,
"name": "Stainless Steel",
"tool-coolant": "flood",
"use-stepdown": false,
"use-stepover": false,
"v_c": 375,
"v_f": 37.0503885996837,
"v_f_leadIn": 37,
"v_f_leadOut": 37,
"v_f_plunge": 37,
"v_f_ramp": 37
]
,
"stockQty": 5,
"type": "thread mill",
"unit": "inches",
"vendor": "Gorilla Mill"
,
【问题讨论】：
【参考方案1】：清除随附的文本，我想我了解困难所在，确实它是我们需要使用的一种奇异数据类型，除非 json 中只有一个列表，在这种情况下，您可以简单地将表添加到命名数据集“工具" 并对其进行序列化，我已将两者都包含在内
public partial class frmWithGrid : Form
public frmWithGrid()
InitializeComponent();
string myDynamicJSON = "Imagine your testLibraryJson loaded here or later but before next line";
DataTable convertedToTableToolData = ConvertToTableToolData(myDynamicJSON);
dataGridView1.DataSource = convertedToTableToolData;
//dataGridView1.DataMember = we're not storing it in a dataset so we can ignore this one
dataGridView1.AutoGenerateColumns = true;
//TODO: Add bla bla to setup UI of cause, suppose you're able to navigate rows etc.
DataTable ConvertToTableToolData(string jsonSource)
//TODO: Insert own convertion code here, which seems to be in place
return new DataTable(); // instead of this
private void btnUserIsDone_Click(object sender, EventArgs e)
//Obviously this shouldn't be directly in an event handler
//Either you have many lists
dynamic x = new ExpandoObject();
var editedTable = (DataTable)dataGridView1.DataSource;
//Will ignore that your OrderQty maybe wasn't originally part of data structure, because it may have been
//and it doesn't change anything with the principle, and adds needless complexity
var propertiesDictionary = (IDictionary<string, object>)x;
propertiesDictionary.Add("Tool", editedTable);
//TODO: Add other sets to json if applicable
string serialized = Newtonsoft.Json.JsonConvert.SerializeObject(x);
//or just one
var ds = new DataSet("Tool");
ds.Tables.Add(editedTable.Clone());
serialized = Newtonsoft.Json.JsonConvert.SerializeObject(ds);
【讨论】：
微软文档绑定到 SQL。这对我来说很不清楚。我怎样才能将我的数据网格表绑定到现有的数据表，然后对其进行序列化？ @JoeFisher 你决定使用数据表了吗？我建议跳过它，因为这是需要很好工作的手动部分，但会更新如何使用数据表和绑定源示例 显然你可以同时序列化tooltaSet和tooldataSet.Tables["Tool"] 我对数据网格视图进行了更改。 DGV 中的数据是否直接关联到我的数据表？我预计我需要将数据从 gridview 发送回数据表，然后序列化。也和那条序列化线一样简单吗？我不需要一个 foreach 循环来先建立一个列表？ 是的，它可以，因为您必须设置自动生成列或定义相关列，以防数据始终不清楚是哪种类型。在某些情况下，当您想要支持编辑、插入等时，拥有一个实际的绑定源可能是可行的。 Newtonsoft.Json 将表行序列化为一个元素数组，这与序列化的元素列表完全相同，所以我怀疑您不必做任何特别的事情。如果您反序列化，您可能必须根据可空字段来具体说明，这样会猜测字符串，而这往往不是正确的以上是关于使用 datagridview 将列表序列化为现有的 .Json 文件的主要内容，如果未能解决你的问题，请参考以下文章