如何从 nusoap 服务返回的 XML 反序列化对象？
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【中文标题】如何从 nusoap 服务返回的 XML 反序列化对象？【英文标题】：How can I deserialize an object from an XML returned from a nusoap service? 【发布时间】：2019-11-21 22:44:25 【问题描述】：我正在尝试从 NuSoap 服务返回的 Xml 中反序列化一个对象。 我收到了带有 WSDL 文件的服务，并尝试将它实施到我的项目中。问题是 WSDL 文件似乎损坏了。 我可以通过 SoapUI 访问 Web 服务。我也可以成功地将我的请求手动填充到 XML 表单中。作为对请求的回应，我从服务中返回了一个 Xml。
我已经为一些请求创建了类。我可以成功地序列化和发布它们并获得我的 Xml 响应。现在我的实际问题开始了。我想反序列化这个响应。
<?xml version="1.0" encoding="ISO-8859-1"?>
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:tns="urn:LicenseManagement">
<SOAP-ENV:Body>
<ns1:GetErrorCodesResponse xmlns:ns1="urn:LicenseManagement">
<RETURN xsi:type="tns:ReturnGetErrorCodes">
<RC xsi:type="xsd:int">0</RC>
<DATA xsi:type="SOAP-ENC:Array" SOAP-ENC:arrayType=":[55]">
<item xsi:type="xsd:string">OK</item>
<item xsi:type="xsd:string">database unavailable</item>
<item xsi:type="xsd:string">...</item>
</DATA>
</RETURN>
</ns1:GetErrorCodesResponse>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
我从实现其中一个响应的类开始。 我可以设法反序列化这个 XML 的 Envelope、Body、GetErrorResponse 部分。当我到达返回部分时，我得到一个空值。
我知道我可以使用 DataSet 来解决我的问题，但这需要每个响应都有一个 MappingProfile。
try
//
GetErrorCodesRequestModel request = new GetErrorCodesRequestModel()
Username = "xxx" ,
Password = "zzZzZ"
;
var res = XmlExtension.SerializeToString(request);
XmlDocument soapEnvelopeXml = CreateSoapEnvelope(res);
HttpWebRequest webRequest = CreateWebRequest(command , "POST");
InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml , webRequest);
IAsyncResult asyncResult = webRequest.BeginGetResponse(null , null);
asyncResult.AsyncWaitHandle.WaitOne();
string soapResponse = string.Empty;
using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult))
using (StreamReader rd = new StreamReader(webResponse.GetResponseStream()))
soapResponse = rd.ReadToEnd();
// this is the part where I have to deserialize the soapResponse
var deserialized = XmlExtension.Deserialize<Envelope>(soapResponse);
// deserialized contains information til RETURN
// important information missing
我的课程看起来像这个 atm。
[XmlRoot(ElementName = "RC")]
public class RC
[XmlAttribute(AttributeName = "type" , Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
public string Type get; set;
[XmlText]
public string Text get; set;
[XmlRoot(ElementName = "item")]
public class Item
[XmlAttribute(AttributeName = "type" , Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
public string Type get; set;
[XmlText]
public string Text get; set;
[XmlRoot(ElementName = "DATA")]
public class DATA
[XmlElement(ElementName = "item")]
public Item[] Item get; set;
[XmlAttribute(AttributeName = "type" , Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
public string Type get; set;
[XmlAttribute(AttributeName = "arrayType" , Namespace = "http://schemas.xmlsoap.org/soap/encoding/")]
public string ArrayType get; set;
[XmlType(AnonymousType = true , IncludeInSchema = true)]
[XmlRoot(ElementName = "RETURN", Namespace = "tns:ReturnGetErrorCodes" , IsNullable = false)]
public class RETURN
[XmlElement(ElementName = "RC")]
public RC RC get; set;
[XmlElement(ElementName = "DATA")]
public DATA DATA get; set;
[XmlAttribute(AttributeName = "type" , Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
public string Type get; set;
[XmlRoot(ElementName = "GetErrorCodesResponse" , Namespace = "urn:LicenseManagement")]
public class GetErrorCodesResponse
[XmlElement(ElementName = "RETURN")]
public RETURN RETURN get; set;
[XmlAttribute(AttributeName = "ns1" , Namespace = "http://www.w3.org/2000/xmlns/")]
public string Ns1 get; set;
[XmlRoot(ElementName = "Body" , Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
public class Body
[XmlElement(ElementName = "GetErrorCodesResponse" , Namespace = "urn:LicenseManagement")]
public GetErrorCodesResponse GetErrorCodesResponse get; set;
[XmlRoot(ElementName = "Envelope" , Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
public class Envelope
[XmlElement(ElementName = "Body" , Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
public Body Body get; set;
[XmlAttribute(AttributeName = "SOAP-ENV" , Namespace = "http://www.w3.org/2000/xmlns/")]
public string SOAPENV get; set;
[XmlAttribute(AttributeName = "xsd" , Namespace = "http://www.w3.org/2000/xmlns/")]
public string Xsd get; set;
[XmlAttribute(AttributeName = "xsi" , Namespace = "http://www.w3.org/2000/xmlns/")]
public string Xsi get; set;
[XmlAttribute(AttributeName = "SOAP-ENC" , Namespace = "http://www.w3.org/2000/xmlns/")]
public string SOAPENC get; set;
[XmlAttribute(AttributeName = "tns" , Namespace = "http://www.w3.org/2000/xmlns/")]
public string Tns get; set;
【问题讨论】：
您缺少名称空间“SOAP-ENV”的定义。 其实不是。我只是把那部分删掉了。那就编辑吧^^ 我们需要带有命名空间定义的行来提供帮助。没有命名空间，xml 就会被破坏。 我再次编辑它并添加了我得到的完整 xml 和我为反序列化创建的类。 【参考方案1】：解决这些问题的最佳方法是使用示例数据创建类并进行序列化。然后将您的序列化 xml 与原始 xml 进行比较
const string FILENAME = @"c:\temp\test.xml";
static void Main(string[] args)
Envelope envelope = new Envelope()
Body = new Body()
GetErrorCodesResponse = new GetErrorCodesResponse()
Ns1 = "urn:LicenseManagement",
RETURN = new RETURN()
Type = "tns:ReturnGetErrorCodes",
RC = new RC()
Type = "xsd:int",
Text = "0"
,
DATA = new DATA()
Type = "SOAP-ENC:Array",
ArrayType = ":[55]",
Item = new Item[]
new Item() Type = "xsd:string", Text = "OK",
new Item() Type = "xsd:string", Text = "database unavailable",
new Item() Type = "xsd:string", Text = "..."
;
XmlWriterSettings settings = new XmlWriterSettings();
settings.Indent = true;
XmlWriter writer = XmlWriter.Create(FILENAME, settings);
XmlSerializer serializer = new XmlSerializer(typeof(Envelope));
serializer.Serialize(writer, envelope);
【讨论】：
我可以用一种非常丑陋、不优雅的方式解决我的问题。 StringReader reader = new StringReader(soapResult);数据集 ds = new DataSet(); ds.ReadXml(阅读器); var deserialized = XmlExtension.Deserialize以上是关于如何从 nusoap 服务返回的 XML 反序列化对象？的主要内容，如果未能解决你的问题，请参考以下文章