当我单击不同活动的文本视图时，我想显示该特定文本视图的内容。一世

Posted 2023-03-30

【中文标题】当我单击不同活动的文本视图时，我想显示该特定文本视图的内容。一世

【英文标题】：I want to display the contents of that specific text view when i click on the text view on a different activity. I

【发布时间】：2015-11-15 14:21:18

【问题描述】：

这是我的主要活动 Collegelist，内容已经从数据库中加载，但我只显示了名称。当我点击名称时，我想在不同的活动中显示名称、地址和联系人。

public class Collegelist extends ActionBarActivity 

    HTTPConnection http;

    List<Colleges> college = new ArrayList<Colleges>();


    @Override
    protected void onCreate(Bundle savedInstanceState) 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.college_list);
        http = new HTTPConnection(getApplicationContext());
        if (http.isNetworkConnection()) 

            //String data = http.HTTPGetData("http://localhost/minorproject/show.php");
            //Toast.makeText(getApplicationContext(),data ,Toast.LENGTH_LONG).show();
            task.execute();
        
        else 


            Toast.makeText(getApplicationContext(), "check your connection",
                    Toast.LENGTH_LONG).show();
        
    


    AsyncTask<Void, Void, String> task = new AsyncTask<Void, Void, String>() 

        @Override
        protected String doInBackground(Void... params) 
            String data = http.HTTPGetData("http://localhost/college/show.php");
            return data;
        

        @Override
        protected void onPostExecute(String result) 
            super.onPostExecute(result);
            populateList(result);
            displayList();
        

        @Override
        protected void onPreExecute() 
            super.onPreExecute();

        

    ;
    protected void populateList(String result) 
        try 
            //Toast.makeText(getApplicationContext(),result,Toast.LENGTH_LONG).show();
            JSONObject jobj = new JSONObject(result);
            String res = jobj.getString("success");
            if (!res.equals("true")) 
                Toast.makeText(getApplicationContext(), "JSON Error",
                        Toast.LENGTH_LONG).show();
                return;
            
            else
            
                JSONArray data = jobj.getJSONArray("msg");
            //  Toast.makeText(getApplicationContext(),"successss",Toast.LENGTH_SHORT).show();
                for (int i = 0; i < data.length(); i++) 
                    JSONObject col = data.getJSONObject(i);
                    Colleges cg = new Colleges(col.getString("cname"), col.getString("caddress"), col.getString("ccontact_a"));
                    college.add(cg);
                
            

         catch (Exception e) 
            e.printStackTrace();
            // TODO: handle exception
        


    


    protected void displayList() 
        ArrayAdapter<Colleges> adapter = new ArrayAdapter<Colleges>(this, R.layout.list_item,college)

            @Override
            public View getView(int position, View convertView, ViewGroup parent) 
                View view = getLayoutInflater().inflate(R.layout.list_item,null);
                //set values
                Colleges c = college.get(position);
                ((TextView)view.findViewById(R.id.name)).setText(c.getName());
            /*  ((TextView)view.findViewById(R.id.address)).setText(c.getAddress());
                ((TextView)view.findViewById(R.id.contact)).setText(c.getContact());
                */
                return view;
            

        ;

        final ListView collegelistnew = (ListView) findViewById(R.id.listView);
        collegelistnew.setAdapter(adapter);

        collegelistnew.setOnItemClickListener(new AdapterView.OnItemClickListener() 

            @Override
            public void onItemClick(AdapterView<?> arg0, View arg1, int position,
                                    long arg3) 
                /*Toast.makeText(
                        getApplicationContext(),
                        "You clicked position" + position + "with item name"
                                + college.get(position).getName(),
                        Toast.LENGTH_LONG).show();*/


                Intent newIntent =new Intent(getApplicationContext(),CollegeDetails.class);

                newIntent.putExtra("college", (Serializable) college.get(position));
                startActivity(newIntent);


            

        );

    

【参考方案1】：

取消注释这两行：

/*  ((TextView)view.findViewById(R.id.address)).setText(c.getAddress());
            ((TextView)view.findViewById(R.id.contact)).setText(c.getContact());
            */

然后使用以下命令将其可见性设置为 GONE：

((TextView)view.findViewById(R.id.address)).setVisibility(View.GONE);
((TextView)view.findViewById(R.id.contact)).setVisibility(View.GONE);

或使用 xml。

通过这种方式，您可以在列表视图中仅显示一个姓名，但您还可以获得地址和联系方式以继续进行另一项活动。

【参考方案2】：

那堂课似乎还可以。但是你应该让你的类Colleges实现Parcelableinterface。

错误必须在CollegeDetails类中