写下SQL显示员工（工资大于5000）平均工资小于8000的部门

Posted 2023-03-28

【中文标题】写下SQL显示员工（工资大于5000）平均工资小于8000的部门

【英文标题】：Write down the SQL to show the department in which the average salary of the employees (whose salary is greater than 5000) is less than 8000

【发布时间】：2017-03-20 17:24:34

【问题描述】：

写下SQL，显示员工（工资大于5000）平均工资低于8000的部门。

这是我写的。我不确定这是否正确。

select departments.department_name, employees.avg(salary) as avgsalary from departments
inner join employees
on departments.department_id = employees.department_id
where avgsalary > 5000 and avgsalary < 8000;

【问题讨论】：

你需要一个 group by 和一个 (having 而不是 where)

作为建议，请在每个 from、join、where、group by、having 之前换行，但不要在 on 之前换行（或缩进on)

【参考方案1】：

select departments.department_name
    , avg(employees.salary) as avgsalary 
from departments inner join employees
    on departments.department_id = employees.department_id
group by departments.department_name
having avg(employees.salary) > 5000 and avg(employees.salary) < 8000;