Percentile_Cont 函数抛出错误

Posted 2023-03-27

【中文标题】Percentile_Cont 函数抛出错误

【英文标题】：Percentile_Cont function throwing error

【发布时间】：2016-06-08 04:27:05

【问题描述】：

我有这个查询，我试图在 PERCENTILE_CONT 中引入一个非静态值：

SELECT perf2.REVIEW_PERIOD
     , PERCENTILE_CONT(goalsASP.GOAL*.01) WITHIN GROUP (ORDER BY AVG_AMT ASC) ast75 
FROM repDB.TBL_PERFORMANCE perf2 JOIN
      pz.CATEGORY C on perf2.DEPTCAT = C.id JOIN
      repDB.TBL_GOALS_MATRIX goalsASP ON C.NAME = goalsASP.DIMENSION_Y
                                       and perf2.REVIEW_PERIOD = goalsASP.SNAP_NAME 
                                       and goalsASP.DIMENSION_X = 'asp'
GROUP BY perf2.REVIEW_PERIOD

抛出的错误是：

ORA-30497: Argument should be a constant or a function of expressions in GROUP BY. 30497. 00000 - "Argument should be a constant or a function of expressions in GROUP BY."

这是在一个视图中，当 goalsASP.GOAL*.01 是 .75 时它工作正常，并且我有一个存储过程，其中将列作为参数输入工作得很好，所以我有点不知所措我在这里做错了。

【参考方案1】：

知道了。与其说是 Percentile_Cont 的问题，不如说是正确分组的问题。

为了解决问题，我隔离了goalsASP.GOAL

SELECT perf2.REVIEW_PERIOD
     , goalsASP.GOAL
FROM repDB.TBL_PERFORMANCE perf2 JOIN
      pz.CATEGORY C on perf2.DEPTCAT = C.id JOIN
      repDB.TBL_GOALS_MATRIX goalsASP ON C.NAME = goalsASP.DIMENSION_Y
                                       and perf2.REVIEW_PERIOD = goalsASP.SNAP_NAME 
                                       and goalsASP.DIMENSION_X = 'asp'
GROUP BY perf2.REVIEW_PERIOD

然后很明显，我还需要按goalsASP.GOAL 分组。

那么，答案是：

SELECT perf2.REVIEW_PERIOD
     , PERCENTILE_CONT(goalsASP.GOAL*.01) WITHIN GROUP (ORDER BY AVG_AMT ASC) ast75 
FROM repDB.TBL_PERFORMANCE perf2 JOIN
      pz.CATEGORY C on perf2.DEPTCAT = C.id JOIN
      repDB.TBL_GOALS_MATRIX goalsASP ON C.NAME = goalsASP.DIMENSION_Y
                                       and perf2.REVIEW_PERIOD = goalsASP.SNAP_NAME 
                                       and goalsASP.DIMENSION_X = 'asp'
GROUP BY perf2.REVIEW_PERIOD,
         goalsASP.GOAL

有点尴尬，我以前没看到过，但是疲惫的眼睛想念这些东西。