Java 通过 ctrl click 检测在 OSX 上释放了哪个 mouseButton

Posted 2023-03-27

【中文标题】Java 通过 ctrl click 检测在 OSX 上释放了哪个 mouseButton

【英文标题】：Java detect which mouseButton is released on OSX with ctrl click

【发布时间】：2019-03-12 09:16:39

【问题描述】：

我尝试跟踪BUTTON1 BUTTON2 和BUTTON3 是否被按下。

问题是在 OSX 上 ctrl + click 被视为右键单击。 所以如果我有以下（使用处理）：

boolean mouse_left_pressed;
boolean mouse_right_pressed;

void setup() 
  size(200, 100);  


void draw() 
  background(0);
  fill(255);
  text("left: "+mouse_left_pressed, 50, 50);
  text("right: "+mouse_right_pressed, 50, 75);



public void mousePressed(MouseEvent e) 
  if (e.getButton() == LEFT) mouse_left_pressed = true;
  if (e.getButton() == RIGHT) mouse_right_pressed = true;


public void mouseReleased(MouseEvent e) 
  if (e.getButton() == LEFT) mouse_left_pressed = false;
  if (e.getButton() == RIGHT) mouse_right_pressed = false;

如果我执行以下步骤：

用鼠标左键单击并按住 按住控制键 松开鼠标左键

然后虽然我没有再按下鼠标，但mouse_left_pressed 的状态仍然是真实的。 有没有办法获得实际释放的鼠标按钮？

【参考方案1】：

这是因为在 OSX 中 control+left-click 等同于 right-click。它有点 hack，但您可以按如下方式检查修饰符：

boolean mouse_left_pressed;
boolean mouse_right_pressed;

void setup() 
  size(200, 100);  


void draw() 
  background(0);
  fill(255);
  text("left: "+mouse_left_pressed, 50, 50);
  text("right: "+mouse_right_pressed, 50, 75);



public void mousePressed(MouseEvent e) 
  if (e.getButton() == LEFT) mouse_left_pressed = true;
  if (e.getButton() == RIGHT) 
    if (!e.isControlDown()) 
      mouse_right_pressed = true;
    
    else 
      mouse_left_pressed = true;
    
  


public void mouseReleased(MouseEvent e) 
  println(e);
  if (e.getButton() == LEFT) mouse_left_pressed = false;
  if (e.getButton() == RIGHT) 
      if (!e.isControlDown()) 
        mouse_right_pressed = false;
      
      else 
        mouse_left_pressed = false;