合并两个 SOQL 查询

Posted 2023-03-23

【中文标题】合并两个 SOQL 查询

【英文标题】：Combine two SOQL queries

【发布时间】：2013-06-04 09:11:57

【问题描述】：

我是 SOQL 的初学者，希望你能帮助我。 我想结合这两个查询：

查询 1：

SELECT Id, Category__c, Segment__c
FROM Account
WHERE (Category__c = 'Prospect' AND Segment__c = 'High') OR (Category__c = 'Referrer' AND Segment__c = 'High')

查询 2：

SELECT Account_vod__c, WEEK_IN_YEAR(Call_Date_vod__c), CALENDAR_YEAR(Call_Date_vod__c)
FROM Call2_vod__c
WHERE Call_Date_vod__c = LAST_N_WEEKS:7
GROUP BY Account_vod__c, Call_Date_vod__c

Account 的 id 应该等于 Call2_vod__c 中的 Account_vod__c 值。

当我将这些结合起来时，我得到的结果是：

组合查询：

SELECT Id, Category__c, Segment__c
FROM Account
WHERE id in (select Account_vod__c from Call2_vod__c where Call_Date_vod__c = LAST_N_WEEKS:7) AND ((Category__c = 'Prospect' AND Segment__c = 'High') OR (Category__c = 'Referrer' AND Segment__c = 'High'))

但现在我缺少周和年值：

WEEK_IN_YEAR(Call_Date_vod__c), CALENDAR_YEAR(Call_Date_vod__c)

这部分： GROUP BY Account_vod__c，Call_Date_vod__c

如何组合这些查询并显示正确的星期和日历数据？

谢谢！

【问题讨论】：

顺便说一句，Stackexchange 上有一个额外的 Salesforce 论坛：salesforce.stackexchange.com

【参考方案1】：

如果您的 Account_vod__c 是对 Account 对象的查找，您可以通过键入 Account_vod__r.Name 等（使用“r”而不是“c”并使用点）从 Account 获取字段。

那么试试这样的东西？

SELECT Account_vod__c, Account_vod__r.Category__c, Account_vod__r.Segment__c, WEEK_IN_YEAR(Call_Date_vod__c), CALENDAR_YEAR(Call_Date_vod__c)
FROM Call2_vod__c
WHERE Call_Date_vod__c = LAST_N_WEEKS:7
GROUP BY Account_vod__c, Account_vod__r.Category__c, Account_vod__r.Segment__c, WEEK_IN_YEAR(Call_Date_vod__c), CALENDAR_YEAR(Call_Date_vod__c)

一个类似的，应该适用于没有你的对象的每个人：

SELECT AccountId, Account.Name, COUNT(Id) countOfContactsCreatedThatWeek, WEEK_IN_YEAR(CreatedDate) week, CALENDAR_YEAR(CreatedDate) year
FROM Contact
GROUP BY AccountId, Account.Name, WEEK_IN_YEAR(CreatedDate), CALENDAR_YEAR(CreatedDate)

【参考方案2】：

如果您可以使用两个查询，我会从它开始。在您拥有的组合版本中，无论如何，您在技术上都调用了两个查询。 where 子句中的内部查询算作针对您的调控器限制的第二次查询。

如果您使用的是 Apex，请尝试：

Map<Id, Account> aMap = new Map<Id, Account>([SELECT Id, Category__c, Segment__c
FROM Account
WHERE (Category__c = 'Prospect' AND Segment__c = 'High') OR (Category__c = 'Referrer' AND Segment__c = 'High')]);

List<Call2_vod__c> callList = [SELECT Account_vod__c, WEEK_IN_YEAR(Call_Date_vod__c), CALENDAR_YEAR(Call_Date_vod__c)
FROM Call2_vod__c
WHERE Call_Date_vod__c = LAST_N_WEEKS:7 and Id in :aMap.keySet()
GROUP BY Account_vod__c, Call_Date_vod__c];

【讨论】：

第二个将是AggregateResult，它有自己的一系列小问题。