我想在 Xcode 中使用 telprompt 拨打电话号码“#51234”[重复]

Posted 2023-03-16

【中文标题】我想在 Xcode 中使用 telprompt 拨打电话号码“#51234”[重复]

【英文标题】：I want to call phone number "#51234" in Xcode use telprompt [duplicate]

【发布时间】：2013-09-06 00:41:05

【问题描述】：

我想在 Xcode 中使用 telprompt 拨打电话号码“#51234”。

但 telprompt 拒绝它。

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"telprompt://#5%@", nzoneNum]]];

nzomeNum 是“1234”

【参考方案1】：

至少从 ios 11 开始，可以拨打带有井号 (#) 或星号 (*) 的号码。

使用这些字符拨打电话，首先对电话号码进行编码，然后添加tel: 前缀，最后将生成的字符串转换为 URL。

Swift 4、iOS 11

// set up the dial sequence
let nzoneNum = "1234"
let prefix = "#5"
let dialSequence = "\(prefix)\(nzoneNum)"

// "percent encode" the dial sequence with the URL Host allowed character set
guard let encodedDialSequence =
    dialSequence.addingPercentEncoding(withAllowedCharacters: .urlHostAllowed) else 
    print("Unable to encode the dial sequence.")
    return


// add the `tel:` url scheme to the front of the encoded string
let dialURLString = "tel:\(encodedDialSequence)"

// set up the URL with the scheme/encoded number string
guard let dialURL = URL(string: dialURLString) else 
    print("Couldn't make the dial string into an URL.")
    return


// dial the URL
UIApplication.shared.open(dialURL, options: [:])  success in
    if success  print("SUCCESSFULLY OPENED DIAL URL") 
    else  print("COULDN'T OPEN DIAL URL") 

Objective-C，iOS 11

// set up the dial sequence
NSString *nzoneNum = @"1234";
NSString *prefix = @"#5";
NSString *dialSequence = [NSString stringWithFormat:@"%@%@", prefix, nzoneNum];

// set up the URL Host allowed character set, and "percent encode" the dial sequence
NSCharacterSet *urlHostAllowed = [NSCharacterSet URLHostAllowedCharacterSet];
NSString *encodedDialSequence = [dialSequence stringByAddingPercentEncodingWithAllowedCharacters:urlHostAllowed];

// add the `tel` url scheme to the front of the encoded string
NSString *dialURLString = [NSString stringWithFormat:@"tel:%@", encodedDialSequence];

// set up the URL with the scheme/encoded number string
NSURL *dialURL = [NSURL URLWithString:dialURLString];

// set up an empty dictionary for the options parameter
NSDictionary *optionsDict = [[NSDictionary alloc] init];

// dial the URL
[[UIApplication sharedApplication] openURL:dialURL
                                   options:optionsDict
                         completionHandler:^(BOOL success) 
                             if (success)  NSLog(@"SUCCESSFULLY OPENED DIAL URL"); 
                             else  NSLog(@"COULDN'T OPEN DIAL URL"); 
                         ];

【讨论】：

你的回答很有趣：请在***.com/questions/13097737/… 上重新发布并投票以关闭 Mr_T 问题作为重复。

【参考方案2】：

很遗憾，您无法拨打任何号码，包括主题标签。 Apple 明确限制了这些调用：iPhoneURLScheme_Reference

为防止用户恶意重定向电话或更改电话或帐户的行为，电话应用支持 tel 方案中的大部分（但不是全部）特殊字符。具体来说，如果 URL 包含 * 或 # 字符，则电话应用不会尝试拨打相应的电话号码。