如何将 NSString 从 JSON 转换为 NSDictionary？ [关闭]

Posted 2023-03-16

【中文标题】如何将 NSString 从 JSON 转换为 NSDictionary？ [关闭]

【英文标题】：How convert a NSString from JSON to NSDictionary? [closed]

【发布时间】：2014-02-14 09:56:18

【问题描述】：

最终编辑解决方案：

解决问题的代码：

-(void) atacarAbogados

abogados = [[[NSArray alloc] init] autorelease];

NSLog(@"%@", userReceived);

NSString *myRequestString = [NSString stringWithFormat:@"user=%@", userReceived];
NSData *myRequestData = [NSData dataWithBytes: [myRequestString UTF8String] length: [myRequestString length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL: [NSURL

URLWithString:@""]];

[request setHTTPMethod:@"POST"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"content-type"];
[request setHTTPBody:myRequestData];

NSURLResponse *response;
NSError *error;

NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response

错误:&error];

NSString *content = [NSString stringWithUTF8String:[returnData bytes]];

//NSLog(@"Contenido de content: %@", content);


NSData *jsondata = [content dataUsingEncoding:NSUTF8StringEncoding];

NSError *jsonError = nil; 
id jsonObject = [NSJSONSerialization JSONObjectWithData:jsondata options:kNilOptions error:&jsonError];


if ([jsonObject isKindOfClass:[NSArray class]]) 
    NSLog(@"its an array!");
    NSArray *jsonArray = (NSArray *)jsonObject;
    for (id item in jsonArray) 
        if ([item isKindOfClass:[NSDictionary class]]) 
            NSString *foundValue = [(NSDictionary*)item objectForKey:@"CodigoAbogado"];
            if (foundValue) 
                NSLog(@"found 'CodigoAbogado' value: %@",foundValue);
            
         else 
            NSLog(@"item %@ is not a dictionary",item);
        

        //do the same thing for another search key
    

else 
    NSLog(@"its probably a dictionary");
    NSDictionary *jsonDictionary = (NSDictionary *)jsonObject;
    NSString *foundValue = [jsonDictionary objectForKey:@"CodigoAbogado "];
    NSLog(@"found 'CodigoAbogado' value %@", foundValue); //it return null if not found value for key 'COdigoabogado'

 

新编辑： 我的新代码，应用程序崩溃了，抱歉...

NSLog(@"%@", userReceived);

NSString *myRequestString = [NSString stringWithFormat:@"user=%@", userReceived];
NSData *myRequestData = [NSData dataWithBytes: [myRequestString UTF8String] length: [myRequestString length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL: [NSURL

URLWithString:@""]];

[request setHTTPMethod:@"POST"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"content-type"];
[request setHTTPBody:myRequestData];

NSURLResponse *response;
NSError *error;

NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response

错误:&error];

NSString *content = [NSString stringWithUTF8String:[returnData bytes]];

//NSLog(@"Contenido de content: %@", content);


NSData *jsondata = [content dataUsingEncoding:NSUTF8StringEncoding];

NSError *e = nil;
//NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData:jsondata options: NSJSONReadingMutableContainers

错误：&e];

NSError *jsonError = nil;
id jsonObject = [NSJSONSerialization JSONObjectWithData:jsondata options:kNilOptions error:&jsonError];

if ([jsonObject isKindOfClass:[NSArray class]]) 
    NSLog(@"its an array!");
    NSArray *jsonArray = (NSArray *)jsonObject;
    NSLog(@"jsonArray - %@",jsonArray);

else 
    NSLog(@"its probably a dictionary");
    NSDictionary *jsonDictionary = (NSDictionary *)jsonObject;
    NSLog(@"jsonDictionary - %@",jsonDictionary);

日志：

2014-02-14 12:09:50.649 appAbogados[34863:f803] 1 2014-02-14 12:09:50.651 appAbogados[34863:f803] 管理员 2014-02-14 12:09:50.685 appAbogados[34863:f803] 它是一个数组！ 2014-02-14 12:09:50.686 appAbogados[34863:f803] jsonArray - ( 0 = 1； 1 = 24898; 10 = "西班牙\U00f1a"; 11 = ""; 12 = 管理员； 13 = 1; 14 = 0; 15 = ""; 16 = 00； 17 = ""; 18 = ""; 19 = 0000000001; 2 =“琼·路易斯·冈萨雷斯·费雷里”； 20 = 00； 21 = 0; 22 = ""; 23 = ""; 24 = ""; 25 = " "; 26 = 0; 27 = 0; 28 = 0; 29 = 0; 3 = ""; 30 = 0; 31 = 0; 32 = 1; 33 = 0; 34 = 1; 35 = 3; 36 = 1; 37 = 000000002EEFA536C0B8B44B9B44E513587FBA9BA4F22000； 38 =“2011 年 11 月 10 日上午 11:32:54:000”； 39 = "\U00bd"; 4 = ""; 5 = ""; 6 =“[e-mail]”； 7 = ""; 8 = ""; 9 = ""; “Avis_Guardia” = 1； “Avis_Vista”= 0； CanalHabitualAbogado = 00; 证书编号 = ""; ClienteSerieTurnoOficio = 00; ClienteTurnoOficio = 0000000001; CodigoAbogado = 1; CodigoColegioAbogado = 0; CodigoPostal = ""; 描述1 = 0； Desc2 = 0; Desc3 = 0; Desc4 = 0; Desc5 = 0; Desc6 = 0; 方向 = ""; 特别 = "\U00bd"; EmpresaPredeterminadaEosCodigo = ""; EmpresaPredeterminadaEosNombre = ""; IPF = 0； IdOutLook = 000000002EEFA536C0B8B44B9B44E513587FBA9BA4F22000； 进口标识 = ""; 邮件=“[e-mail]”； MostrarInforme = 1; NIF = ""; Nombre = "琼·路易斯·冈萨雷斯·费雷里"; NombreColegioAbogado = ""; NombreComun = ""; 注释 = ""; NumeroColegiado = 24898; Pais = "Espa\U00f1a"; Poblacion = ""; 省 = ""; SerialCertificado = 1; 性=“”； "Tiempo_Avis" = 1; "Tiempo_Tipo" = 3; TipoVia = ""; UltimaModificacion = "2011 年 11 月 10 日上午 11:32:54:000"; Usuario = 管理员； )

---

我在 php 中有一个脚本，它以 JSON 格式响应数据。

当我收到数据时，我有一个包含内容的字符串，但我想将这些数据存储在字典中，因为我想访问一些值。

我一直在尝试使用 NSJSONSerialization，但我的应用程序到处崩溃。我是新手，我不知道请帮忙。

我的代码是：

NSLog(@"%@", userReceived);

NSString *myRequestString = [NSString stringWithFormat:@"user=%@", userReceived];
NSData *myRequestData = [NSData dataWithBytes: [myRequestString UTF8String] length: [myRequestString length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL: [NSURL URLWithString:@""]];

    [request setHTTPMethod:@"POST"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"content-type"];
[request setHTTPBody:myRequestData];

NSURLResponse *response;
NSError *error;

NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

NSString *content = [NSString stringWithUTF8String:[returnData bytes]];

NSLog(@"Contenido de content: %@", content);

变量“content”的内容是：

2014-02-14 10:48:17.996 appAbogados[34082:f803] 内容内容：

["0":"1","CodigoAbogado":"1","1":"24898","NumeroColegiado":"24898","2":"JOAN LLUIS GONZALEZ FERRERI","Nombre":"JOAN LLUIS GONZALEZ 
FERRERI","3":"","NombreComun":"","4":"","NIF":"","5":"","Direccion":"","6":"[e-mail]","Mail":"[e-mail]","7":"","CodigoPostal":"","8":"","Poblacion":"","9":"","Provincia":"","10":"Espa\u00f1a","Pais":"Espa\u00f1a","11":"","Notas":"","12":"Administrador","Usuario":"Administrador","13":"1","SerialCertificado":"1","14":0,"CodigoColegioAbogado":0,"15":"","NombreColegioAbogado":"","16":"00","CanalHabitualAbogado":"00","17":"","EmpresaPredeterminadaEosCodigo":"","18":"","EmpresaPredeterminadaEosNombre":"","19":"0000000001","ClienteTurnoOficio":"0000000001","20":"00","ClienteSerieTurnoOficio":"00","21":0,"IPF":0,"22":"","TipoVia":"","23":"","ImportIdentificacion":"","24":"","CertNombre":"","25":"
","Sexo":" 
","26":0,"Desc1":0,"27":0,"Desc2":0,"28":0,"Desc3":0,"29":0,"Desc4":0,"30":0,"Desc5":0,"31":0,"Desc6":0,"32":1,"Avis_Guardia":1,"33":0,"Avis_Vista":0,"34":1,"Tiempo_Avis":1,"35":3,"Tiempo_Tipo":3,"36":1,"MostrarInforme":1,"37":"000000002EEFA536C0B8B44B9B44E513587FBA9BA4F22000","IdOutLook":"000000002EEFA536C0B8B44B9B44E513587FBA9BA4F22000","38":"Nov
10 2011 11:32:54:000AM","UltimaModificacion":"Nov 10 2011 
11:32:54:000AM","39":"\u00bd","ESPECIAL":"\u00bd"]

PHP脚本的响应：

["0":"1","CodigoAbogado":"1","1":"24898","NumeroColegiado":"24898","2":"JOAN LLUIS GONZALEZ FERRERI","Nombre":"JOAN LLUIS GONZALEZ 
FERRERI","3":"","NombreComun":"","4":"","NIF":"","5":"","Direccion":"","6":"[e-mail]","Mail":"[e-mail]","7":"","CodigoPostal":"","8":"","Poblacion":"","9":"","Provincia":"","10":"Espa\u00f1a","Pais":"Espa\u00f1a","11":"","Notas":"","12":"Administrador","Usuario":"Administrador","13":"1","SerialCertificado":"1","14":0,"CodigoColegioAbogado":0,"15":"","NombreColegioAbogado":"","16":"00","CanalHabitualAbogado":"00","17":"","EmpresaPredeterminadaEosCodigo":"","18":"","EmpresaPredeterminadaEosNombre":"","19":"0000000001","ClienteTurnoOficio":"0000000001","20":"00","ClienteSerieTurnoOficio":"00","21":0,"IPF":0,"22":"","TipoVia":"","23":"","ImportIdentificacion":"","24":"","CertNombre":"","25":"
","Sexo":" 
","26":0,"Desc1":0,"27":0,"Desc2":0,"28":0,"Desc3":0,"29":0,"Desc4":0,"30":0,"Desc5":0,"31":0,"Desc6":0,"32":1,"Avis_Guardia":1,"33":0,"Avis_Vista":0,"34":1,"Tiempo_Avis":1,"35":3,"Tiempo_Tipo":3,"36":1,"MostrarInforme":1,"37":"000000002EEFA536C0B8B44B9B44E513587FBA9BA4F22000","IdOutLook":"000000002EEFA536C0B8B44B9B44E513587FBA9BA4F22000","38":"Nov
10 2011 11:32:54:000AM","UltimaModificacion":"Nov 10 2011 
11:32:54:000AM","39":"\u00bd","ESPECIAL":"\u00bd"]

非常感谢。

【问题讨论】：

NSString *content = [NSString stringWithUTF8String:[returnData bytes]]; NSData *jsondata = [内容 dataUsingEncoding:NSUTF8StringEncoding];这是完全没有意义的。您将 NSData 转换为 NSString 到 NSData。您所做的只是浪费时间和内存（加上有人发送 UTF-16 的可能性）。

【参考方案1】：

NSError *jsonError = nil; id jsonObject = [NSJSONSerialization JSONObjectWithData:jsondata options:kNilOptions error:&jsonError];

if ([jsonObject isKindOfClass:[NSArray class]]) 
    NSLog(@"its an array!");
    NSArray *jsonArray = (NSArray *)jsonObject;
    for (id item in jsonArray) 
        if ([item isKindOfClass:[NSDictionary class]]) 
            NSString *foundValue = [(NSDictionary*)item objectForKey:@"CodigoAbogado"];
            if (foundValue) 
                NSLog(@"found 'CodigoAbogado' value: %@",foundValue);
            
         else 
            NSLog(@"item %@ is not a dictionary",item);
        

        //do the same thing for another search key
    

else 
    NSLog(@"its probably a dictionary");
    NSDictionary *jsonDictionary = (NSDictionary *)jsonObject;
    NSString *foundValue = [jsonDictionary objectForKey:@"CodigoAbogado "];
    NSLog(@"found 'CodigoAbogado' value %@", foundValue); //it return null if not found value for key 'COdigoabogado'

【讨论】：

那行得通，我非常爱你，我对你投了绿票。感谢像我这样的菜鸟的奉献。

【参考方案2】：

查看 srik 的回答，您会找到将 json 字符串转换为数组或字典的方法。

How to use NSJSONSerialization

另外，发布您使用 NSJSonSerialization 和错误的代码！

问候，

【讨论】：

我编辑帖子，我收到此错误：2014-02-14 11:06:20.391 appAbogados[34221:f803] 解析 JSON 时出错：错误域 = NSCocoaErrorDomain 代码 = 3840 “操作无法” t 完成。（Cocoa 错误 3840。）“（垃圾结束。） UserInfo=0x686fb90 NSDebugDescription=垃圾结束。

该错误表明您的json字符串中可能存在无效字符。我已经复制了你的 json 并粘贴到一个文件中，有一些换行符。我已经删除了这些换行符并使用了你的代码，它可以工作。

其实你的json字符串根是字典，不是数组！ -> 抱歉，我们可以将其视为一个数组。但是，我在您的 json 'array' 中发现，有些字典没有键值。例如 "TipoVia":"" 。当我们将 json 转换为字典数组时，不接受这种情况，并且数组中的该项不是字典！。

你能把代码发给我吗？ [e-mail]

我添加了一个代码（这是你的代码）。运行此代码，应用程序将在“TipoVia”：“”处崩溃。删除“计数：%d”以避免崩溃

【参考方案3】：

NSString *jsonString = [NSString stringWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"json" ofType:@"txt"] encoding:NSUTF8StringEncoding error:nil];

NSData *jsondata = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSError *e = nil;
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData:jsondata options: NSJSONReadingMutableContainers error: &e];

if (!jsonArray) 
    NSLog(@"Error parsing JSON: %@", e);
 else 
    for(NSDictionary *item in jsonArray) 
        NSLog(@"Item: %@, count: %d", item, item.allKeys.count);
    

并在 json.txt 中编辑了 json 字符串：

"0":"1","CodigoAbogado":"1","1":"24898","NumeroColegiado":"24898","2":"JOAN LLUIS GONZALEZ FERRERI","Nombre" :"JOAN LLUIS GONZALEZ FERRERI","3":"","NombreComun":"","4":"","NIF":"","5":"","Direccion":"", "6":"[e-mail]","邮件":"[e-mail]","7":"","CodigoPostal":"","8":"","Poblacion":" ","9":"","Provincia":"","10":"Espa\u00f1a","Pais":"Espa\u00f1a","11":"","Notas":"", "12":"管理员","Usuario":"管理员","13":"1","SerialCertificado":"1","14":0,"CodigoColegioAbogado":0,"15":"" ,"NombreColegioAbogado":"","16":"00","CanalHabitualAbogado":"00","17":"","EmpresaPredeterminadaEosCodigo":"","18":"","EmpresaPredeterminadaEosNombre":" ","19":"0000000001","ClienteTurnoOficio":"0000000001","20":"00","ClienteSerieTurnoOficio":"00","21":0,"IPF":0,"22": "","TipoVia":"","23":"","ImportIdentificacion":"","24":"","CertNombre":"","25":"","Sexo":" ","26":0,"Desc1":0,"27":0,"Desc2":0,"28":0,"Desc3":0,"29":0,"Desc4":0, "30":0,"Desc5":0,"31":0,"Desc6":0,"32":1,"Avis_Gu ardia":1,"33":0,"Avis_Vista":0,"34":1,"Tiempo_Avis":1,"35":3,"Tiempo_Tipo":3,"36":1,"MostrarInforme" ：1，“37”：“000000002EEFA536C0B8B44B9B44E513587B444E513587FB444F22000”“IDOUTLOOK”：“000000002EEFA536C0B8B44B9B444E513587FB444E513587FB444E513587FB444E513587FB444E513587FB444E513587FB444E513587FBA9BA4F22000”：2011年11月11：32：54：000AM“，”Ultimamodificion“：”2011年11月10日11：32：54：000AM ","39":"\u00bd","ESPECIAL":"\u00bd"

【讨论】：

我编辑了第一篇文章，看到了，现在的问题是如何访问数据。我想获取数组的 CodigoAbogado 和 Nombre 来搜索键值，而不是像索引

您可以转换为 NSDictionary。使用 srik 的代码，它转换为字典，而不是数组。在该字典中，它包含的项目少于您的 json 字符串，因为某些项目没有价值。然后你可以使用 [dict objectForKey:'CodigoAbogado'] 来获取它的值。

我使用了 sriks 的代码，但是日志怎么说，保持数组而不是字典

【参考方案4】：

试试这个：

原文：

NSError *error = nil;
id object = [NSJSONSerialization JSONObjectWithData:returnData options:kNilOptions error:&error];

if([object isKindOfClass:[NSDictionary class]])
    NSDictionary *dict = [[NSDictionary alloc] initWithDictionary:object];


NSString *stringValue = [[dict objectForKey:@"CodigoAbogado"] stringValue];

编辑：由于响应在方括号中：

NSError *error = nil;
id object = [NSJSONSerialization JSONObjectWithData:returnData options:kNilOptions error:&error];

if([object isKindOfClass:[NSArray class]])
    NSArray *array = [[NSArray alloc] initWithArray:object];

for(NSDictionary *dict in array)
    NSString *stringValue = [[dict objectForKey:@"CodigoAbogado"] stringValue];

【讨论】：

嗯，不要转换成stringValue试试； SO NSString *stringValue = [dict objectForKey:@"CodigoAbogado"];

我使用了你的代码，但没有出现，代码没有进入 if

我用过这个： if ([object isKindOfClass:[NSArray class]]) NSLog (@"Class array"); 然后应用程序打印“类数组”

好的，我编辑了答案，它是如何工作的？

应用程序因此代码而崩溃-.-