条件JOIN不同的表

Posted 2023-03-14

【中文标题】条件JOIN不同的表

【英文标题】：Conditional JOIN different tables

【发布时间】：2012-05-03 23:31:39

【问题描述】：

我想知道用户是否在 任何 2 个相关表中都有条目。

表格

USER (user_id)
EMPLOYEE (id, user_id)
STUDENT (id, user_id)

用户可能有员工和/或学生条目。如何在一个查询中获取该信息？ 我试过了：

select * from [user] u
inner join employee e 
    on e.user_id = case when e.user_id is not NULL 
                        then u.user_id 
                        else null 
                   end
inner join student s 
    on s.user_id = case when s.user_id is not NULL 
                        then u.user_id 
                        else null 
                   end

但它只会返回在两个表中都有条目的用户。

SQL Fiddle example

【参考方案1】：

如果您将员工表和学生表视为一个表，则可以使用左连接：

select * 
from user u
left join 
(
   select 'Employee' as UserType,
          id,
          user_id
     from employee e 
    union all
   select 'Student',
          id,
          user_id
     from student s 
) r
  ON u.user_id = r.user_id

【讨论】：

最佳解决方案。 UNION ALL 将解决所有有条件的工作......太好了。谢谢。

【参考方案2】：

你可以使用外连接：

select *
  from USER u
  left outer join EMPLOYEE e ON u.user_id = e.user_id
  left outer join STUDENT s ON u.user_id = s.user_id
 where s.user_id is not null or e.user_id is not null

或者（如果您对 EMPLOYEE 或 STUDENT 表中的数据不感兴趣）

select *
  from USER u
 where exists (select 1 from EMPLOYEE e where e.user_id = u.user_id)
    or exists (select 1 from STUDENT s  where s.user_id = u.user_id)

【参考方案3】：

UNION 怎么样，你写成 2 个单独的 SELECT 语句

例如： SELECT * FROM User U JOIN Employee E ON E.User_Id = U.User_Id UNION SELECT * FROM User U JOIN student S ON S.User_Id = U.User_Id 我不明白你为什么需要 CASE 声明，它看起来是多余的。如果您想要所有用户并显示空值，请使用 LEFT OUTER JOIN。

【参考方案4】：

如果您想将所有用户数据放在一起，您可能有：

SELECT 
    user_id
    ,'Employee' AS Source
FROM 
    employee
UNION 
SELECT 
    user_id
    ,'Student' AS Source
FROM 
    student

http://sqlfiddle.com/#!3/90216/22

这也可以通过完全连接和 CASE 语句来完成：

SELECT 
    ISNULL(e.user_id,s.user_id) AS user_id
    ,CASE WHEN e.user_id IS NULL THEN 'Student' 
        ELSE 'Employee'
    END AS SOURCE
FROM 
    employee AS e 
    FULL JOIN student AS s
        ON s.user_id = e.user_id

http://sqlfiddle.com/#!3/90216/29

后者会将既是学生又是雇员的人组合成一排，并称他们为雇员。比较：

http://sqlfiddle.com/#!3/2aa3e/1 和 http://sqlfiddle.com/#!3/2aa3e/2

我让用户 1 成为学生和员工

【参考方案5】：

这样的解决方案也可以帮助你。

SELECT  S.*, P.*

,CASE
    WHEN S.ShipmentType = 'import' THEN SP.SupplierName
    WHEN S.ShipmentType = 'export' THEN C.CustomerName
END AS ShipmentDesination

FROM            tblShippments   S 
INNER JOIN      tblProducts     P   ON S.productId = P.productID  
LEFT OUTER JOIN tblCustomers    C   ON S.companyId = C.customerId AND S.ShipmentType = 'export'
LEFT OUTER JOIN tblSuppliers    SP  ON S.companyId = SP.supplierId AND S.ShipmentType = 'import'

【参考方案6】：

SELECT   OrderID, Quantity,  O.ProductID , ProductName,
CASE
WHEN Quantity > 3 THEN 'The quantity is More than 3'
WHEN Quantity = 3 THEN 'The quantity is Equal to  3'
ELSE 'The quantity is Less than 3'
END AS QuantityText

FROM            tb_OrderDetail O 
INNER JOIN      tb_Product     P   ON O.ProductID = P.ProductID

【讨论】：

请提供有关您的解决方案的更多详细信息。仅发布代码并不是回答问题的好方法。

【参考方案7】：

适用于 mysql v5.6+ 架构：

CREATE TABLE USER (user_id INT);
CREATE TABLE employee (id INT, user_id INT);
CREATE TABLE student (id INT, user_id INT);

INSERT INTO USER SELECT 1;
INSERT INTO USER SELECT 2;
INSERT INTO USER SELECT 3;
INSERT INTO USER SELECT 4;

INSERT INTO employee SELECT 1, 1;
INSERT INTO employee SELECT 2, 4;

INSERT INTO student SELECT 1, 2;

第一个解决方案 ，完全外连接不适用于mysql v5.6+：

 SELECT 
    IF(e.user_id IS NULL,s.user_id,e.user_id) AS user_id
    ,CASE WHEN e.user_id IS NULL THEN 'Student' 
        ELSE 'Employee'
    END AS SOURCE
FROM 
    employee AS e 
    LEFT JOIN student AS s
        ON (s.user_id = e.user_id)
    UNION
        SELECT 
    IF(e.user_id IS NULL,s.user_id,e.user_id) AS user_id
    ,CASE WHEN e.user_id IS NULL THEN 'Student' 
        ELSE 'Employee'
    END AS SOURCE
    FROM 
    employee AS e 
     RIGHT JOIN student AS s
        ON (s.user_id = e.user_id)

替代解决方案：

SELECT   IF(e.user_id IS NULL,s.user_id,e.user_id) AS user_id,
 CASE WHEN e.user_id IS NULL THEN 'Student' 
            ELSE 'Employee'
        END AS SOURCE
 FROM   USER AS u
 LEFT OUTER JOIN employee e ON (u.user_id = e.user_id) 
 LEFT OUTER JOIN student s ON (u.user_id = s.user_id) 
 WHERE s.user_id IS NOT NULL OR e.user_id IS NOT NULL

其他替代解决方案：

 SELECT u.user_id,SOURCE 
FROM USER u
INNER JOIN 
(
   SELECT 'Employee' AS SOURCE,id,user_id FROM employee e 
    UNION ALL
   SELECT 'Student',id,user_id  FROM student s 
) r ON u.user_id = r.user_id