TypeError [ERR_INVALID_ARG_TYPE]：“listener”参数必须是函数类型。收到未定义

Posted 2023-03-14

【中文标题】TypeError [ERR_INVALID_ARG_TYPE]：“listener”参数必须是函数类型。收到未定义

【英文标题】：TypeError [ERR_INVALID_ARG_TYPE]: The "listener" argument must be of type function. Received undefined

【发布时间】：2020-09-16 18:40:03

【问题描述】：

在对象。 (C:\Users\Hades\Downloads\Jaxxy\src\bot.js:51:8)

我指定命令的代码是

client.on('guildMemberAdd'), member => 
  const channel = member.guild.channels.cache.find(channel=> channel.name === "welcome");
  if(!channel) return;
  channel.send(`Welcome to Hades's Tavern,$(member), make sure to read the rules in #rules!`)

;

我正在使用 discord.js v12！ 有人知道吗？

【参考方案1】：

右括号必须在箭头函数的主体之后：

client.on('guildMemberAdd', member => 
    const channel = member.guild.channels.cache.find(channel => channel.name === "welcome");
    if (!channel) return;
    channel.send(`Welcome to Hades's Tavern,$(member), make sure to read the rules in #rules!`)

);