SQL 排行榜问题 nodejs discord.js

Posted 2023-03-14

【中文标题】SQL 排行榜问题 nodejs discord.js

【英文标题】：SQL Leaderboard issue nodejs discord.js

【发布时间】：2019-07-26 08:48:26

【问题描述】：

我创建了一个简单的不和谐机器人，其中包含消息侦听器等，它在某些事件上将数据添加到 mysql 数据库中。

我的代码为在频道中添加 +1 点评分（完全有效）：

//If message is sent add points to scores table

    con.query(`SELECT * FROM scores WHERE user="$message.author.id" AND guild= "$message.guild.id"`, (err, rows) => 
        if (err) throw err;

        let sql;
        if (rows.length < 1) 
            sql = `INSERT INTO scores (user, guild, points) VALUES ('$message.author.id', '$message.guild.id', '1')`, (err, rows) => 
                if (err) throw err;
            ;

         else 
            let score = rows[0].scores;
            sql = `UPDATE scores SET points = points +1 WHERE user="$message.author.id" AND guild= "$message.guild.id"`;
        ;

        con.query(sql);

    );

一旦排行榜命令进入频道；我想获取分数表中的数据，将其分类到前 10 名并以不和谐的方式打印（通过使用 message.channel.send 或 message.channel.send(embed)。

以下代码是我目前所拥有的：

const Discord = require("discord.js");

module.exports.run = async (bot, message, args, con) => 
    
const top10 = `SELECT user, points, lstmsg FROM scores WHERE guild = '$message.guild.id' ORDER BY cast(points as SIGNED) ASC LIMIT 10`;
//user, points, lstmsg from scores WHERE guild= '$message.guild.id' ORDER BY points DESC LIMIT 10`;

con.query(top10, function(err, rows, fields) 
  if (err) throw err;

  //    const embed = new Discord.RichEmbed()
  //   .setTitle("Leaderboard")
  //   .setAuthor(bot.user.username,)
  //   .setDescription("Inactive..... Boooooo!")
  //   .addField(rows[1])
  //   .setColor(0x00AE86)


return message.channel.send(rows);

);



module.exports.help = 
    name: "top10",
    usage: "``prefix`` top10",
    description: "top 10 points",

但它发送的内容不一致：

[object Object]
[object Object]
[object Object]
[object Object]
[object Object]
[object Object]
[object Object]
[object Object]
[object Object]
[object Object]

有什么想法吗？提前致谢

使用 JSON.Stringify 会返回如下结果：

["user":"123456789876587659","points":"2","lstmsg":"2019-03-04T22:40:40.000Z","user":"378976806730203147","points":"80","lstmsg":"2019-03-05T10:10:18.000Z","user":"123456789101112131","points":"93","lstmsg":"2019-03-04T22:40:29.000Z","user":"378976806730203147","points":"168","lstmsg":"2019-03-05T10:10:18.000Z","user":"456567676767867677","points":"289","lstmsg":"2019-03-04T22:41:01.000Z"]

我希望数据显示为：

User:
Points:
Last Message: 

对于数据库中的每个条目（限制为 10 个）。

我还尝试了以下资源：SQLite-Based Points system

代码：

const Discord = require("discord.js");

module.exports.run = async (bot, message, args, con) => 
  
    var top10query = "SELECT * FROM scores WHERE guild = ? ORDER BY points DESC LIMIT 10"
    const top10 = con.query(top10query)

    // Now shake it and show it! (as a nice embed, too!)
    const embed = new Discord.RichEmbed()
      .setTitle("Leaderboard")
      .setAuthor(bot.user.username, bot.user.avatarURL)
      .setDescription("Our top 10 points leaders!")
      .setColor(0x00AE86);

    for (const data of top10) 
      embed.addField(bot.users.get(data.user).tag, `$data.points points (last message $data.lstmsg)`);
    
    return message.channel.send( embed );
  






module.exports.help = 
  name: "inactive",
  usage: "``prefix`` inactive",
  description: "Bottom 30 inactive & last message date for current weeks",

但我得到一个错误（很可能是因为该示例适用于 SQLlite 并适用于 MySQL）：

(node:2880) UnhandledPromiseRejectionWarning: TypeError: top10 is not iterable

【参考方案1】：

如果还没有的话，我建议user、guild 是分数表的复合主键（或唯一键）。这可以在 SQL 中完成：

ALTER TABLE scores DROP PRIMARY KEY, ADD PRIMARY KEY (user, guide)

对于您的 SQL 语句，INSERT ON DUPLICATE KEY UPDATE 是一个常见的查询。它依赖于上面的唯一键或主键。

INSERT INTO scores (user, guild, points) VALUES ('$message.author.id', '$message.guild.id', '1')
ON DUPLICATE KEY UPDATE points=points+1

另见Preventing SQL injection in Node.js

【讨论】：

承认这不是你问的问题，但是代码有点乱，而且两部分都有需要修复的 SQL 注入（无需信任不和谐机器人）。

感谢您的建议！它只是一个用于跟踪行会中非活动用户的基本机器人，所以并不真正关心这个特定项目的 SQL 注入。我可能会稍后更新它以防止这种情况发生，但不是现在。

【参考方案2】：

尝试使用JSON.stringify();，文档为here。

var o = 
  a: 2, 
  b: 3

console.log(JSON.stringify(o));  //""a":2,"b":3"

【讨论】：

JSON.stringify 正是我所需要的！！谢谢！在正确的轨道上.. 我将如何拆分结果以显示：用户：积分：最后一条消息：每个条目？结果显示为：["user":"123456789876587659","points":"2","lstmsg":"2019-03-04T22:40:40.000Z","user":"378976806730203147" ,"points":"77","lstmsg":"2019-03-04T23:47:47.000Z","user":"123456789101112131","points":"93","lstmsg":"2019 -03-04T22:40:29.000Z","user":"456567676767867677","points":"289","lstmsg":"2019-03-04T22:41:01.000Z"]

因为这个答案对你有用，我建议你点击旁边的小空心复选标记将其标记为正确，这样如果人们有和你一样的问题。如果您使用rows[x].key，那么它将为您提供该值，例如console.log(rows[0].points); //2 将返回2，另一个示例是rows[1].points，这将返回77，依此类推。

【参考方案3】：

我用map来绘制结果。

const Discord = require("discord.js");

module.exports.run = async (bot, message, args, con) => 

  const top10query = `SELECT user, points, lstmsg FROM scores WHERE guild = '$message.guild.id' ORDER BY cast(points as SIGNED) DESC LIMIT 10`

  const query = querytxt => 
    return new Promise((resolve, reject) => 
      con.query(querytxt, (err, results, fields) => 
        if (err) reject(err);
        resolve([results, fields]);
      );
    );
  ;
  const [results, fields] = await query(top10query);

  const map1 = results.map(results => ` ** User:** $bot.users.get(results.user).username \n **Messages:** $results.points \n **Last message:** $results.lstmsg \n`);
  message.channel.send(map1)

module.exports.help = 
  name: "top10",
  usage: "``prefix`` top10",
  description: "top 10 points",