发生 HttpsURLConnection 400 Bad Request 错误

Posted 2023-03-12

【中文标题】发生 HttpsURLConnection 400 Bad Request 错误

【英文标题】：HttpsURLConnection 400 Bad Request error occured

【发布时间】：2018-11-21 00:27:21

【问题描述】：

我需要将以下 Swift 代码转换为 Java。 Swift 代码有效。 但是，Java 代码不起作用。

HttpsURLConnection 失败。

responseCode: 400 (HttpsURLConnection.getResponseCode())

message2：错误请求 (HttpsURLConnection.getResponseMessage())

如何解决 400 Bad Request 错误。

在 Swift 中（有效）

func sendNotification(token: String, message: String) 

 //Firebase CloudMessaging serverkey
    var firebaseServerKey = "AAAAA6qLps4:APA91bE7szGAgp3qYGOJsrSsrM1InhIgf5Fq1xxxxxx"

    let url = URL(string: "https://fcm.googleapis.com/fcm/send")!
    var request = URLRequest(url: url)
    request.setValue("application/json", forHTTPHeaderField: "Content-Type")

    request.setValue("key=\(firebaseServerKey)", forHTTPHeaderField: "Authorization")
    request.httpMethod = "POST"

    request.httpBody = "\"to\":\"\(token)\",\"notification\":\"body\":\"\(message)\",\"badge\":\"1\"".data(using: .utf8)

我用JAVA写的（没用）

private void sendNotification(String token, String message) 
//Firebase CloudMessaging serverkey
    var firebaseServerKey = "AAAAA6qLps4:APA91bE7szGAgp3qYGOJsrSsrM1InhIgf5Fq1xxxxxx"

    try 
        URL url = new URL("https://fcm.googleapis.com/fcm/send");
        HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
        conn.setReadTimeout(10000);
        conn.setConnectTimeout(15000);
        conn.setRequestMethod("POST");
        conn.setDoInput(true);
        conn.setDoOutput(true);
        conn.setRequestProperty("Content-Type", "application/json");
        conn.setRequestProperty("Authorization", "key="+firebaseServerKey);


        String str = "\"to\": " + token + ", \"notification\":  \"body\": " + message + ", \"badge\": \"1\"";


        byte[] outputInBytes = str.getBytes("UTF-8");
        OutputStream os = conn.getOutputStream();
        os.write(outputInBytes);
        os.close();

        int responseCode = conn.getResponseCode(); // responseCode: 400

        if (responseCode == HttpsURLConnection.HTTP_OK) 
            Log.d("Success", String.valueOf(responseCode));
         else 
            String code = String.valueOf(responseCode);
            String message2 = conn.getResponseMessage(); // message2: Bad Request
            Log.d("Fail", String.valueOf(responseCode));
            Log.d("Fail2", conn.getResponseMessage());
        

【参考方案1】：

您的 JSON 请求正文不正确。它产生 "to": zxc 这是一个无效的 json。改成

String str = "\"to\": \"" + token + "\", \"notification\":  \"body\": \"" +
    message + "\", \"badge\": \"1\"";

【讨论】：

嗨，谢谢。我无法用你的代码建立成功。我对 Json 的东西不熟悉。我应该如何改变它？

嗨，我仍然没有像下图那样构建失败。

我更新了它。我检查了我的 IDE。再次放错地方对不起