Swift - 序列化包含对象数组的对象并使用 alamofire 发送

Posted 2023-03-10

【中文标题】Swift - 序列化包含对象数组的对象并使用 alamofire 发送

【英文标题】：Swift - Serialize object containing array of objects and send with alamofire

【发布时间】：2020-09-06 17:25:59

【问题描述】：

我需要使用 Alamofire 发送带有类作为参数的发布请求。 我的班级包含其他班级的数组，因此我被卡住了。

class CreateRecordData
    var RecordDate: String?
    var RecordType: String?
    var SubType: String?
    var Name: String?
    var MovementRecords: [RecordMovementData]?
    var MeasurementId: Int?
    var SensorType: String?



class RecordMovementData
    var FrameRate: Int?
    var JointType: String?
    var Samples: [MovementSampleData]?
    var RecordId: Int?




class MovementSampleData 
    var Id: Int?
    var TimeStamp: Int64?
    var X: Float?
    var Y: Float?
    var Z: Float?

我是 swift 的新手，有一段时间无法完成这项工作。

解决这个问题的方法是什么。

我需要 CreateRecordData 类使用 alamofire 作为参数发送。

谢谢

添加 Encodable 后的类

class CreateRecordData: Encodable
    var RecordDate: String?
    var RecordType: String?
    var SubType: String?
    var Name: String?
    var AudioRecords: [AudioData]?
    var MovementRecords: [RecordMovementData]?
    var MeasurementId: Int?
    var SensorType: String?

    enum CodingKeys: String, CodingKey 
        case RecordDate
        case RecordType
        case SubType
        case Name
        case AudioRecords
        case MovementRecords
        case MeasurementId
        case SensorType
    
    func encode(to encoder: Encoder) throws 
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(RecordDate, forKey: .RecordDate)
        try container.encode(RecordType, forKey: .RecordType)
        try container.encode(SubType, forKey: .SubType)
        try container.encode(Name, forKey: .Name)
        try container.encode(AudioRecords, forKey: .AudioRecords)
        try container.encode(MovementRecords, forKey: .MovementRecords)
        try container.encode(MeasurementId, forKey: .MeasurementId)
        try container.encode(SensorType, forKey: .SensorType)
    


class RecordMovementData: Encodable
    var FrameRate: Int?
    var JointType: String?
    var Samples: [MovementSampleData]?
    var RecordId: Int?

    enum CodingKeys: String, CodingKey
        case FrameRate
        case JointType
        case Samples
        case RecordId
    
    func encode(to encoder: Encoder) throws
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(FrameRate, forKey: .FrameRate)
        try container.encode(JointType, forKey: .JointType)
        try container.encode(Samples, forKey: .Samples)
        try container.encode(RecordId, forKey: .RecordId)
    



class MovementSampleData: Encodable 
    var Id: Int?
    var TimeStamp: Int64?
    var X: Float?
    var Y: Float?
    var Z: Float?

    enum CodingKeys: CodingKey
        case Id
        case TimeStamp
        case X
        case Y
        case Z
    
    func encode(to encoder: Encoder) throws
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(Id, forKey: .Id)
        try container.encode(TimeStamp, forKey: .TimeStamp)
        try container.encode(X, forKey: .X)
        try container.encode(Y, forKey: .Y)
        try container.encode(Z, forKey: .Z)
    

还有一点要提。 a 不要直接使用 CreateRecordData 作为参数。我使用该类的数据创建字典，如下所示：

let recordParams: [String:Any] = [
            "RecordDate": recordData.RecordDate!,
            "RecordType": recordData.RecordType!,
            "SubType": recordData.SubType!,
            "Name": recordData.Name!,
            "AudioRecords": "",
            "MovementRecords": recordData.MovementRecords!,
            "MeasurementId": "\(recordData.MeasurementId!)",
            "SensorType": recordData.SensorType!
        ]

        AF.request("https://repac-fe-v1-webapp.azurewebsites.net/api/record",method: .post, parameters: recordParams, encoding: JSONEncoding.default, headers: header).responseJSON  response in

        

这也可能有问题

【问题讨论】：

您的服务器需要什么样的编码？你已经尝试了什么？你看过Codable 协议了吗？ developer.apple.com/documentation/foundation/…

@gcharita 需要 Json 编码。我尝试了 Codable 协议，但在 JSON 写入中出现错误无效类型。我会仔细查看您发送的链接

请发布您的Codable 代码以找出缺少的内容。

@gcharita 我编辑了帖子，我假设我只需要在我的课程中使用 Encodable 来完成我需要做的事情。在此之后我仍然有同样的错误

【参考方案1】：

由于 JSON 中的键与模型属性的名称相同，因此您可以在模型类中省略 CodingKeys 枚举。此外，由于您没有在编码中进行自定义操作，因此您可以完全省略 encode(to:) 函数的实现：

class AudioData: Encodable 
    // This class is missing from the posted code


class CreateRecordData: Encodable 
    var RecordDate: String?
    var RecordType: String?
    var SubType: String?
    var Name: String?
    var AudioRecords: [AudioData]?
    var MovementRecords: [RecordMovementData]?
    var MeasurementId: Int?
    var SensorType: String?


class RecordMovementData: Encodable 
    var FrameRate: Int?
    var JointType: String?
    var Samples: [MovementSampleData]?
    var RecordId: Int?


class MovementSampleData: Encodable 
    var Id: Int?
    var TimeStamp: Int64?
    var X: Float?
    var Y: Float?
    var Z: Float?

使用Encodable 对象作为参数的发布请求比您想象的要简单。您只需调用request 方法，该方法将encoder 而非encoding 作为参数：

let recordParams = CreateRecordData() // Set the class values here

AF.request(
    "https://repac-fe-v1-webapp.azurewebsites.net/api/record",
    method: .post,
    parameters: recordParams,
    encoder: JSONParameterEncoder.default,
    headers: header
).responseJSON  response in