比较数组中的元素，看看字符串中是不是有重复项

Posted 2023-03-10

【中文标题】比较数组中的元素，看看字符串中是不是有重复项

【英文标题】：Compare the elements in the array to see if there are duplicates in the string比较数组中的元素，看看字符串中是否有重复项

【发布时间】：2021-06-10 03:09:57

【问题描述】：

目前，我在将数组与字符串进行比较时遇到问题。我有 2 个数组，想知道这 2 个数组中的元素是否在字符串中

 let resultString = "STEREON10.000 4ailthameGrinreD NOCHIMINNICHNUÖC-LOINHÀ GIAIDACBIET2ty UnOMMOSTCRShitConDONG FlimChineCrJ045 Dòketquásoan: XSHCM goi 7181 8186-8110°593364THUBAY6A7 05-6-2021teIntaiKNInTaiChínhTP.HCM"
 let code_province:[String] = ["xsag", "xsbd", "xsbdi", "xsbl","xsbp",
                           "xsbt", "xsbth", "xscm", "xsct", "xsdl",
                           "xsdlk", "xsdn", "xsdng", "xsdno", "xsdt",
                           "xsgl", "xshcm", "xshg", "xskg", "xskh",
                           "xskt", "xsla", "xsmb", "xsnt", "xspy",
                           "xsqb", "xsqng", "xsqnm", "xsqt", "xsst",
                           "xstg", "xstn", "xstth", "xstv", "xsvl",
                           "xsvt", "xsbri",]
    
    let name_Province:[String] = ["angiang","binhduong","binhdinh","baclieu", "binhphuoc","bentre", "binhthuan", "camau", "cantho", "dalat","daklak", "dongnai", "daNang", "daknong", "dongthap","gialai", "hcm", "haugiang", "kiengiang", "khanhhoa","kontum", "longan", "mienbac", "ninhthuan", "phuyen","quangbinh", "quangNgai", "quangnam", "quangtri", "soctrang","tiengiang", "tayninh", "thuat.hue", "travinh", "vinhlong","vungtau","baria"]

【问题讨论】：

请添加一些您尝试过的代码。另外，添加您面临的问题。

可能是let resultStringSplit = resultString.components(separatedBy: " "); let contains = !Set(code_province).intersection(resultStringSplit).isEmpty || !Set(name_Province).intersection(resultStringSplit).isEmpty; print(contains)?

你不能指望社区给你一个算法的解决方案。有很多字符串搜索算法。这实际上不是问题。感觉就像你想要有人为你做这项工作。做这项工作。开始here。然后实施它。同样对于@aheze 评论，这不起作用，因为他们询问两个数组之一中的字符串是否为“IN THE STRING”。您的评论假定他们正在寻找的字符串由未指定的空格分隔。

【参考方案1】：

这是一种方法：

let f: (String) -> String? =  resultString.localizedStandardContains($0) ? $0 : nil 
let provincesInResult = code_province.compactMap(f)
let namesInResult = name_Province.compactMap(f)

我们从字符串列表中映射要搜索的事物列表，如果没有找到则映射到 nil，如果找到则映射到字符串。然后我们压缩结果，只留下一个找到的列表。这可能是 0、1 或更多，因此请考虑这些可能性。