Apollo 客户端不显示错误消息
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【中文标题】Apollo 客户端不显示错误消息【英文标题】:Apollo client doesn't display an error message 【发布时间】:2019-10-05 08:26:43 【问题描述】:我已经配置并设置了一个功能齐全的 express-nextjs-graphql-apollo 应用程序,它可以登录/注销用户,并完美地执行 CRUD。 最后也是非常重要的一步是在客户端显示错误消息。
到目前为止,我只在控制台中收到此红色错误:POST http://localhost:3000/graphql 500 (Internal Server Error)
例如,登录表单验证。当没有提供输入时,它应该得到一个无效的输入错误消息,如果电子邮件格式不正确,它应该得到一个E-Mail is invalid
。
在graphqllocalhost:3000/graphql
中测试的以下突变代码:
mutation
login(userInput: email:"" password:"")
userId
返回下面的消息。我实际上希望这条消息显示在客户端上。
"errors": [
"message": "Please provide input.",
"locations": [
"line": 2,
"column": 3
],
"path": [
"login"
]
],
"data": null
我还尝试使用 onError 在 Mutation 组件内的客户端上显示错误消息:
onError=error =>
console.log("ERROR in SigninBox component ", error);
仅在控制台中显示此错误消息:Response not successful: Received status code 500
这就是我在服务器上设置'express-graphql'
包的方式:
server.use(
"/graphql",
graphqlHTTP(
schema: graphQlSchema,
rootValue: graphQlResolvers,
graphiql: true,
customFormatErrorFn(err)
if (!err.originalError)
return err;
const data = err.originalError.data;
const message = err.message || "An error occurred.";
const code = err.originalError.code || 500;
return
message: message,
status: code,
data: data
;
)
);
登录解析器:
login: async ( userInput ) =>
if (
validator.isEmpty(userInput.email) ||
validator.isEmpty(userInput.password)
)
throw new Error("Please provide input.");
if (!validator.isEmail(userInput.email))
throw new Error("E-Mail is invalid.");
if (
validator.isEmpty(userInput.password) ||
!validator.isLength(userInput.password, min: 5 )
)
throw new Error("Password too short!");
const user = await User.findOne( email: userInput.email );
if (!user)
const error = new Error("User does not exist!");
error.code = 404;
throw error;
const isEqual = await bcrypt.compare(userInput.password, user.password);
if (!isEqual)
throw new Error("Password is incorrect!");
const token = jwt.sign(
userId: user.id, email: user.email ,
"somesupersecretkey",
expiresIn: 1000
);
return userId: user.id, token: token, tokenExpiration: 1 ;
客户端:
import Mutation, withApollo from "react-apollo";
import gql from "graphql-tag";
import redirect from "../lib/redirect";
import setCookie from "../helpers/cookie";
const SIGN_IN = gql`
mutation login($email: String!, $password: String!)
login(userInput: email: $email, password: $password )
token
`;
const Signin = ( client ) =>
let email, password;
return (
<Mutation
mutation=SIGN_IN
onCompleted=data =>
setCookie("token", data.login.token);
client.cache.reset().then(() =>
redirect(, "/admin");
);
onError=error =>
console.log("ERROR in SigninBox ", error);
>
(login, data, error ) => (
<div>
<form
onSubmit=e =>
e.preventDefault();
e.stopPropagation();
login(
variables:
email: email.value,
password: password.value
);
email.value = password.value = "";
>
<div>
<h1>Admin Page Login</h1>
</div>
<div className="form-label-group">
<input
className=`form-control $error ? "is-invalid" : ""`
name="email"
id="inputEmail"
placeholder="Email"
ref=node =>
email = node;
/>
<label htmlFor="inputEmail">Email address</label>
error && (
<div className="invalid-feedback">
No user found with that information.
</div>
)
</div>
<div>
<input
name="password"
id="inputPassword"
placeholder="Password"
ref=node =>
password = node;
type="password"
/>
<label htmlFor="inputPassword">Password</label>
</div>
<button type="submit">Login</button>
</form>
</div>
)
</Mutation>
);
;
export default withApollo(SignIn);
我也试过这个 onError 检查:
onError=( graphQLErrors, networkError ) =>
if (graphQLErrors)
graphQLErrors.map(( message, locations, path ) =>
console.log(
`[GraphQL error]: Message: $message, Location: $locations, Path: $path`
)
);
if (networkError) console.log(`[Network error]: $networkError`);
这基本上返回了相同的错误消息:[Network error]: ServerError: Response not successful: Received status code 500
我的目标是显示我通常会在 graphql localhost:3000/graphql
中收到的消息,它来自我的解析器,例如:E-Mail is invalid
、Please provide input.
等。
如何将此message
发送到客户端 onError 处理程序?
【问题讨论】:
【参考方案1】:做了一些研究后,我意识到错误本身就是一个对象
onError=error =>
console.log("ERROR in SigninBox ", error );
并且错误信息存储在error.networkError.result.errors[0].message
中
【讨论】:
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