快速连续多次创建 UIAlertView
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【中文标题】快速连续多次创建 UIAlertView【英文标题】:Creating UIAlertView multiple times in a quick succession 【发布时间】:2013-11-05 18:47:17 【问题描述】:在我的应用程序中,我打算让两个(或更多)设备共享和合并 NSDictionaries。我的 Multipeer Connectivity 工作完美,当归结为在每次传输时合并两个字典时,我遇到了一个问题。我现在有两个“for”循环遍历两个字典。如果存在已经存在的键/值对,则会提示用户是否要覆盖已存在的对象或保留它。他们可以选择保留当前对象、覆盖当前对象、保留所有冲突对象或覆盖所有冲突对象。我到目前为止的代码:
-(void)session:(MCSession *)session didReceiveData:(NSData *)data fromPeer:(MCPeerID *)peerID
pathChooser = 1;
NSLog(@"DATA RECEIVED: %d bytes!", data.length);
dataReceived = data;
receivedDataDict = [[NSMutableDictionary alloc] init];
receivedDataDict = [NSKeyedUnarchiver unarchiveObjectWithData:dataReceived];
for (key1 in receivedDataDict)
NSLog(@"%@", key1);
if ([dataDict objectForKey:key1] == nil)
NSLog(@"Writing new folder");
[dataDict setObject:[[NSMutableDictionary alloc] init] forKey:key1];
for (key2 in [receivedDataDict objectForKey:key1])
if ([[dataDict objectForKey:key1] objectForKey:key2] == nil)
NSLog(@"Writing a new file");
[[dataDict objectForKey:key1] setObject:[[receivedDataDict objectForKey:key1] objectForKey:key2] forKey:key2];
else
if (pathChooser == 1)
NSLog(@"MADE IT TO -ALREADY EXISTS-");
UIAlertView *alert1 = [[UIAlertView alloc]initWithTitle: [[NSString alloc] initWithFormat:@"Match %@ already exists in %@!", key2, key1]
message: @"Overwrite?"
delegate: self
cancelButtonTitle:@"Keep"
otherButtonTitles:@"Overwrite", @"Keep All", @"Overwrite All",nil];
[alert1 show];
else if (pathChooser == 3)
NSLog(@"Path 3");
[[dataDict objectForKey:key1] setObject:[[receivedDataDict objectForKey:key1] objectForKey:key2] forKey:key2];
[dataDict writeToFile:path atomically:YES];
NSLog(@"%@", dataDict);
receivedDataDict = nil;
// Buttons for UIAlertView...
-(void)alertView:(UIAlertView *)alert1 clickedButtonAtIndex:(NSInteger)buttonIndex
//Keep Current
if (buttonIndex == 0)
pathChooser = 1;
//Overwrite Current
else if (buttonIndex == 1)
[[dataDict objectForKey:key1] setObject:[[receivedDataDict objectForKey:key1] objectForKey:key2] forKey:key2];
//Keep All
else if (buttonIndex == 2)
pathChooser = 2;
//Overwrite All
else if (buttonIndex == 3)
pathChooser = 3;
当两个 NSDictionaries 之间存在多个相似的键/值对时,我遇到的问题会快速连续创建 UIAlertView 多次,这显然不是一件好事。有没有办法可以延迟 UIAlertView 的每次创建?还有比这更明显的解决方案吗?我尝试使用代码块,但代码块似乎没有读取“key1”和“key2”值,因为它们在 UIAlertView 中显示为“(null)”。我也在 [alert1 show] 之后的行中尝试过这种方法:
while ((!alert1.hidden) && (alert1.superview != nil))
[[NSRunLoop currentRunLoop] limitDateForMode:NSDefaultRunLoopMode];
但它似乎直到第二次创建 UIAlertView 之后才起作用。我得到的错误是:
-[UIKeyboardTaskQueue performTask:] 中的断言失败,/SourceCache/UIKit/UIKit-2903.23/Keyboard/UIKeyboardTaskQueue.m:388
由于未捕获的异常“NSInternalInconsistencyException”而终止应用程序,原因:“-[UIKeyboardTaskQueue performTask:] 只能从主线程调用。”
欢迎任何建议,我会尽力而为。我找不到许多与我有同样问题的人。
【问题讨论】:
我在寻找解决方案时发现了这个:***.com/questions/19005463/… 【参考方案1】:您总是可以在创建 UIAlertView 时执行“dispatch_async”。
所以,它最终看起来像:
__block UIAlertView *alert1 = [[UIAlertView alloc]initWithTitle:[[NSString alloc] initWithFormat:@"Match %@ already exists in %@!", key2, key1]
message:@"Overwrite?"
delegate:weakSelf
cancelButtonTitle:@"Keep"
otherButtonTitles:@"Overwrite", @"Keep All", @"Overwrite All",nil];
dispatch_async(dispatch_get_main_queue(), ^(void)
[alert1 show];
);
【讨论】:
好的,到目前为止有效。没有错误了,非常感谢!但是,我将如何确保代码在用户响应之前不会超过 UIAlertView 块? (以便“覆盖所有”和“保留所有”选项生效并停止下一个警报视图)以上是关于快速连续多次创建 UIAlertView的主要内容,如果未能解决你的问题,请参考以下文章
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