如何实现面料数字找朋友？

Posted 2023-03-06

【中文标题】如何实现面料数字找朋友？

【英文标题】：How to implement find friends with fabric digits?

【发布时间】：2016-12-20 17:35:08

【问题描述】：

如何实现织物数字找朋友？

我已成功实施手机号码验证，但我无法上传联系人并获取匹配的联系人..每次我都遇到同样的错误

错误：超出速率限制

下面是实现

registerReceiver(new MyResultReceiver() 
        @Override
        public void onReceive(Context context, Intent intent) 
            super.onReceive(context, intent);
            if (ContactsUploadService.UPLOAD_COMPLETE.equals(intent.getAction())) 
                ContactsUploadResult result = intent.getParcelableExtra(ContactsUploadService.UPLOAD_COMPLETE_EXTRA);
                Log.e("upload", result.totalCount + "  " + result.successCount);
            
        
    , new IntentFilter("com.digits.sdk.android.UPLOAD_COMPLETE"));
    sharedPreferences = getSharedPreferences(MyPREFERENCES, Context.MODE_PRIVATE);
    Ref = FirebaseDatabase.getInstance().getReference().child("Users");


    DigitsAuthButton digitsButton = (DigitsAuthButton) findViewById(R.id.auth_button);
    digitsButton.setCallback(new AuthCallback() 
        @Override
        public void success(DigitsSession session, String phoneNumber) 
            // TODO: associate the session userID with your user model
            phone = session.getPhoneNumber();
            digitsId = String.valueOf(session.getId());
            Toast.makeText(getApplicationContext(), "Authentication successful for "
                    + phoneNumber, Toast.LENGTH_LONG).show();
            Log.e("number", "Mobile Number:  " + phoneNumber);
            Log.e("digit", "DigitsID  " + session.getAuthToken() + "  " + session.getId());
            // Digits.getInstance().getActiveSession();
            sendDigitANdNumber(String.valueOf(session.getId()), phoneNumber);
            // startService(new Intent(PhoneVerification.this, MyResultReceiver.class));

            startActivity(new Intent(PhoneVerification.this, RecentsTab.class));
            finish();


        

        @Override
        public void failure(DigitsException exception) 
            Log.d("Digits", "Sign in with Digits failure", exception);
        
    );

收货人

public class MyResultReceiver extends BroadcastReceiver 
    @Override
    public void onReceive(Context context, Intent intent) 
        if (ContactsUploadService.UPLOAD_COMPLETE.equals(intent.getAction())) 
            ContactsUploadResult result = intent.getParcelableExtra(ContactsUploadService.UPLOAD_COMPLETE_EXTRA);

        
    

联系人类

find.setOnClickListener(new View.OnClickListener() 
            @Override
            public void onClick(View view) 
                ContactMatch();
            
        );

     private void ContactMatch() 
        Digits.uploadContacts();
        progressDialog.show();

        Digits.findFriends(new ContactsCallback<Contacts>() 

            @Override
            public void success(Result<Contacts> result) 
                if (result.data.users != null) 
                    // Process data
                    progressDialog.dismiss();
                    linearLayout.setVisibility(View.GONE);
                    Log.e("data", result.toString());
                
            

            @Override
            public void failure(TwitterException exception) 
                progressDialog.dismiss();
                // Show error
            
        );
    

【参考方案1】：

Twitter 会限制您在特定时间范围内向其 API 发出的请求数量。所以你达到了这个极限。如果抛出速率限制异常，您需要修改逻辑以限制您的请求或等待一段时间。

他们的docs page关于速率限制非常彻底，所以我建议检查一下。